CHM 234 Problem Set #4 - Organic Reactions & Functional Groups (Spring 2009) - Prof. Randa, Assignments of Organic Chemistry

A problem set from a university organic chemistry course (chm 234) in spring 2009. It includes various questions related to organic chemistry concepts such as increasing acidity, bond dissociation energy, rate of reaction, and functional group identification in ir and nmr spectra. Students are required to rank compounds, identify synthons and actual structures, classify reactions, and determine degrees of unsaturation.

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Pre 2010

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CHM 234 Spring 2009 Problem Set #4
1
Give an unambiguous name for the following compounds. Be sure
to use cis/trans, E/Z or R/S where appropriate.
OH
Cl
(3S)-chlorocyclohexan-(1R)-ol
NO2
OH
Br
2-bromo-5-nitrophenol 1,(4E)-heptadien-6-yne
3-(1-methylpropyl)-1-heptyne
OH
CO2H
2-hydroxybenzoic acid
Br
CO2H
Cl
2-bromo-4-chlorobenzoic acid
N-propyl-4-methyl-3-octanamine
N
H
2,5-dimethyl-(5E)-octenoic acid
CH2
CH3
CH3CH2
HCH2CH
CO2H
CH3
2,5-dimethylhexanedioic acid methyl-2-bromo-2-methylbutanoate
CH2C
Br
CH3
C
O
OCH3
CH3
methyl-5-cyanopentanoate
NC CH2CH2CH2CH2CO2CH3
methyl-2-bromo-2-methylbutanoate
CH2C
Br
CH3
C
O
OCH3
CH3
Ph
N
C
O
N,N-dimethyl-2-phenylpentanamide
N
Br
4-bromo-N-ethyl-N-methyl-1-pentananime
CH3CH
CO2H
CH2CH2CH
CO2H
CH3
a) b) c)
d) e) f)
g)
h)
i) j)
k) l)
m) n)
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Give an unambiguous name for the following compounds. Be sure to use cis/trans, E/Z or R/S where appropriate.

OH

Cl (3S)-chlorocyclohexan-(1R)-ol

NO (^2)

OH Br

2-bromo-5-nitrophenol 1,(4E)-heptadien-6-yne

3-(1-methylpropyl)-1-heptyne

OH

CO 2 H

2-hydroxybenzoic acid

Br

CO 2 H

Cl 2-bromo-4-chlorobenzoic acid

N-propyl-4-methyl-3-octanamine

N

H

2,5-dimethyl-(5E)-octenoic acid

CH 2

CH 3 CH 2 CH 3

H CH 2 CH CO 2 H

CH 3

2,5-dimethylhexanedioic acid (^) methyl-2-bromo-2-methylbutanoate

CH 2 C

Br

CH 3

C

O

OCH 3

CH 3

methyl-5-cyanopentanoate

NC CH 2 CH 2 CH 2 CH 2 CO 2 CH 3

methyl-2-bromo-2-methylbutanoate

CH 2 C

Br

CH 3

C

O

OCH 3

CH 3

Ph

N

C

O

N,N-dimethyl-2-phenylpentanamide

N

Br

4-bromo-N-ethyl-N-methyl-1-pentananime

CH 3 CH

CO 2 H CH 2 CH 2 CH

CO 2 H CH 3

a) b) c)

d) e)^ f)

g) h)

i)

j)

k) (^) l)

m) (^) n)

Page 1

Increasing acidity

a)

Rank the following in order of:

C A D B

––– –––

Increasing rate of reaction in a Diels-Alder reaction

b)

B

A B C

Increasing rate of reaction with an electrophile

c)

B A < C

A B C D

A C

A B^ C

Increasing rate of hydrolysis

d)

A C < B

NHCOCH 3 COCl CO 2 CH 3

A B C

withdrawing

strong

donating

strong

donating

weak donating

withdrawing

moderate donating

N

H

N

O

H

O

N

H

O

O

amide acid ester

chloride

OMe OMe MeO

weak donating

weak donating

weak donating strong

donating

strong donating

strong donating

weak donating withdrawing strong donating neither, by definition!

OH OH OH OH

H 3 C NC H 3 CO H

Page 2

Give the number of enolizable hydrogens for each compound.

