Solutions to Homework 4 in ISyE 6739 (Summer 2009) for Module 15, Assignments of Data Analysis & Statistical Methods

The solutions to homework 4 in the isye 6739 course during the summer 2009 semester, focusing on module 15. It includes the calculation of the probability density functions (p.d.f.) for random variables z, given the uniform distribution of x.

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Pre 2010

Uploaded on 08/05/2009

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ISyE 6739 Summer 2009
Homework #4 (Covers Module 15) Solutions
1. Suppose XUnif(1,3). Find the p.d.f. of Z=eX.
Hint: The c.d.f. of Zis
G(z) = Pr(Zz)
=Pr(eXz)
=Pr(X`n(z))
=Z`n(z)
1f(x)dx (if 1 `n(z)3)
= (`n(z)1)/2.
Now you can get the p.d.f.
g(z) = d
dz G(z) = (0 if z < e or z > e3
1
2zif eze3
2. Suppose Xhas p.d.f. f(x) = 2xex2,x0. Find the distribution of Z=X2.
Hint: The c.d.f. of Zis
G(z) = Pr(Zz)
=Pr(X2z)
=Pr(zXz)
=Pr(0 Xz) (since X0)
=Zz
02xex2dx
= 1 ez.
Thus, Zis Exp(1).
3. Computer Exercises Random Variate Generation (see original assignment)

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ISyE 6739 — Summer 2009

Homework #4 (Covers Module 15) — Solutions

  1. Suppose X ∼ Unif(1, 3). Find the p.d.f. of Z = e

X .

Hint: The c.d.f. of Z is

G(z) = Pr(Z ≤ z)

= Pr(e

X ≤ z)

= Pr(X ≤ `n(z))

∫ (^) `n(z)

1

f (x) dx (if 1 ≤ `n(z) ≤ 3)

= (`n(z) − 1)/ 2.

Now you can get the p.d.f.

g(z) =

d

dz

G(z) =

{ 0 if z < e or z > e^3 1 2 z if^ e^ ≤^ z^ ≤^ e

  1. Suppose X has p.d.f. f (x) = 2xe

−x^2 , x ≥ 0. Find the distribution of Z = X

2 .

Hint: The c.d.f. of Z is

G(z) = Pr(Z ≤ z)

= Pr(X

2 ≤ z)

= Pr(−

z ≤ X ≤

z)

= Pr(0 ≤ X ≤

z) (since X ≥ 0)

∫ √z

0

2 xe

−x^2 dx

= 1 − e

−z .

Thus, Z is Exp(1). ♦

  1. Computer Exercises — Random Variate Generation (see original assignment)