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This is the Exam of Mathematics which includes Vector Valued Function, Denote, Statements, Vector Equation, Equation, Plane Containing, Derivatives of Inverse, Notation, Derivatives etc. Key important points are: Solvability Condition, Integral Representation, Modified, Function Method, Solve, Free Space, Spherical Coordinates, Transformation, Problem, Triangle Bounded
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The University of British Columbia
Closed book exam. No notes or calculators allowed. Answer all 4 questions
u^00 + π^2 u = f (x), 0 < x < 1 u(0) = 0 , u(1) = 0,
determine the solvability condition on f (x). (b) Assuming this condition is satisfied, calculate the modified Green’s function, G(ξ; x). (c) Find an integral representation of the solution.
L[u] = ∇^2 u − k^2 u = f (x), −∞ < (x, y) < ∞, 0 < z < ∞, (1) u(x, y, z) = g(x, y), on the plane z = 0.
and give a representation of the solution in terms of G(ξ;x). b) Find the free-space Green’s function, F (ξ;x), where x = (x, y, z) for the problem (1).
Note that in spherical coordinates, F (r) can be represented as a singular solution of
∇^2 F − k^2 F = F 00 +
r
F 0 − k^2 F = 0,
and a transformation F (r) = r−^1 W (r) will be useful.
(c) Find the Green’s function, G(ξ;x) for the problem (1) in terms of F (r).
The region D is the triangle bounded by the lines, y = ±x/
3 and x = b > 0, and
uxx + uyy + 2 = 0 in D, (2) u = 0 on ∂D,
(a) Describe how you would find approximate solutions to (2) using both a Galerkin and a Rayleigh- Ritz method. (b) Describe how you would find an approximate one-term Kantorovich solution of the form U (x, y) = (y^2 − x^2 /3)V (x).
(a) Write down an expression for the Rayleigh Quotient for the general Sturm-Liouville problem:
(p(x)u^0 )^0 − q(x)u = −λr(x)u, 1 ≤ x ≤ 2 u(1) = u(2) = 0
(b) For α > 1 , solve
x−^1 (x^3 u^0 )^0 = −αu, 1 ≤ x ≤ 2 u(1) = u(2) = 0
You might want to expand it out to help solve it. Give a rough numerical estimate of α. You can take ln 2 ∼ 0 .7 and π^2 ∼ 10. (c) Obtain upper and lower bounds for λ 1 for the eigenvalue problem:
x−^1 ((x^3 + 1)u^0 )^0 = −λu, 1 ≤ x ≤ 2 u(1) = u(2) = 0
by using different methods.