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Solved Assignment for Statistics and Probability I | STAT 400, Assignments of Probability and Statistics

University of Illinois - Urbana-ChampaignProbability and Statistics
Prof. Yuguo Chen

Material Type: Assignment; Professor: Chen; Class: Statistics and Probability I; Subject: Statistics; University: University of Illinois - Urbana-Champaign; Term: Fall 2009;

Typology: Assignments

Pre 2010

Uploaded on 10/27/2009

gavinr
gavinr 🇺🇸

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1.5-2 (a) P(ANB) — P(A)P(B) — (0.3)(0.6) — 0.18; P(AUB) — P(A)+P(B)—P(AnB) = 0.3+0.6 —0.18 — 0.72. (b) P(ALB) = ae = a =0. © BOG. 1.6-4 Let event B denote an accident and let A, be the event that age of the driver is 16-25. Then (0.1)(0.05) (0.1)(0.05) £ (0.55)(0.02) + (0.20)(0.03) + (0.15) (0.01) “ =! Lost 50+ 110+ 60+60 28070 7 P(A |B) = 1.6-10 (a) P(AD) — (0.02)(0.92) + (0.98) (0.05) — 0.0184 + 0.0490 — 0.0674; 0.0490 0.0184 (b) P(N| AD) = 0.0674 = 0.727; P(A| AD) = 00674 = 0.273; : _ (0.98) (0.95) — 9310 . op) (c) P(N|ND)= (0.02)(0.08) + (0.95)(0.95) ~ 1649310 ~ 0.998; P(A | ND) = 0.002. 2.1-2 (a) 0.6, wl, Ji) = 4 0.3, v5, 0.1, w= 10, (b) fix) 0.6 05 0.4 0.3 0.2 0.1 1 2 3 4 5 6 7 8 9 10 Figure 2.1-2: A probability histogram