Parametrization of the Intersection of Surfaces in Math 210 Quiz #3, Quizzes of Advanced Calculus

The solution to quiz #3, section 13.1-13.2 of math 210, where students are asked to find a parametrization of the intersection of the surfaces y2 − z2 = x − 2 and y2 + z2 = 9 using y = t as a parameter. The steps to solve the problem and the final parametrization of the intersection points.

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2011/2012

Uploaded on 05/18/2012

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Math 210
Quiz #3
Sec. 13.1-13.2 September 15, 2009
You must show all of your work to receive full credit. Please put a box around
the final answer.
Find a parametrization of the intersection of the surfaces
y2z2=x2 and y2+z2= 9
using y=tas a parameter.
Solving both surfaces for z2we find that
z2=y2x+ 2 and z2= 9 y2.
We set the equations equal to each other
y2x+ 2 = 9 y2
and solve for x
x= 2y27.
From y2+z2= 9 we can see that z=±p9y2.
Letting y=tbe the parameter, we find that surfaces intersect at
~r(t) =<2t27, t, ±9t2>, where 3t3.

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Math 210 Sec. 13.1-13.2Quiz #3 September 15, 2009

You must show all of your work to receive full credit. Please put a box around the final answer. Find a parametrization of the intersection of the surfaces y^2 − z^2 = x − 2 and y^2 + z^2 = 9 using y = t as a parameter.

Solving both surfaces for z^2 we find that z^2 = y^2 − x + 2 and z^2 = 9 − y^2. We set the equations equal to each other y^2 − x + 2 = 9 − y^2 and solve for x x = 2y^2 − 7. From y^2 + z^2 = 9 we can see that z = ±√ 9 − y^2. Letting y = t be the parameter, we find that surfaces intersect at ~r(t) =< 2 t^2 − 7 , t, ±√ 9 − t^2 >, where − 3 ≤ t ≤ 3.