Solving Linear & Nonlinear Systems with Gaussian & Exponential Distributions, Slides of Stochastic Processes

An exact solution for linear and nonlinear systems of equations with gaussian and exponential distributions. It includes the determination of the number of times a level is crossed in an interval, the study of limit cycle oscillations, and the integration of terms by parts using taylor's expansion. The document also discusses the general formulation of the problem and the steady state pdf.

Typology: Slides

2012/2013

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Markov Vector Approach-3
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Download Solving Linear & Nonlinear Systems with Gaussian & Exponential Distributions and more Slides Stochastic Processes in PDF only on Docsity!

Markov Vector Approach-

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2

 ^

 ^

 ^

 ^

^ 

 ^

 ^

^

^

^ 

^ 

^ 

0

,^1

,^

;^ 0;

0

,^ ,

~^1 ,^

~ ~^

(^1) 0;^

2

,^ ;^

1, 2,^

,

2

; ,^

1, 2,^

, 1 2 i^

j^

ij

j^ j

t ij^

ij n

j n j j dX^ t^

f^ t X

t^ dt

G t X

t^ dB t

t^

X^

X

X^ t^

f^ t X

t^

n

G t X

t^

n^ m dB t^

m dB t^

B^ t^

B^ t^

D

f^ t x

j^

n

GDG

x

i j^

m

p^

p t^

x

 

 ^

 ^ 

^

^

^

^

^

^

^

^

^

^  ^

 ^

^  ^

   ^

^

^

^

 ^

 ^

^

 ^

^ ^

  ^

 ^  ^

^ 

 

Ge n e

r a l :

  • d i m^

e n s i o

n a l I t o SD^

E

^

^

^

0

0 1 ;0 |^

;^

BCS m^ m

jk j^ k^

j^ k

n

i^ i i

p x^ x

p x^

x^

x^ x

^  

^ 

  ^ 

^

^

   ^ 

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4

Further

questions

-^ How

to^ solve

the^

FPK^

equations?

-^ A^ few

selected

examples

for^ which

exact

solutions

are^ possible

-^ Can

we^

derive

equations

governing

the

moments?

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5

^

^

^

^

^

^  

Lagrange's method for solving linear PDE-s. Consider the PDE of the form,^

,^

,^ ,^

,^ ,^

1

To obtain an integral of the above equation we considerthe auxiliary equationLe

z^

z

P x y z

Q x y z

R x y z

x^

y

dx^

dy^

dz P^ Q^ ^ R

 ^

^

^

Recall :

^

^

^

t two independent solutions of this equation be written as,^ ,^ ^ 

&^

,^ ,^

where

and

are constants.

Then ,

0 is a solution of (1). Alternatively,

( ) is also a solution.

u x y z

a^

v x y z

b^

a^

b

u v

u^ f v  

  

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7

 ^

^ ^

^ 

 ^

 ^

 ^

^ 

^ 

0

0

1

1

1

1

1

1 ;^ 0;

0

;^0

~^

1;^ ~

;^

~^ 1

0;^

2 t

ij^ m m

I II I II II

II^

I

MX^

CX^

KX^

W^ t^

t^

X^

X^ X^

X

X^ t^

N^

n^ m^

W^ t^

m

W^ t^

W^ t W

t^

D

X^ M

CX^

M^ KX

M^

W^ t

Y^

X Y^ Y

X dY^

Y dt dY^

M^ CY

M

KY^

M^

dB t

dY^ t^

PYdt

 

^

^

^

^

^

^

 ^

^

^

^ 

  

^

^

 ^

^

^

^

^ ^

^  ^

 ^ ^

^  ^  ^    ^

^

^

  Example : Linear MDOF systems^ ^

^

^

^

 

 ^

^ ^

0

1

1

0;^01

0

0 QdB t t^ ;

Y^

Y

I

P^

Q

M^ K

M^

C^

M

^

^

 ^

^

 ^

^

^

^

^

^

^



^

^

^

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8

   

   ^

 