O

H

O O^ OH

Rank in order of increasing rate of SN2 reaction with sodium azide, Na + –N 3

Ph O –––A^ <^ –––B < –––D

A

Rank in order of increasing basicity

N N

N

–––B^ <^ –––A^ < –––C^ < –––D

A B C D

H H

H

H 2 N

increasing resonance stabilization decreasing reactivity

not a reaction that we discussed in class, but azide is a nucleophile so will want to react with the carbonyl carbon, C=O, usual "rules" apply. Think about the C=O as a simple pi-system with substituents. The acid halide is most reactive, fastest, due to the -Cl withdrawing group, followed by the ketone with 2 weak donating groups, followed by the ester with a stronger -OR donating group, the slowest is the amide which has the strong -NR 2 donating group.

H H

H

H H

H

Guanidine is obtained from degradation of guanine. Explain why guanidine is a very strong base even though it is neutral.hint, the basic electrons are indicated with the arrow

C

H 2 N NH 2

N

H

guanidine

H A

C

H 2 N NH 2

N

H H

C

H 2 N NH 2

N

H H

C

H 2 N NH 2

N

H H

the protonated guanidine is highly resonance stabilized

O amide

Ph

B

O

Ph N

C

O

Ph Cl

D

O

–––D <

ester ketone^ acid chloride

strong D weak D V. strong D weak W

Page 4

Rank the following in order of increasing energy

E

E

B C

D F

B A F D C

Draw the HOMO's ( orbitals) for the following systems. Non-bonding electrons are not shown, work out their locations based on the provided formal charges and add them to the structures

N

O

N

N

H

H

N

When in a flat configuration, which of the following compounds are:

a) Aromatic? A F

b) Non-aromatic? B C D

E

c) Antiaromatic? E

A

A B

D F

C

O

H

O

N

H

H

H

the larger the number of bonding interactionsk, the lower in energy a pair

of electrons will be in any particular orbital

Page 5

The Fischer Esterification is not a good method for synthesis of an ester, but, you need to know the mechanism. Show where each proton goes to and comes from and show all important resonance structures

Give a complete arrow pushing mechanism for the following reaction. Show where each proton goes to and comes from and show all important resonance structures

H 3 C OH

C

O

+ CH 3 CH 2 OH

H 3 C OCH 2 CH 3

C

O

HCl (catalytic)

H 3 C OH

C

O

H

CH 3 CH 2 OH

C

OH

H 3 C OH

O +

CH 3 CH 2 H

C

OH

H 3 C OH

CH 3 CH 2 O

C

HOH

H 3 C OH

CH 3 CH 2 O

H 3 C C O

CH 3 CH 2 O

H OH 2

– OCH

3

+ H 2 O

O

Na+

CH 3 OH

OCH 3

H

O

O

O O

H OCH 3 O^ HO

H

O HO

O

heat

O

O HO

Cl H

Cl

Cl H

H 3 C OH

C

O

H

H 3 C C O

CH 3 CH 2 O+

H

OCH 3

Page 6

Draw the complete arrow pushing mechanism for the following addition reaction. Draw all resonance structures and show where all protons go to and come from.

O O

O

O O O O

O O

NaOH H 2 O

O

O

O O

H

H–OH

Draw the complete arrow pushing mechanism for the following reaction, as per instructions above

O O

NaOH H 2 O

H

O

OH

H–OH

H

  • OH

O

OH

Congratulations! If you completed the two mechanisms above, you just did a Robinson annulation (which is the first spontaneously followed by the second

OH

O O O

heat

OH

O O O

OH

Page 7

Give a curved arrow-pushing mechanism for the following reaction:

OH OH

HCl

OH 2

O H

H

O

Is this reaction exothermic? Why?

