Solving Application Problems - Intermediate Algebra - Homework Solutions, Exercises of Algebra

Its the important key points of Homework Solutions of Intermediate Algebra are:Solving Application Problems, Function Notation, Solving Word Problems, First Degree Equations and Inequalities, Expressions and Formulas

Typology: Exercises

2012/2013

Uploaded on 01/07/2013

sajid
sajid 🇮🇳

4.6

(7)

128 documents

1 / 4

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
Chapter 2.3
Steps
for Solving Application Problems:
1.
Read,
throw out nonsense numbers
2.
Assign
a
variable
(What is it
asking
for?)
3.
Write
an equation
4.
Solve
the equation
5.
Check,
does it make sense?
Math
233A
Chapter 2.3: Solving Application
Problems
Objectives:
Fixed
cost plus cost/percent per something
Finding
when
fixed
cost plus cost/percent
per something is equal to a different
fixed
cost plus cost/percent per something
Leaving
a tip
The sum of three items
Fixed
Costs
Plus
Additional
Costs
Ex:
My
cell
phone
plan
charges $5 for 200 text messages and then $.10 for each additional text. If I was
billed
$18.50 for
texting,
how many text messages did I use?
Let
Then
Equation:
+
constantcost
moneyspenton
additional
texts
total
text
cost
Answer: 135 = number of texts used after the
first
200
335 = number of
total
texts
You
try:
1. If
you
got
paid
a
flat
rate
of
$120
for the
first
8 hours on
a
job
and $18/hr for each
addifional
hour, how
many
hours did you
work
total
if
you
got
paid
$165
that
day?
Let
=
Then
Equation: + =
^
V ' ^ V ^ ^ V
constant
pa>'nient
pa>'menl
for additional
hours
total
payment
Answer: 2.5 = number of
hours
worked
after 8 hours
10.5 = total hours
worked
Docsity.com
pf3
pf4

Partial preview of the text

Download Solving Application Problems - Intermediate Algebra - Homework Solutions and more Exercises Algebra in PDF only on Docsity!

Chapter 2.

Steps for Solving Application Problems:

  1. Read, throw out nonsense numbers
  2. Assign a variable (What is it asking for?)
  3. Write an equation
  4. Solve the equation
  5. Check, does it make sense?

Math 233A

Chapter 2.3: Solving Application Problems

Objectives:

  • Fixed cost plus cost/percent per something
  • Finding when fixed cost plus cost/percent per something is equal to a different fixed cost plus cost/percent per something
  • Leaving a tip
  • The sum of three items Fixed Costs Plus Additional Costs

Ex: M y cell phone plan charges $5 for 200 text messages and then $.10 for each additional text. If I was billed $18.50 for texting, how many text messages did I use?

Let Then

Equation: (^) + constantcost moneyspenton additional texts total text cost

Answer: 135 = number of texts used after the first 200 335 = number of total texts You try:

  1. If you got paid a flat rate of $120 for the first 8 hours on a job and $18/hr for each addifional hour, how many hours did you work total if you got paid $165 that day?

Let = Then

Equation: + = ^ V ' ^ V ^ ^ V constant pa>'nient pa>'menl for additional hours total payment

Answer: 2.5 = number of hours worked after 8 hours 10.5 = total hours worked

Finding When a Fixed Cost Plus Additional Costs is Equal to a Different Fixed Cost Plus Additional Costs

Ex: Company A has a monthly cell phone plan that charges a flat rate of $49 and $.30 for each mmute used and Company B has a monthly cell phone plan that charges a flat rate of $89 and $. 10 for each minute used. How many minutes would you have to use for both plans to cost the same?

Let = Then = And =

Equation: = V V fixed cost+moneyspenton minutesused fixedcost+moneyspenlon minutesused

Answer: 200 = number of minutes used for both plans to cost the same

You try:

  1. Commission job A pays a fixed salary of $500 plus 2% of sales (money you make for the company) and commission job B a fixed salary of $1000 plus 1% of sales. How much in sales would you have to make for both jobs to pay the same salary? Let = Then = And = Equation: = fixed salary+salary made from sales fixed salary+salary made from sales

Answer: $50,000 = amount made in sales for both companies to pay the same salary

Sum of Three Items

Ex: A house for sale has 2 bedrooms with the same square footage, and a third bedroom that is 4 sq. ft. less than five times the area of the other two rooms. Together, all three rooms have a total of 556 sq. ft. How much area does each room have?

Let = Then = Equation:

+ _+ =

_\ \ ^ i _ 1 si room'sarea 2ndroom'sarea 3rd room'sarea tola) area

Answer: 80 sq. ft. = area of and room 396 sq. ft. = area of 3"^ room You try: \ Ruby, Hazel, and Violet went shopping and spent a total of $1250. If Ruby spent 4 times as much as Hazel, and Violet only spent $50 more than Hazel, how much did Ruby, Hazel, and Violet each spend?

Let = Then = And =.

Equation: +^ +^ =^ ^ ^/ V ^ SHazelspent SRubyspent SVioletspent totalSspent

Answer: $200 = money Hazel spent $800 = money Ruby spent $250 = money Violet spent