 ^

 ^

^ 

1

1

1

1

2 2

2

2 1

2 1

0

0;^

Consider the eigenvalue problemLet^

be the 2

matrix of

I^

I

II^

II^

m

N^ N^

N^ m

N^

N

dY^ t

Y^ t I^

dt^

dB t

dY^

t^

Y^ t

M^ K

M
C^
M

dY^ t

PYdt QdB t t

Y
Y
P
N^
N

^ 

^

^

^

^

^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
 ^
^
^
 ^
^

  

 

1

eigenvectors and

be the 2

diagonal matrix of complete set of

eigenvalues of

Introduce the transformation

N^
N P
P^
P

Y^ t^

Z t

^

^

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10

^ ^

^ 

^

^

2

2 1

1 1

1 2

2

(^02) 0

1 2

2

1

0

Define the conditional characteristic function

,^ ,^
,^ ; |
; |^

;0 exp ; |^

;0 exp N^

m^ m j^ j^

jk

j^

j^ k j^

j^ k

N

N j^

j^

N

j j j

p^

p

z p t^

z^

z^ z

M^

t^ Z^

z^

M^

t

p z t

z^

i^

z^ dz dz

dz

p z t

z^

i^

z

^ ^

  

^

^ 

^ ^

 ^

 ^

^
^
^
^
^
^
^ 
^
^
^
^

^

 ^

 ^
^

^   ^

^

2 1

2 0

1

;^
; |^

N j ;0 exp

N

k^

j^ j j

k

dz

M^

t^

z p z t

z^

i^

z^ dz

 





^
^
^
^
^
^
^
^
^
^ 

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11

^ 

^

^

^

^ 

^ 

^

^

^

(^2)   0

1

2

0

1 2 0

1

2

0

1

;^

; |^

;0 exp 1

; |^

;^

;^ exp 2 ;^

; |^

;0 exp

; 1 ; |^

;^

exp

2

N j^

j j

N j^

j j N

k^

j^ j j

k

N

k^

j^ j j

k

M^

t^

p z t

z^

i^

z^ dz

p z t

z^

M^

t^

i^

z^ d

M^

t^

iz p z t

z^

i^

z^ dz M^

t

z p z t

z^

i^

z^ d

i

^

^

^



 





^

^

^

 ^

 

^

^



 ^

^

^

^

^

^

^

^

^

^

^



^

^

^

^ 

 ^

^  

^ 

 ^

^ ^ ^

^

^ 

^

^

2

0

1

; 1 ; |^

;^

exp

2

N

k^

k^

j^ j j

k^

M^ t k

z p z t

z^

i^

i^

z^ d

z

^

^

^

^ 

^

^ ^

 ^

^



^

^

^

^

 

^

^ 

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13

 ^

^  2

2 1

1 1 2

2 2 1

(^1 )

1

2

2 2

1 1

2 2

2 2

(^1 )

1 2 1 2

1

1

2

;^ 1, 2,

, 2^

exp^

;^ 1, 2,

, 2

1

N^

m^ m j^ j^

jk

j^

j^ k j^

j^ k

N^

N^ N j^ j^

jk^ j^ k

j^

j^ k j

N

N^ N N^ N^

jk^ j^ k j^ k

i

i^

i^

i

i^ i p^

p

z p t^

z^

z^ z

M^

M^

M

t

d

d^

d dt^

dM

M

d dt^

i^

N^

t^

t^ i^

N

 

   

^

  ^

 

^ 

  

^

^

^  

^  ^

^ 

^ 

^

^

^

^

 ^

^

^

^ 

^

^

 ^

^

 ^

^

^ 

 

^

^

^

^

^

 ^





 ^

^  ^

   

^

(^0) i (^) diagonal matrix with entries exp

i

i

t

t

^

   ^

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14

^ ^

^ 

^ ^

^ ^

^

^   

2 2

2 2

1 1

1 1 2 2 1 1

2 2 1 1

Consider

&

1

1

2

(^212)

1 2 i^

l

N^ N^

N^ N

i^ i^

l^ l

jk^ j^ k^

jk^ j^ k

j^ k^

j^ k i^ l^

l^ i

i^ i^ l^

l^ i^ l^

l^ i^

i^ l^

N^ N

jk^ j^ k j^ k

l^ i^

l^ i N N

i^ l^

jk j^ k d^

d

dM^

dM

a^

b

M^

M dM

a^

b^

d^

d

M

d^

dM

 

