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Circle your starting and end “dots” on the spider and trace the path needed. 4. Circle your final answer. Reminders: Each dot is a step in the solution. Each ...
Typology: Exercises
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Name: _____________________________ Date: _______________________ Period: ________
For each problem below that requires calculations:
Reminders: Each dot is a step in the solution. Each dot is also the units to put in the top boxes in your setup. Your diagonal units must match to cancel. If you need grams, use the periodic table. Also, recall that 1 mol of a gas = 22.4 L.
4 Al + 3 O 2 2 Al 2 O 3
A. 44.6 grams
B. 35.6 grams
C. 87.6 grams
D. 21.6 grams
1 B 2 (CO 3 ) 3 1 B 2 O 3 + 3 CO 2
A. 15 mol
B. 1.67 mol
C. 5 mol
D. 8 mol
4 HF + 1 O 2 2 F 2 + 2 H 2 O
A. 0.67 L
B. 2.68 L
C. 0.335 L
D. 1.34 L
1 C 2 H 4 + 3 O 2 2 CO 2 + 2 H 2 O
A. 20.88L
B. 2.32 L
C. 22.4 L
D. 6.54 L
A. 1:
B. 3:
C. 2:
D. 2:
2 K + Cl 2 2 KCl
A. Step 1 B. Step 2 C. Step 3 D. There is no mistake
A. 3 moles B. 1.5 moles C. 12 moles D. 6 moles
Step 1 Step 2 Step 3
2 H 2 + O 2 2 H 2 O
𝟓. 𝟎 𝐠 𝐎𝟐 𝟏
A. (^) 1.0 mole O18 g H^2 O 2
B. 2.0 mole H1.0 mole O^22 O
C. (^) 2.0 mole H18 g H^2 O 2 O
D. (^) 2.0 mole H2.0 mole O^2 2 O
A. Newton’s three laws of motion
B. Law of Conservation of Mass
C. Law of Molarity
D. Law of Scientific Principles
2 H 2 + O 2 2 H 2 O
A. H 2
B. O 2
C. Both A and B.
D.H 2 O
Short Answer:
Aluminum bromide can be prepared by the reaction of aluminum metal with bromine gas shown by the equation:
2 Al + 3 Br 2 2 AlBr 3
Now suppose that 5.6 mol of aluminum reacts with 4.4 mol of bromine.
The limiting reactant is _________________________.
The excess reactant is __________________________.
The actual amount of product produced is __________________________.