Solutions for Assignment 5 | Analog Electronics | ECE 3050, Assignments of Electrical and Electronics Engineering

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ECE 3050 — Spring 2003 Page | lomewor! i: : ‘ion: 1.) Find the de operating point, the small signal voltage gain, Vour/Vin. the small signal input resistance, Rin, and the small signal output resistance, Roy, if K = 0.1mA/V2, V; = - iV, and’ =0.01V"!, W99FEP6 Solution Finding the de Thevenin equivalent circuit looking out the gate gives Vg = 7.5V and Re =0.5MQ. Assuming saturation gives Ip = KVog VP. Combining with Vog =75V = Ves +IpRy gives 7.5 = Vogt 5kQ.0.1MASV4( Vee I)? = Vigg + 0.5V eae? - Ves +05 which reduces to Vos =l14 + Ves= ¥14 =3.74V This gives 7, = 0.1mA(3.75-1)2 = 0.752mA. Finally, Vpg= 15 - Ip{RptRy) = 7.48V Vg = 3-74V, Tp = 0.752mA and Vep= 148 Note that the MOSFET is indeed saturated. The small signal mode] parameters are g,, = 24) KI ID 2N0.1-0.752 = 0.548mA/V and P52 (Al py! = 100/0.752 = 133kQ. The small-signal model for this problem is, Rin G Rout Vout T= Bn (MgelRyllR,) = -0.548(1 331151110) i =-1.782V/V, Rj, = S00kR and Roy = Folly, = 3.25kQ2. Rig = 5OOKQ, Roy = 3.25KQ. and Vout v; ~ = ~-1.782 V/V in 2.) Problem 13.91 of the text. 3.) Problem 13.100 of the text. [A, = -4.60 V/V] 4.) Problem 13.108 of the text.