 

  

   ^ ^

 

  ^

  ^

^ ^

^ ^

  

 

 

^ 

 ^ ^

^   

^   ^

 

^ ^

^ 

^ ^

^ 

^ ^

^  

^

^

^

  ^

   

  ^ ^  ^ ^ 

 



^

^

^  

2 2 1 1 Multiply both sides by

and sum over

and 2 1 2

j^ k il

N^ N

il

l^ i

i^ l^

i^ l

M

i^ l

dM^

d

M

   ^

  ^   ^ ^ 

 

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16

^

^ 

^

0

0 0

0 0

0

0 0

(^0 00 ) (^1) exp 0 0

exp 2 1 exp^

2 1

1

,^ exp

2

2

1 exp^

2 This is the characteristic function of a multivariateGaussian PDF.

t^

t

t^

t t t^

t^

t

t^

t^

t

M^

i^ z

M^

i^ z M^

t^

i^ z i^ z

^ 

^

^  

^

^

^ 

^

^

^

^ ^  ^

 ^

 ^

^

^  ^

 ^

 ^

^

^  

^

^

^

^

^

^

    ^

^

 ^  ^

^

^

^ 

^

  ^

 

The mean vector and covariance matrix can be evaluated fromthe charateristic function.The PDF in the original coordinate system can be obtainedby using the transformation

. Y^ t^

Z t  

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17

RemarksFor linear systems, the exact solution can also be obtained  using convolution integral approach discussed earlier in this course.The Markov vector approach does not offer any special advantage

 ^

^ ^

^ 

 ^

^ ^

^ 

 ^

 ^ 

^

^ 

 ^

 ^

 ^

2 2

0

0 0

0

here.The above formulation is also valid when excitations are modeled asfiltered white noise excitations.^2

;^ 0;

0

;^0

2

;^ 0;

0

;^0

0;^

2

x^

x^

x^ f^

t^ t^

x^

x^ x^

x

f^

f^

f^ w t

t^

f^

f^ f^

f

w t^

w t w t

D

X^ t^

x t^

x t^

f^ t

^

 ^

^

 

 ^

^

^

^

^

^

^

^

^

^

^

^ 

 ^

^

^

^

^

^

^

^

 ^

 ^

^ ^

is Markov^0 0;^

t f t 0

dX^ t^

PXdt^

QdB t t

X

X

 ^

^

^

 

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19

^ ^

^ 

^  ^ ^

    ^  ^ 

2 2 0 0; lim^32

0

1 exp^

;

Select C such that

1

Example:

1 exp^

; 2

4

0

pdf is Gaussian, as it should be.

x x

d^

x^ p^

d^ pD

p x

dx^

dx dpD

x^ p dx p x^

C^

s ds^

x

D p x dx x^ ax

bx ax^

bx

p x^

C^

x

Db

 

  

^

 ^

 ^

^

 

^

^

^

^

 ^

 

^

 ^

 

^  

 ^

^

^

^

 ^

 

^

 ^

 ^

^

^ ^

 

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20

^ ^

^ ^

 ^

^ ^

^ 

 ^

 ^ 

^ 

^     

     ^

   ^

^ ^

^ 

0

0

(^20121 )

2

1

sdof system with nonlinear damping and

nonlinear stiffness

;^ 0;

0

;^0

.

0;^

2 Total energy x 2 x^ xf

H^

g^ x^

w t^

t^

x^

x^ x^

x

w t^

w t w t

D

xH

g u du X^ t^

x t X^ t^

x t dX^ t

X

t dt dX^

t^

X g^

H^  g^ X

 

^

^

^

^

^

^

^

^ 

^

^ ^

^

^ ^

  ^

^ ^

^

^ ^

^

^ ^

  ^ ^

  Example :^ ^ ^

^

 

1 ^  X 2 2 20

dt^ dB t

XH

g u du

^ 

^

^

^ 

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