

Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
A performance task on solving optimization problems using calculus. The task involves finding two positive numbers whose sum is 20 if the product of the first number and the square of the second number is to be a maximum. important notes on how to approach the problem, including denoting the problem as x + y = 20 and maximizing x y2. It also explains the objective, the variable to be controlled, the function that accurately models the problem, and the critical points. The document concludes by providing the numbers that maximize the objective.
Typology: Exercises
1 / 2
This page cannot be seen from the preview
Don't miss anything!


Basic Calculus Performance Task 2
number and the square of the second number is to be a maximum.
Important Notes:
2
a. What is the objective? Let it be ๐(๐ฅ).
The objective is the product of the first number and the square of the
second number.
We are required to find the numbers that will maximize ๐.
b. What variable are you going to control? Let it be ๐ฅ.
Let
x be the second number. Let it be the control variable. Let
20 โ x be the
first number.
c. What function accurately models this problem?
Our model is
P ( x )=( 20 โ x ) x
2
= 20 x
2
โ x
3
. Let it be
continuous
d. What are the numbers?
Finding its critical points.
P ' ( x )=( 2 ) 20 x
2 โ 1
โ( 3 ) x
3 โ 1
= 40 x โ 3 x
2
40 x โ 3 x
2
= 0 โ x = 0 ,
Evalu ating P at 0,
x 0
P(x)
Min
Max
Min
To maximize ๐, the value of the second number should be
while the
value of the first number should be
Therefore, the first and second number are
and
, respectively.
e. What is the maximum product of the first number and the square of
the other?
The maximum product of the first number and the square of the second
number is
2
3
โจ1185. 185 Alternative Method:
Using x y
2
x y
2
2
2
3