Electric Field of Uniformly Distributed Charge on a Sphere, Exercises of Electrical Engineering

How to calculate the electric field of a uniformly distributed charge on the surface of a sphere using the formula e = ze / (4πε0r^2), where ze is the magnitude of the total charge, r is the sphere radius, and ε0 is the permittivity of free space. The document also provides the numerical value of the electric field for a given charge and radius.

Typology: Exercises

2011/2012

Uploaded on 07/20/2012

apurva
apurva 🇮🇳

70 documents

1 / 1

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
7. Since the charge is uniformly distributed throughout a sphere, the electric field at the surface is exactly
the same as it would be if the charge were all at the center. That is, the magnitude of the field is
E=q
4πε0R2
where qis the magnitude of the total charge and Ris the sphere radius. The magnitude of the total
charge is Ze,so
E=Ze
4πε0R2=(8.99 ×109N·m2/C2)(94)(1.60 ×1019 C)
(6.64 ×1015 m)2=3.07 ×1021 N/C.
The field is normal to the surface and since the charge is positive, it points outward from the surface.
docsity.com

Partial preview of the text

Download Electric Field of Uniformly Distributed Charge on a Sphere and more Exercises Electrical Engineering in PDF only on Docsity!

  1. Since the charge is uniformly distributed throughout a sphere, the electric field at the surface is exactly the same as it would be if the charge were all at the center. That is, the magnitude of the field is

E =

q 4 πε 0 R^2

where q is the magnitude of the total charge and R is the sphere radius. The magnitude of the total charge is Ze, so

E =

Ze 4 πε 0 R^2

(8. 99 × 109 N · m^2 /C^2 )(94)(1. 60 × 10 −^19 C) (6. 64 × 10 −^15 m)^2

= 3. 07 × 1021 N/C.

The field is normal to the surface and since the charge is positive, it points outward from the surface.

docsity.com