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Scattering by identical particles, Bragg scattering.
Typology: Slides
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Scattering theory is important as it underpins one of the most ubiquitous
tools in physics.
Almost everything we know about nuclear and atomic physics has
been discovered by scattering experiments,
e.g. Rutherford’s discovery of the nucleus, the discovery of
sub-atomic particles (such as quarks), etc.
In low energy physics, scattering phenomena provide the standard
tool to explore solid state systems,
e.g. neutron, electron, x-ray scattering, etc.
As a general topic, it therefore remains central to any advanced
course on quantum mechanics.
In these two lectures, we will focus on the general methodology
leaving applications to subsequent courses.
In an idealized scattering experiment, a sharp beam of particles (A)
of definite momentum k are scattered from a localized target (B).
As a result of collision, several outcomes are possible:
A + B elastic
∗
inelastic
C absorption
In high energy and nuclear physics, we are usually interested in deep
inelastic processes.
To keep our discussion simple, we will focus on elastic processes in
which both the energy and particle number are conserved –
although many of the concepts that we will develop are general.
Both classical and quantum mechanical scattering phenomena are
characterized by the scattering cross section, σ.
Consider a collision experiment in which a detector measures the
number of particles per unit time, N dΩ, scattered into an element
of solid angle dΩ in direction (θ, φ).
This number is proportional to the incident flux of particles, j I
defined as the number of particles per unit time crossing a unit area
normal to direction of incidence.
Collisions are characterised by the differential cross section defined
as the ratio of the number of particles scattered into direction (θ, φ)
per unit time per unit solid angle, divided by incident flux,
dσ
dΩ
j I
In classical mechanics, for a central
potential, V (r ), the angle of scattering is
determined by impact parameter b(θ).
The number of particles scattered per unit
time between θ and θ + dθ is equal to the
number incident particles per unit time
between b and b + db.
Therefore, for incident flux j I , the number
of particles scattered into the solid angle
dΩ =2 π sin θ dθ per unit time is given by
N dΩ =2 π sin θ dθ N = 2πb db j I
i.e.
dσ(θ)
dΩ
j I
b
sin θ
db
dθ
dσ(θ)
dΩ
b
sin θ
db
dθ
For elastic scattering from a hard (impenetrable) sphere,
b(θ) = R sin α = R sin
π − θ
= −R cos(θ/2)
As a result, we find that
db
dθ
R
2
sin(θ/2) and
dσ(θ)
dΩ
2
As expected, total scattering cross section is just
dΩ
dσ
dΩ
= πR
2 ,
the projected area of the sphere.
Simplest scattering experiment: plane wave impinging on localized
potential, V (r), e.g. electron striking atom, or α particle a nucleus.
Basic set-up: flux of particles, all at the same energy, scattered from
target and collected by detectors which measure angles of deflection.
In principle, if all incoming particles represented by wavepackets, the
task is to solve time-dependent Schr¨odinger equation,
iℏ ∂ t Ψ(r, t) =
2
2 m
2
Ψ(r, t)
and find probability amplitudes for outgoing waves.
However, if beam is “switched on” for times long as compared with
“encounter-time”, steady-state conditions apply.
If wavepacket has well-defined energy (and hence momentum), may
consider it a plane wave: Ψ(r, t) = ψ(r)e
−iEt/ℏ .
Therefore, seek solutions of time-independent Schr¨odinger equation,
E ψ(r) =
2
2 m
2
ψ(r)
subject to boundary conditions that incoming component of
wavefunction is a plane wave, e
ik·r (cf. 1d scattering problems).
E = (ℏk)
2 / 2 m is energy of incoming particles while flux given by,
j = −i
2 m
(ψ
∗ ∇ψ − ψ∇ψ
∗ ) =
ℏk
m
In higher dimension, phenomenology is similar – consider plane wave
incident on localized target:
Outside localized target region, wavefunction involves superposition
of incident plane wave and scattered (spherical wave)
ik·r
e
ikr
If we define z-axis by k vector, plane wave can be decomposed into
superposition of incoming and outgoing spherical wave:
If V (r ) isotropic, short-ranged (faster than 1/r ), and elastic
(particle/energy conserving), scattering wavefunction given by,
e
ik·r = ψ(r) %
i
∞ ∑
i
$ (2) + 1)
e
−i(kr −$π/2)
$ (k)
e
i(kr −$π/2)
$ (cos θ)
ψ(r) % e
ik·r
e
ikr
r
Particle flux associated with ψ(r) obtained from current operator,
j = −i
m
(ψ
∗ ∇ψ + ψ∇ψ
∗ ) = −i
m
Re[ψ
∗ ∇ψ]
= −i
m
Re
e
ik·r
e
ikr
r
∗
e
ik·r
e
ikr
r
Neglecting rapidly fluctuation contributions (which average to zero)
j =
ℏk
m
ℏk
m
ˆe r
|f (θ)|
2
r
2
3 )
j =
ℏk
m
ℏk
m
ˆe r
|f (θ)|
2
r
2
3 )
(Away from direction of incident beam, ˆe k
) the flux of particles
crossing area, dA = r
2 dΩ, that subtends solid angle dΩ at the
origin (i.e. the target) given by
NdΩ = j · ˆe r dA =
ℏk
m
|f (θ)|
2
r
2
r
2 dΩ + O(1/r )
By equating this flux with the incoming flux j I × dσ, where j I
ℏk
m
we obtain the differential cross section,
dσ =
NdΩ
j I
j · ˆe r dA
j I
= |f (θ)|
2 dΩ, i.e.
dσ
dΩ
= |f (θ)|
2
σ tot = 4π
$
(2) + 1)|f $ (k)|
2 , f (θ) =
∞ ∑
$=
(2) + 1)f $ (k)P $ (cos θ)
Making use of the relation f $ (k) =
2 ik
(e
2 iδ!(k) − 1) =
e
iδ!(k)
k
sin δ $
σ tot
4 π
k
2
∞ ∑
$=
(2) + 1) sin
2 δ $ (k)
Since P $ (1) = 1, f (0) =
$
(2) + 1)f $ (k) =
$
e
iδ !
(k)
k
sin δ $
Im f (0) =
k
4 π
σ tot
One may show that this “sum rule”, known as optical theorem,
encapsulates particle conservation.
ψ(r) = e
ik·r
e
ikr
r
The quantum scattering of particles from a localized target is fully
characterised by the differential cross section,
dσ
dΩ
= |f (θ)|
2
The scattering amplitude, f (θ), which depends on the energy
k , can be separated into a set of partial wave amplitudes,
f (θ) =
∞ ∑
$=
(2) + 1)f $ (k)P $ (cos θ)
where partial amplitudes, f $ (k) =
e
iδ !
k
sin δ $ defined by scattering
phase shifts δ $ (k). But how are phase shifts determined?