Draw a properly labelled reaction energy diagram for this reaction

Energy

Reaction Coordinate

OH

OH 2

OH

Yes, because the conjugation in the system increases

OH 2

H H

Cl–

Page 10

Give a curved arrow-pushing mechanism for the following reactions, you can use the +H +^ and –H+ notation

O

O

CN

Br

LiAlH 4

O

O CN

H Al H

H

H

O

O

CN

Br

Br

O

CH 3 NH 2

O

N

H

Br

O

N

H H

O

N

H

H

–H+

O

O

O

CH 3 NH 2

HO

H

N

CH 3

O O

O

O

O

N

CH 3

H

H

O

H

N

CH 3

O O

H

+H+ –H+

Page 11

a)

b)

c)

d)

e)

f)

1. Sia 2 BH/THF

H

2. – OH, H 2 O 2

CH 2 CHO

CO 2 H

1. SOCl 2

2. AlCl 3

O

NH

O

1. –^ OH, H 2 O, heat

2. H 3 O+^ (neutralize) HO^ NH^2

O

Br

1. Mg, THF

2. D 2 O

D

O

O 1. LiAlH

4

2. H 3 O+

OH

OH

H

O

NH 3 /H+

H 2 /Pd/C

H

NH 2

Cl

DCl

D

(±) (kinetic control conditions)

g)

Page 13

EtO OEt

O O

  1. NaOEt/EtOH O
    1. H 3 O +

O

OEt

O

  1. NaOEt/EtOH

O O

Br

NaCN CN

NC CN

heat

CN

CN

heat

Br 2

Br

Br

(thermodynamic control)

2. H 3 O +

OH

OH H

O

O

O

EtO O

O (^) EtOH HCl

HO

OEt

1 Equiv. HBr Br

(±)

CF 3

1. HONO

2. H 3 PO 2

CF 3

NH 2 H !!!

Page 14

O

H+

(CH 3 ) 2 NH

N

O

H+

(CH 3 )NH 2

N

CN

2. H 3 O +

  1. CH 3 MgBr

O

1. HBr, ROOR

2. NaCN

CN

N

O

H

1.LiAlH 4

2. H 3 O+

N

H

O

O O 1. 1 Equiv. PhMgBr

2. H 3 O+ O

OH O

Ph

OH OH (^) Cl Cl

O

O

O

O

O

O O 1. Excess LiAlH 4

2. H 3 O+

OH OH OH

NH 2

OH (^) Cl CH 3

O

1 Equiv.

NH

OH

O

H 3 C

H

O O

2. LiAlH 4

3. H 3 O +

1. 1 Equiv. NH 3 /H+^ cat.) H 2 N OH

Page 16

SOCl 2

Br 2 / FeBr

OH Cl

1. Hg(OAc) 2 , EtOH

2. NaBH 4

CH 3 CH 2 CH CH 2 CH 3 CH 2 CH CH 3

OCH 2 CH 3

2. H 3 O +

CH 3 C C MgBr

O

CH 3 C C

CH 3

OH

F 3 C F 3 C Br

O 1.H^ N /H^ N

2. LiAlH 4

3. H 3 O +

1. HBr/ROOR

2. NaCN

3.LiAlH 4

4. H 3 O +

NH 2

OH

1. PBr 3

2. NaN 3

3.LiAlH 4

4. H 3 O +^

NH 2

CF 3

NH 2

heat

NH 2

CF 3

1. HNO 3 /H 2 SO 4

F 3 C F 3 C OH

2. H 2 /Pd/C

3. HONO

4. H 3 O +

Page 17

a)

1. Hg(OAc) 2 /H 2 O

2. NaBH 4 H 2 /Pd/C

OHC

CHO

NH 3 /H+

NH 2

H 2 N

b)

O

HC C–

HO

H 3 O +

Na+

c)

Show how you would make the target molecules from the provided starting

structures. Show all intermediate structures, do not show any mechanisms

d)

Br CN CO 2 H COCl

C

O

NH 2

H 3 O +

NBS, h

Na+ –^ CN SOCl 2

NH 3

OH

HO PCC

OH

PCC

NBS/h

Br

K+ –^ O-t-Bu

1. Hg(OAc) 2 /H 2 O

2. NaBH 4

OH

O

O

OH

PCC

H 2 C-PPh 3 MCPBA

H 3 O +

PhMgBr

Page 19

H 3 O +

CO 2 H

C

HO

BrMgO

2 CH 3 MgBr

1. MeMgBr

2. H 3 O+

CH 2 OH

O

O

H

PCC

CN CN

CN

heat

O CN

1. BH 3 .THF

2. – OH, H 2 O 2

SOCl 2

O

Cl

HO

PCC

OH

PCC

retrosynthesis problems continued...

Page 20