Solving Right Triangles: Finding Unknown Side Lengths and Angles, Study notes of Pre-Calculus

Instructions on how to find all the unknown parts of a right triangle, given the measure of two sides or an acute angle and a side. It includes examples and formulas for calculating side lengths and angles using trigonometric functions such as sin, cos, and tan.

Typology: Study notes

Pre 2010

Uploaded on 09/17/2009

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§5-5 Solving Right Triangles
Solving right triangles: Find all unknown parts of a right triangle,
given the measure of two sides or the measure of one acute angle and a side.
a
b
c
α
β
Figure 1
Basic relations between the elements of the right triangle:
α+β= 90o, a2+b2=c2
Locate the right triangle in the first quadrant of a rectangular coordinate
system, we have following relations:
-
6
a
b
c
0o< β < 90o
(a, b)
β
α
sin β=b
c
cos β=a
c
tan β=b
a
csc β=c
b
sec β=c
a
cot β=a
b
Figure 2
Side bis often referred to as the side opposite angle β,aas the side
adjacent to angle β, and cas the hypotenuse. Using these designations
for an arbitrary right triangle, we have the relations (Figure 2).
Example Solve the right triangle with c= 6.25 feet with β= 32.2o
Solution. Solve for α:α= 90o
32.2o= 57.8o.
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§5-5 Solving Right Triangles

Solving right triangles: Find all unknown parts of a right triangle, given the measure of two sides or the measure of one acute angle and a side.

a

b

c

α

β

Figure 1

Basic relations between the elements of the right triangle: α + β = 90o, a^2 + b^2 = c^2

Locate the right triangle in the first quadrant of a rectangular coordinate system, we have following relations:

6

a

c b

0 o^ < β < 90 o

(a, b)

β

α

sin β = b c cos β = a c

tan β =

b a

csc β =

c b sec β = c a

cot β = a b

Figure 2

Side b is often referred to as the side opposite angle β, a as the side adjacent to angle β, and c as the hypotenuse. Using these designations for an arbitrary right triangle, we have the relations (Figure 2). Example Solve the right triangle with c = 6.25 feet with β = 32. 2 o

Solution. Solve for α: α = 90o^ − 32. 2 o^ = 57. 8 o. 1

2

sin β = OppHyp

cos β = (^) HypAdj

tan β = OppAdj

csc β = HypOpp

sec β = HypAdj

cot β = (^) OppAdj

β Adj

Hyp Opp

0 < β < 90 o

Figure 3

a

b

α

  1. 2 o

6 .25ft

Figure 4

Solve for b: sin β =

b c sin 32. 2 o^ = b

  1. 25 b = 6 .25 sin 32. 2 o = 3 .33feet Solve for a: cos β = ac

cos 32. 2 o^ =

a

  1. 25 a = 6 .25 cos 32. 2 o = 5 .29feet § Example Solve the right triangle with a = 4.32 centimeters and b = 2. 62 centimeters.