Statistics and Probability (Random Variables and Probability Distributions), Exercises of Mathematics

Learn about Statistics and Probability (Random Variables and Probability Distributions) with many examples and solutions given.

Typology: Exercises

2020/2021

Available from 11/04/2021

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Statistics and Probability:
Random Variables and Probability Distributions
Random Variable
- It is a result of chance event that you can measure or count.
- It is a numerical quantity that is assigned to the outcome of an experiment. It is
a variable that assumes numerical values associated with the events of an experiment.
- It is a quantitative variable which depends on change.
What I Know
A.
If two coins are tossed once, which is NOT a possible value of the random
variable for the number of heads?
a. 0 b. 1 c. 2 d. 3
Answer: 3
Solution:
Let H represent the number of heads that will come out. Determine the values of
the random variable H.
Steps Solution
1. List the sample space S= {TT, TH, HT, HH}
2. Count the number of heads in
each outcome and assign this
number to this outcome
Outcome Number of
Heads
(Value of H)
HH 2
HT 1
TH 1
TT 0
3. Conclusion The values of the random variable H
(number of heads) in this experiment
are 0, 1, and 2.
Which of the following is a discrete random variable?
a. Length of wire ropes
b. Number of soldiers in the troop
c. Amount of paint used in repainting the building
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Statistics and Probability: Random Variables and Probability Distributions Random Variable

  • It is a result of chance event that you can measure or count.
  • It is a numerical quantity that is assigned to the outcome of an experiment. It is a variable that assumes numerical values associated with the events of an experiment.
  • It is a quantitative variable which depends on change. What I Know A.  If two coins are tossed once, which is NOT a possible value of the random variable for the number of heads? a. 0 b. 1 c. 2 d. 3 Answer: 3 Solution: Let H represent the number of heads that will come out. Determine the values of the random variable H. Steps Solution
  1. List the sample space S= {TT, TH, HT, HH}
  2. Count the number of heads in each outcome and assign this number to this outcome Outcome Number of Heads (Value of H) HH 2 HT 1 TH 1 TT 0
  3. Conclusion The values of the random variable H (number of heads) in this experiment are 0, 1, and 2.  Which of the following is a discrete random variable? a. Length of wire ropes b. Number of soldiers in the troop c. Amount of paint used in repainting the building

d. Voltage of car batteries Answer: Number of soldiers in the troop  Which formula gives the probability distribution shown by the table? X 3 4 5 P(X) 1/3 1.4 1/ a. P(X)= X b. P(X)= 1/X c. P(X)= X/ d. P(X)= X/ Answer: P(X)= 1/X  How many ways are there in tossing two coins once? Answer: 4

  • Each coin can land in two possible ways (head or tail). Therefore, two coins can land in 4 possible ways.  It is a numerical quantity that is assigned to the outcome of an experiment. Answer: Random variable B. Discrete or continuous  The weight of the professional wrestlers Continuous  The number of winners in lotto for each day Discrete  The area of lots in an exclusive subdivision Continuous  The speed of a car Continuous  The number of dropouts in a school per district Discrete C.  Two coins are tossed. Let T be the number of tails that occur. Determine the values of the random variable T. Answer: 0, 1, 2

What’s In A.  Any activity which can be done repeatedly under similar conditions Answer: Experiment or trial  The set of all possible outcomes in an experiment Answer: Sample space  A subset of a sample space Answer: Event  The elements in a sample space Answer: Outcome  The ratio of the number of favorable outcomes to the number of possible outcomes Answer: Probability B.  In how many ways can two coins fall? Answer: 4 Since each coin can fall in two possible ways (head or tail), two coins can fall in 4 different ways (2 x 2 = 4)  If three coins are tossed, in how many ways can they fall? Answer: 8 2 x 2 x 2 = 8 ways  In how many ways can a die fall? Answer: 6  In how many ways can two dice fall? Answer: 36 Each die can fall in six ways. Hence, 6 x 6 = 36 ways.

 How many ways are there in tossing one coin and rolling a die? Answer: 12 A coin can fall in two ways and a die can fall in six ways. Hence, 2 x 6 = 12 ways. What’s New  Mary Ann, Hazel, and Analyn want to know what numbers can be assigned for the frequency of heads that will occur in tossing three coins. Can you help them? Thanks! Steps Solution

  1. List the sample space S= {HHH. HHT, HTH, THH, TTH, THT, HTT, TTT)
  2. Count the number of heads in each outcome and assign this number to this outcome Outcome Number of Heads (Value of H) HHH 3 HHT 2 HTH 2 THH 2 TTH 1 THT 1 HTT 1 TTT 0
  3. Conclusion The values of the random variable H (number of heads) in this experiment are 0, 1, 2, and 3. What’s More  A basket contains 10 red balls and 4 white balls. If three balls are taken from the basket one after the other, construct and illustrate the probability distribution. Steps Solution
  4. List the sample space S= {RRR. RRW, RWR, WRR, WWR, WRW, RWW, WWW)
  5. Count the number of red balls in each outcome and assign this number to this outcome Outcome Number of Red Balls (Value of R) RRR 3 RRW 2

What I Can Do Number of Defective COVID-19 Rapid Antibody Test Kit  Suppose three test kits are tested at random. Let D represent the defective test kit and let N represent the non-defective test kit. If we let X be the random variable for the number of defective test kits, construct the probability distribution of the random variable X. Steps Solution

  1. List the sample space S= {DDD. DDN, DND, NDD, NND, NDN, DNN, NNN)
  2. Count the number of defective kits in each outcome and assign this number to this outcome Outcome Number of Defective Kits (Value of X) DDD 3 DDN 2 DND 2 NDD 2 NND 1 NDN 1 DNN 1 NNN 0
  3. Construct the frequency distribution of the values of the given random variable. Number of Defective Kits (Value of X) Number of Occurrence (Frequency) 0 1 1 3 2 3 3 1 Total 8
  4. Construct the probability distribution of the given random variable by getting the probability of occurrence of each value of the random variable Number of Defective Kits (Value of X) Number of Occurrence (Frequency) Probability P(X) 0 1 1/ 1 3 3/ 2 3 3/ 3 1 1/ Total 8 1 The probability distribution of random variable X can be written as follows: R 0 1 2 3 P(R) 1/8 3/8 3/8 1/

Additional Activities Grace Ann wants to determine if the formula below describes a probability distribution. Solve the following: 𝑃(𝑋) =

X + 1

where X = 0, 1, 2. If it is, find the following:

  1. P (X = 2) P (2) =

2. P (X ≥ 1)

P (1, 2) =

3. P (X ≤ 1)

P (0, 1) =