Linear Algebra: Eq., Lin. Ind., Eigenvalues, Study notes of Mathematics

An explanation of linear algebra concepts including linear independence, eigenvalues, and eigenvectors. It includes examples of solving linear systems, finding eigenvectors, and determining if matrices are singular or nonsingular. The document also discusses the relationship between linear independence and invertibility.

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Pre 2010

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Ch 7.3: Sys. Lin. Eq., Lin. Ind., Eigenvalues
A system of nlinear equations in nvariables,
2,222,211,2
1,122,111,1
nn
nn
bxaxaxa
bxaxaxa
=+++
=+++
L
L
can be expressed as a matrix equation
Ax
=
b
:
,
,22,11, nnnnnn bxaxaxa =+++ L
M
can
be
expressed
as
a
matrix
equation
Ax
b
:
n
n
b
b
x
x
aaa
aaa
L
L
2
1
2
1
2
2
2
1
2
,12,11,1
=
nn
nnnn
n
bx
aaa
MM
L
MOMM
2
2
,2,1,
,
2
2
,
2
1
,
2
To see that the matrix equation is equivalent to the system of equations,
multiply the matrix and vector on the left side and equate components.
If b= 0, the system is said to be homogeneous
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19

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Ch 7.3: Sys. Lin. Eq., Lin. Ind., Eigenvalues^ •

A system of

n

linear equations in

n

variables,

2

, 2

2 (^2) , 2

1 (^1) , 2

1

, 1

2 (^2) , 1

1 (^1) , 1

n n

n n

b x a x a x a b x a x a x a =

L L

can be expressed as a matrix equation

Ax

=

b

: ,

,

2 (^2) ,

1 (^1) ,

n n nn

n

n^

b x a x a x

a^

+^
L
M

can

be expressed as a matrix equation

Ax

b :

n^ n

b b

x x

a

a

a

a

a

a

L L

1 2

1 2

2

(^22)

(^12)

, 1

(^2) , 1

(^1) , 1

⎜ ⎜ ⎜⎜⎝^

n

n nn

n

n

n

b

x

a

a

a

M
M
L
M
O
M
M

2

2

,

(^2) ,

(^1) ,

, 2

(^2) , 2

(^1) , 2

To see that the matrix equation is equivalent to the system of equations,

multiply the matrix and vector on the left side and equate components.

-^

If^

b^

=^

0 , the system is said to be

homogeneous

Nonsingular (i.e., Invertible) CaseNonsingular

(i.e., Invertible) Case

•^

An invertible matrix

A

is called nonsingular

An invertible matrix

A

is called nonsingular.

•^

If

A

is invertible, we can always solve

Ax

b

as follows:

b

A

x

b

A

Ix

b

A

Ax

A

b

Ax

−^

= •^

This solution is unique.

•^

If

A

is invertible, the only solution to

Ax

^0

is

the trivial solution

A

(^1)

x

A

^0

Example 1: Nonsingular Case

(2 of 2)

-^

Now let’s solve the nonhomogeneous linear system A

b

b l

i^

A

(^1)

