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Solutions to exercises on gravimetric analysis, focusing on the concepts of equilibrium constants, solubility calculations, and the relationship between ksp and the solubility of salts. It covers topics such as the meaning of reaction quotients, the calculation of equilibrium constants for various reactions, and the determination of solubility using ksp values.
Typology: Exams
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b) At equilibrium K 3 = [AgCl(aq)], so [AgCl(aq)] = 3.6 x 10-7^ M.
init 0 0.
equil x 0.050 + 3x
where x equals the increase in the [La 3+] as a result of the dissolving process.
at equil, Ksp = 1.0 x 10-11^ = [La3+][lO 3 -^ ] 3 = (x)(0.050 + 3x)^3 • (x)(0.050)^3
assumes 3x << 0.
(assumption valid)
Ksp = 3 x 10-29^ = [Ce3+] 2 [C 2 O 4 2-^ ] 3 = (0.00010) 2 [C 2 O 4 2-^ ] 3
To see if this oxalate concentration will precipitate 0.010 M Ca 2+, calculate Q for the dissolution of CaC 2 O 4 and compare to Ksp.
Q = [Ca2+][C 2 O 4 2-^ ] = (0.010)(1.4 x 10-7^ ) = 14. X 10-
Since Q < Ksp (=1.3 x 10 -8^ ) for CaC 2 O 4 , Ca2+^ will not precipitate.
‚ precipitate from dilute solution
‚ add precipitating agent slowly, with stirring
‚ precipitate from hot solutions
‚ adjust solvent to increase the precipitate solubility