Solving Radical Equations: A Comprehensive Guide with Examples and Practice Problems, Schemes and Mind Maps of Algebra

Solving equations requires isolation of the variable. Equations that contain a variable inside of a radical require algebraic manipulation of the equation ...

Typology: Schemes and Mind Maps

2021/2022

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Solving Radical Equations
 +
=
Solving equations requires isolation of the variable. Equations that contain a variable inside of a
radical require algebraic manipulation of the equation so that the variable “comes out” from underneath the
radical(s). This can be accomplished by raising both sides of the equation to the “nth” power, where n is the
“index” or “root” of the radical. When the index is a 2 (i.e. a square root), we call this method squaring both
sides.” Sometimes the equation may contain more than one radical expression, and it is possible that the
method may need to be used more than once to solve it.
When the index is an even number (n = 2, 4, etc.) this method can introduce extraneous solutions, so it
is necessary to verify that any answers obtained actually work. This can be accomplished by plugging the
answer(s) back in to the original equation to see if the resulting values satisfy the equation. It is also good
practice to check the solutions when there is an odd index to identify any algebra mistakes.
General Solution Steps:
Step 1. Isolate the Radical(s) and identify the index (n).
Step 2. Raise both sides of the equation to the “nth” power.
Step 3. Use algebraic techniques (i.e. factoring, combining like terms,…) to isolate the variable.
Repeat Steps 1 and 2 if necessary.
Step 4. Check answers. Eliminate any extraneous solutions from the final answer.
Examples:
a. = (Problem with 1 radical)
Step 1: Isolate the Radical 5 = 3 Step 4: Check Answers
Step 2: Square both Sides 5 
=3
5 −4 3 = 0
Step 3: Solve for “x”: 5 = 9 9 3 = 0
− = 4 3 3 = 0
= − 0 = 0
b.
+ = 0 (Problem with 2 radicals and no other “non-zero” terms)
Step 1: Isolate the radicals √
2 = + 4
Step 2: Square both Sides √
2
= + 4
Step 3: Solve for “x”:
2 = + 4
6 = 0
+ 2 3= 0
= −  =
Index
or
Root
Radicand
pf3

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Solving Radical Equations

Solving equations requires isolation of the variable. Equations that contain a variable inside of a radical require algebraic manipulation of the equation so that the variable “comes out” from underneath the radical(s). This can be accomplished by raising both sides of the equation to the “nth” power, where n is the “index” or “root” of the radical. When the index is a 2 (i.e. a square root), we call this method “squaring both sides.” Sometimes the equation may contain more than one radical expression, and it is possible that the method may need to be used more than once to solve it. When the index is an even number (n = 2, 4, etc.) this method can introduce extraneous solutions, so it is necessary to verify that any answers obtained actually work. This can be accomplished by plugging the answer(s) back in to the original equation to see if the resulting values satisfy the equation. It is also good practice to check the solutions when there is an odd index to identify any algebra mistakes.

General Solution Steps:

Step 1. Isolate the Radical(s) and identify the index (n). Step 2. Raise both sides of the equation to the “nth” power. Step 3. Use algebraic techniques (i.e. factoring, combining like terms,…) to isolate the variable. Repeat Steps 1 and 2 if necessary. Step 4. Check answers. Eliminate any extraneous solutions from the final answer.

Examples:

a. √➂ − ∆ − ➀ = ❷ (Problem with 1 radical)

Step 1: Isolate the Radical √5 − ᡶ = 3 Step 4: Check Answers

Step 2: Square both Sides 㐵√5 − ᡶ㐹

⡰ = 䙦3䙧⡰^ 㒓5 − 䙦−4䙧 − 3 = 0

Step 3: Solve for “x”: 5 − ᡶ = 9 (^) √9 − 3 = 0 −ᡶ = 4 3 − 3 = 0 ∆ = −➁ 0 = 0 

b. √∆❹^ − ❹ − √∆ + ➁ = 0 (Problem with 2 radicals and no other “non-zero” terms)

Step 1: Isolate the radicals √ᡶ⡰^ − 2 = √ᡶ + 4

Step 2: Square both Sides 㐵√ᡶ⡰^ − 2㐹

⡰ = 㐵√ᡶ + 4㐹

Step 3: Solve for “x”: ᡶ⡰^ − 2 = ᡶ + 4 ᡶ⡰^ − ᡶ − 6 = 0 䙦ᡶ + 2䙧䙦ᡶ − 3䙧 = 0 ∆ = −❹ Ↄ↖ↆ ∆ = ➀

Index or Root

Radicand

Step 4: Check Answers  㒓䙦−2䙧⡰^ − 2 − 㒓䙦−2䙧 + 4 = 0 㒓䙦3䙧⡰^ − 2 − 㒓䙦3䙧 + 4 = 0

√4 − 2^ − √2^ = 0^ √9 − 2^ − √7^ = 0 √2^ − √2^ = 0^ √7^ − √7^ = 0 0 = 0  0 = 0 

c. √∈ − ➃ − √∈ + ➆ + ➀ = ❷ (Problem with 2 radicals and another “non-zero” term)

Step 1: Isolate the radicals so that they are on opposite sides of the “ = ” sign

√ᡸ − 6^ + 3 = √ᡸ + 9

Step 2: Square both Sides 㐵√ᡸ − 6 + 3 㐹

⡰ = 㐵√ᡸ + 9㐹

Step 3: Solve for “x”. Because a radical still remains during this process, repeat Steps 1 and 2.

FOIL  䙦√ᡸ − 6 䙧 ∙ 䙦√ᡸ − 6䙧 + 3 √ᡸ − 6 + 3 √ᡸ − 6 + 䙦3䙧䙦3䙧 = ᡸ + 9

Combine like terms  䙦ᡸ − 6䙧 + 6√ᡸ − 6 + 9 = ᡸ + 9

ᡸ + 3 + 6√ᡸ − 6 = ᡸ + 9

Radical still remains  6√ᡸ − 6 = 6 Step 4: Check Answer

(Repeat Step 1) (^) √ᡸ − 6 = 1 (^) √7 − 6 − √7 + 9 + 3 = 0

(Repeat Step 2) 㐵√ᡸ − 6㐹

⡰ = 䙦1䙧⡰^ √1 − √16 + 3 = 0 ᡸ − 6 = 1 1 − 4 + 3 = 0 ∈ = ➄ 0 = 0 

d. ➁ + √∆ − ➃^ ➀^ = ❹ (Problem with an “nth” root)

Step 1: Isolate the radical (^) √ᡶ − 6^ ㄙ^ = −2 Step 4: Check Answer

Step 2: Raise both sides to the “nth” power (n = 3) 㒓䙦−2䙧 − 6^ ㄙ^ = −

㐵 √ᡶ − 6^ ㄙ^ 㐹

⡱ = 䙦−2䙧⡱^ √−8^ ㄙ^ = −

Step 3: Solve for “x”: ᡶ − 6 = −8 (^) 㒓䙦−2䙧䙦−2䙧䙦−2䙧ㄙ^ = −

∆ = −❹ −2 = −2 

This term will need to be “FOIL-ed”