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Solutions to problem 5 of statistics 776 homework. It includes finding the distribution of a linear combination of normal random variables, determining the value of a to make two random variables independent, and finding independent pairs from a random matrix and its transformations.
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Stat 776 HW
1 X 2
. Find P (X 1 < 0).
X 1 ∼ N (1. 5 , 12 ) P (X 1 < 0) = P (Z < − 1 .5) = 0. 0668
(b) Find a =
( (^) a 1 a 2
such that X 2 and X 2 −a′
1 X 3
are independent
−a 1 1 −a 2
−a 1 + 3 − 2 a 2 = 0 a =
( (^3) − 2 a 2 a 2
The solution is not unique, a =
for example is one solution.
(a) XA and X(I − A) are independent A′(I − A) = 0. So XA and X(I − A) are independent (b) XA and X(I − A)X′^ are independent (I − A)′^ = I − A and A′(I − A) = 0. So XA and X(I − A)X′^ are independent (c) XAX′^ and X(I − A) independent A′^ = A and (I − A)′A = 0. So XAX′^ and X(I − A) are independent (d) XAX′^ and X(I − A)X′^ are independent A′^ = A, (I −A)′^ = I −A and A(I −A) = 0. So XAX′^ and X(I −A)X′ are independent