MAT 242 Fall, 2007 Assignment Solutions by Dr. Ibrahim, Assignments of Linear Algebra

The solutions to assignment c of mat 242, a linear algebra course taught by dr. Ibrahim during the fall, 2007 semester. The solutions cover various subtopics such as identifying subspaces, linear independence, and finding bases for row, column, and null spaces.

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MAT 242 Dr. Ibrahim
SLN: 80071 & 80072 Fall, 2007
MAT 242 Assignment C
C1: Which of the following subsets of IR2are subspaces. Briefly justify your answer.
a) [x, y] satisfying x= 2y;
hAnswer: Yes, this is a vector subspace. It’s a line through the origin in IR2, in the
direction of the vector (2,1)T.i
b) [x, y] satisfying x= 2yand y= 2x;
hAnswer: This is a vector subspace of IR2consisting of the (0,0) vector only.i
c) [x, y] satisfying x= 2y+ 1;
hAnswer: Not a vector space, because it is not closed under multiplication: 2(2,1) =
(4,2).i
d) [x, y] satisfying xy = 0;
hAnswer: Not a vector space, because it is not closed under addition: (1,0) + (0,1) =
(1,1).i
e) [x, y] satisfying x0 and y0.
hAnswer: Not a vector space, because it is not closed under multiplication: (2,1) =
(2,1).i
C2: For which real numbers λare the following vectors linearly independent in IR3?
X1=
λ
1
1
, X2=
1
λ
1
, X3=
1
1
λ
.
hAnswer: The three vectors are linearly dependent only if λ=1 or λ= 2.i
C3: Compute the reduced row echelon form Rof the follwoing matrix Aand find bases for
its row, column and null spaces of A.
A=
1 1 2 0 1 3
2 1 4 0 3 2
0 0 0 1 3 0
3 0 2 4 3 2
.
pf2

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MAT 242 Dr. Ibrahim SLN: 80071 & 80072 Fall, 2007

MAT 242 Assignment C

C1: Which of the following subsets of IR^2 are subspaces. Briefly justify your answer.

a) [[x, y] satisfying x = 2y; Answer: Yes, this is a vector subspace. It’s a line through the origin in IR^2 , in the direction of the vector (2, 1)T^.

]

b) [[x, y] satisfying x = 2y and y = 2x; Answer: This is a vector subspace of IR^2 consisting of the (0, 0) vector only.

]

c) [[x, y] satisfying x = 2y + 1; Answer: Not a vector space, because it is not closed under multiplication: 2(2, 1) = (4, 2).

]

d) [[x, y] satisfying xy = 0; Answer: Not a vector space, because it is not closed under addition: (1, 0) + (0, 1) = (1, 1).

]

e) [[x, y] satisfying x ≥ 0 and y ≥ 0. Answer: Not a vector space, because it is not closed under multiplication: −(2, 1) = (− 2 , −1).

]

C2: For which real numbers λ are the following vectors linearly independent in IR^3?

X 1 =

  

λ − 1 − 1

   ,^ X 2 =

  

λ − 1

   ,^ X 3 =

  

λ

  .

[ Answer: The three vectors are linearly dependent only if λ = −1 or λ = 2.

]

C3: Compute the reduced row echelon form R of the follwoing matrix A and find bases for its row, column and null spaces of A.

A =

   

   

[ Answer:

R =

   

1 0 0 0 −^11232

0 0 1 0 154 −^54

   

A basis for Row(A) is given by the four rows of A (or R). A basis for C(A) is given by the first four columns of A.

A basis for N(A) is given by the two vectors

     

     

and

     

     

]

C4: Let A =

( a b c 1 1 1

) .

Find conditions on a, b, and c such that:

a) rank[ A=1. Answer: a = b = c.

]

b) rank[ A=2. Answer: at least two of a, b and c are distinct.

]

C5: Find a basis for the subspace S of IR^3 defined by the equation

x + 2y + 3z = 0. [

Answer:

 

  ,

 

 ]

Verify that Y 1 =

 

  belongs to S and find a basis for S which contains Y

[

Answer: Let Y 2 =

  

  . Then^ Y 1 , Y 2 is another basis of^ S.

]