Solutions I-Classical Physics-Exam Solution, Exams of Classical Physics

This course includes collaboration policy, collision, conservation law, drag force, mass calculation, multiple stage rocket, estimates and uncertainties, Newton laws, potential energy, torque, friction, gravitational force, masses and rod, orbital velocity. This solved exam includes: Solutions, Force, Block, Moving, Speed, Spring, Work, Component, Resistive, Viscous, Acceleration, Gravitational

Typology: Exams

2011/2012

Uploaded on 08/12/2012

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Problem
1
42
points
6
pts
a)
max.
extension:
mg
sin
+
s
mg
cos
=
kx
max
)
x
max
=
mg
(sin
+
s
cos
)
k
N=mg cos θ
θ
mg
F =kx
sp
F = µsmg cos
fr
6
pts
b)
10
pts
c)
net
force
along
slope
once
the
block
starts
moving:
kx
;
mg
sin
;
k
mg
cos
=
ma
max
speed
when
a
= 0
)
x
=
mg
(sin
+
k
cos
)
k
10
pts
d)
gravity:
;
mg
sin
(
x
max
;
x
)
1
2
spring:
+
2
k
(
x
max
;
x
2
)
fricion:
;
k
mg
cos
(
x
max
;
x
)
10
pts
e)
Substitute
in
the
results
of
d)
for
x
=
0
.
Add
up
the
total
work
done
by
the
three
forces.
If
this
is
zero
or
larger
than
zero,
the
spring
will
become
as
short
as
l
.
Thus,
1
kx
2
mgx
max
(sin
+
k
cos
)
.
2
max
1
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Problem  p oints

pts a max extension mg sin s mg cos k xmax

xmax  mgk^ sin  s cos 

N=mg cos θ

mg

F =kx

sp

F = μ smg cos

fr

pts b

 pts c net force along slop e once the blo ck starts moving k x ; mg sin ; k mg cos ma

max sp eed when a 

x  mgk^ sin  k cos 

 pts d gravity mg sin xmax  x

spring  ^ 

 k^ xmax^ ^ x

fricion k mg cos xmax  x

 pts e Substitute in the results of d for x   Add up the total work done by the three

forces If this is zero or larger than zero the spring will b ecome as short as l  Thus

k x  mg x

 max max^ sin^ ^ ^ k^ cos^ ^ 

Problem   p oints

pts a As the ob ject go es up the comp onent of the resistive force in the vertical y direction

is in the same direction as the gravitational force mg see gure 

res,y

F

mg mg

F

res,y

When the ob ject is on the way down the y comp onent of the resistive force is in the

opp osite direction Thus the comp onent of th e force i n th e y direction is smaller on the

way d own than on the way u p Thus it will take longer than  sec to come down

pts b For zero acceleration T 

q

l (^)  For an acceleration a downwards T 0 

q

g g ;a If a were  msec^ wed have free fall and the p endulum would b e weightless no

oscillations T! 1  Since a  msec ^ T 0  T

p

pts c The viscous term will dominate when v^ C^1 term �^ vcrit where^ vcrit (^) C 2 r ^ When^ the^ viscous term dominates v^ mg term (^) C 1 r ^ The^ mass^ of^ the^ oil^ drop^ is^ given^ by^ m^

 (^)  r  (^)  Thus   r 3 g (^) � C (^1)  C 1 r C 2 r

C  3

r 

 g C

pts d   T ^ ^ f (^) T ^ Hz

 pts e The sp eed is maximum when x  ie when sint ^ 

This happ ens when t ^ n where n  � � �    

t   n   

 and^ the^ max^ sp^ eed^ is^ when^ cos^ t^ Alternatively v ; cos t � This  leads to the same times

l