Taylor Series and Approximations, Assignments of Calculus

Exercises and problems related to the taylor series, its approximation, and the alternating series for functions such as cos(x), sin(x), and ln(cos(x)). It includes problems involving the sum of series, approximations to a certain degree, and comparing the actual sum to the function value. The document also covers the taylor series for tan(x).

Typology: Assignments

Pre 2010

Uploaded on 09/02/2009

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Exercise 10.8
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Exercise 10.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

  

    

1

0

1

0

0

2 2

1

2

0

2 2

1

n

n 1

1

1

n

n

n

k 0

n

2

0

2 4 6

0

1

0

2

!

0

cos

Hence,ifnisapositiveinteger,itfollows that

.

1!

1

!

0

cos x

have that

Then,ifxisarealnumbersatisfying 0 x 1 andifnisapositiveinteger, we

.

1!

1

R

Thus

f , 1.

Observe that

.

1!

,

R

between 0 andx such that

Formulathat thereisarealnumberc(n,x),dependingonbothnand x,

Forapositiveintegernandanonzerorealnumber x,wehavefromTaylor' s

R.

and let

,

!

0

S x

Forapositiveintegernandeachrealnumber x, let

2!

1

6!

1

4!

1

2!

1

1 -

!

0

TheTaylorseriesforf(x)about x 0 is

Letf(x) cos(x).

29.Consider cosx.

x dx

k

f

x dx

x

n

x

k

f

x

n

x

cn x

x

n

f cn x

x

x f x S x

x

k

f

j

x

x x x

x

n

f

dx

n

k

k

k

n

n

k

k

k

n

n

n

n

k

k

j

j

j

n

n

n

 

 

 

n 6 works.Thenourapproximation is

n 1! 2 3

beaccurateto 4 decimalplaces,choosenlargeenoughso that

cos x

to

Thus,inorder tohavetheapproximat ion

n 1! 2 3

n 1!

n 1!

cos x

cos x

1

0

5 9

1

0

4 8 12

1

0

2

1

0

0

2

1

0

2 3

2 2

1

0

1

0

0

2 2

1

0

0

2 2

x x x

x x x dx

n

dx

x dx

k

f

n

x

n

x dx

x dx

k

f

x dx

k

f

n

k

k

k

n

n

n

k

k

k

n

k

k

k

        

 

  

    

    

   

      

        

  

  

        

      

                 

 

  

          

 

 

 

6

5 5

2 4

5

2

cos 5 3 3

cos() 3 2 3

cos() 4 2 2 2

cos() 2 2 2

cos() 3

cos() 3

cos( )

cos() 2

cos() 2

cos() cos

cos( )

cos( 0 ) 1

15 sin cos 15 sin cos sin.

sin 10 sin ( )cos( ) 10 sin ( )

6 cos( )sin( ) sin( )

cos 4 sin cos 12 sin cos 6 sin 8 sin cos

sin sin ( ) 6 sin ( )cos( ) 4 sin ( ) 3 cos ( )

sin 3 sin cos 3 cos( ) 3 sin ( ) cos().

( ) sin sin ( ) 3 sin()cos( )

sin 3 sin cos sin.

2 sin cos sin

sin sin ( ) cos( )

sin cos.

sin sin cos

( ) ( sin( )).

x

f c

R x f x S x

x

e

x

e

S x e

f

x x x x x

e x x x x

x x x

x e x x x x x x x

f x e x x x x x x

f e

x e x x x x x

f x e x x x x

f

e x x x x

e x x x

f x e x x x

f e

e x x

f x e x x e x

f

f x e x

f e e e

vi

v

x

x

v x

iv

x

iv x

x

x

x

x

x x

x

          

        

  

S  x  1  ( ) ( ).

wehave that

So,letS(x)denotetheactualsumofthisseries.Foreachrealnumber xandeachpositiveinteger n,

However,wedonotknowfromthisthat thesumofthisseriesisactuallyf(x) e.

Assumingthispatterncontinues,thisserieswillconvergeforall x.

a ( )

a ,

where

TheTaylorseriesforf(x)about x 0 appearstobeanalternating series

15 cos( ) 15 cos ( ) cos( )

45 sin ( )cos ( ) 75 sin ( )cos( ) 16 sin ( )

sin 15 sin ( )cos( ) 20 sin ( )

30 sin cos 15 cos 15 sin ( ) cos

10 sin ( ) 30 sin ( )cos( ) 15 cos ( )

5 sin ( )cos( ) 30 sin ( )cos ( )

10 sin ( ) 15 sin( )cos ( ) 15 sin( )cos( ) sin( )

sin sin 10 sin ( ) cos

wherecisbetween 0 and x.

1

0

cos(x)

6

3

4

2

2

0 1

n 0

2 4 6

6

3 2

2 2 2 2

cos() 6 4 4

2 2 2

4 2 3

cos() 4 2 2

3 2

cos() 5 3

a x a x

x

e

x

x

e

x a x

e

x ea x

a x

x

e

x

e

x

e

S x e

f e

x x x

x x x x x

e x x x x

x x x x x

x x x x

e x x x x

x x x x x x

f x e x x x x

n

n

k

k

k

n

n

iv

x

x

vi x

Problem 33(e)

Taylorseriesforf(x) lncos ( )about x 0 :

( 0 ) lncos ( 0 ) ln( 1 ) 0.

tan( )

Taylorseriesfor tan(x)about x 0 :

2 cos( )sin( ) 2 tan( ).

cos ( )

( ) lncos ( )

4

2 4 6 8

2

2

2 4 6 8

3 5 7

2

2

f

x x x x

x

f

xdx x x x x c

x x x x

x x x

x

f x

f x x

4

f  