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Solutions to various chemistry problems, including the determination of the solubility of potassium dichromate at different temperatures and the expression of ddt concentration as mass percent. It also covers the preparation of silver nitrate solution and the calculation of the volume of sodium acetate solution required to provide a certain mass. Additionally, it includes the calculation of the molar concentration and molality of solutions, as well as the amount of chloride in aluminum chloride solution and the volume of kbr solution needed to prepare a certain volume of a different molarity solution.
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0 2 0 4 0 6 0 8 0 1 0 0
0
1 0
2 0
3 0
4 0
5 0
6 0
7 0
T e m p e r a t u r e • C
g
K 2 C r 2 O 7
/
1 0 0 g
H 2 O
Solubility curve for potassium dichromate
Using the above solubility curve answer the following questions:
a] What is the solubility of K 2 Cr 2 O7 at 55 o^ C? approximately __ 36 _g/100 ml b] What is the maximum number grams of K 2 Cr 2 O7 that will dissolve in 35 grams of water at 30 o^ C? 35g
H 2 O X
14g K 2 CrO (^7) 100g H 2 O = 4.9 g^ approximately^ ___4.9 g____ c] If K 2 Cr 2 O7 does not supersaturate, tell how many grams will precipitate out per 100 g of solvent when a solution containing 30 g per 100 g of water at 60 o^ C is cooled to 20o^ C (30-8)g = 22g d] For each of the following, indicate what kind of solution exists....... (a) saturated, (b) unsaturated
2] A 0.200 g sample of tissue from a dead bald eagle is found to contain 2.42 μg of DDT. Express this DDT
concentration as mass percent.
2.42 x 10-6g 0.200g sample (100)^ = 1.21 x 10
3] How would you prepare 250.0 g of a 1.00% by mass of a silver nitrate solution?
250.0g soln X
1.00g AgNO (^3) 100g soln = 2.50 g AgNO^3
Answer: Mix ___2.50___g of silver nitrate with ___247.5__g of water 4] How many milliters of solution are required to provide 4.00 g sodium acetate from a 2.00 M sodium acetate solution?
4.00g Na 2 C 2 H 3 O 2 X
1mol Na 2 C 2 H 3 O (^2)
1L soln 2.00mol Na 2 C 2 H 3 O 2 X^
1ml 10 -3^ L
= 24.4ml soln
5] After 25 ml of 0.50 M sulfuric is added to 0.075 liters of water, what is the molar concentration of the resulting solution? [Assume the volumes are additive]
Vf = 25 ml + 75 ml = 100 ml
25ml X 0.50M 100ml = 0.13M
6] What is the molality of a solution made by dissolving 20.0 g of sodium chloride in 225 g of water?
20.0g NaCl X
1mol NaCl 58.5g = 0.342 mol
225g H 2 O X
1Kg H 2 O 103 g H 2 O
= 0.225 Kg
m =
0.342mol NaCl 0.225Kg H 2 O = 1.52 m
7] How many grams of chloride are contained in 25 ml of a 2.37 M aluminum chloride solution?
25 ml soln X
2.37moles AlCl (^3) 1000ml X^
3mol Cl 1mol AlCl 3 X^
35.5g Cl 1mol = 6.3 g Cl
8] How many milliters of 3.5 M KBr is needed to prepare 355 ml of 0.50 M solution?
355ml x 0.50M 3.5M = 51 ml
9] 14 grams of methanol, CH3OH, are dissolved in 100.0 g of water a) Find the molality of the solution.
14g CH 3 OH X
1molCH 3 OH 32.0g = 0.44 mol CH^3 OH
100.0g H 2 O X 1Kg 103 g = 0.1000 Kg H 2 O
m =
0.44mol CH 3 OH 0.1000Kg H 2 O = 4.4 m
b) Find the percent alcohol by mass in this solution.
g soln = 14g CH 3 OH + 100g H 2 O = 114 g soln
% mass =
14g CH 3 OH 114g soln (100)^ = 12.3 %