A

x^

=^

b

below using

A

3

2

1

3

2 1

x

x

x

x

x x

-^

This system of equations can be written as

Ax

b

where

3

2

1

3

2

1

x

x x

x

x

x

where

⎞⎟ ⎟ ⎟ ⎠ ⎛⎜ −⎜ ⎜ ⎝ = ⎞⎟ ⎟ ⎟ ⎠ ⎛⎜ ⎜ ⎜ ⎝ = ⎞⎟ ⎟ ⎟ ⎠

⎛⎜ ⎜ ⎜ ⎝

2 2 0

,

, 8 3 4

3 0 1

2 1 0

1 2

b

x

A^

x x

-^

Then

⎞ ⎟ ⎟

⎛ −⎜ ⎜ ⎞⎟ ⎟ ⎛⎞⎜⎟ ⎜⎟

⎛^ ⎜ ⎜

−^

23

2 (^2) / 3 7 (^2) / 9

1

⎟ ⎠ ⎜ ⎝

⎟ ⎠ ⎜ ⎝

⎟ ⎠

⎜ ⎝^

−^

0

8 3 4

x^3

⎟ ⎟ ⎠ −=⎜ ⎜ ⎝ ⎟ ⎟ ⎠ −⎜⎟ ⎜⎟ ⎝⎠

⎜ ⎜ ⎝^

=

=^

12 7

2 0 (^2) / 1 2 (^2) / 3

1

4 2

1 b A x

Singular Case

-^

If the coefficient matrix

A

is singular (not invertible),

then either there is no solution to

Ax

b

, or there are

i fi it l

l ti

t^

A

b

infinitely many solutions to

A

x^

=^

b

We can find these solutions by row reducing

(A | b).

Example 3: Linear Independence

(1 of 2)

Example

3: Linear Independence

(1 of 2)

-^

Determine whether the following vectors are linearDetermine whether the following vectors are lineardependent or linearly independent.

⎞ ⎟ ⎛⎜

⎞⎟ ⎛⎜

⎞⎟ ⎛^ ⎜

2

1

0

) (^3) (

) (^2) (

) (^1) (

⎟ ⎟ ⎟⎠ ⎜ ⎜ ⎜⎝ =

⎟ ⎟ ⎟⎠ ⎜ =⎜ ⎜−⎝

⎟ ⎟ ⎟⎠ ⎜ =⎜ ⎜⎝

3 8

, 0 3

, (^1 )

) (^3) (

) (^2) (

) (^1) (

x

x

x

-^

We need to determine for what coefficients

x

x

x^

+^

) (^3) ( 3 ) (^2) ( 2 ) (^1) ( 1

c

c

c

or

⎞ ⎟ ⎟ ⎛⎜ =⎜ ⎞⎟ ⎟ ⎛⎞⎜⎟ ⎜⎟

⎛⎜ ⎜ ⇔ ⎞⎟ ⎟ ⎛⎜ =⎜ ⎞⎟ ⎟ ⎛⎜ ⎜ ⎞⎟ +⎟ ⎛⎜ ⎜ ⎞⎟ +⎟ ⎛⎜ ⎜

0 0

3 0 1

2 1 0

0 0

2 3

(^10)

0 1

c^1 c

c

c

c

⎟ ⎟⎠ =⎜ ⎜⎝ ⎟ ⎟⎠ ⎜⎟ ⎜⎟⎝⎠

⎜ ⎜⎝^

⇔ ⎟ ⎟⎠ =⎜ ⎜⎝ ⎟ ⎟⎠ ⎜ ⎜⎝ +⎟ ⎟⎠ ⎜ ⎜−⎝ +⎟ ⎟⎠ ⎜ ⎜⎝^

0 0

8 3 4

3 0 1

0 0

3 8

0 3

(^14)

2 3

3

2

1

c^ c

c

c

c

Example 3: Linear Independence

(2 of 2)

Example

3: Linear Independence

(2 of 2)

-^

We reduce the augmented matrix (

A

| b

We reduce the augmented matrix (

A

| b

(^

)^

⎞ ⎟ ⎟ ⎟

⎛⎜ ⎜ ⎜ ⎞⎟ →⎟ ⎟

⎛⎜ ⎜ ⎜ =^

0 2 1 0

0 3 0 1 0 3 0 1

0 2 1

0

b A (

)

⎞ ⎟ ⎟ ⎛⎜ ⎜

=

⎟ ⎟⎠

⎜ ⎜⎝ ⎟ ⎟⎠

⎜ ⎜⎝^

0 0

0

2

0

3

0 1 0 0 0 8 3 4

3

1

c

c

Th

th

l^

l ti

i^

d

⎟ ⎟⎠ ⎜ ⎜⎝ = →

= =

0 0

0 0

2

3 3

2

c

c c

c

-^

Thus, the only solution is

c

c

2

cn

= 0, and

therefore the original vectors are linearly independent.

Example 4: Linear Dependence

(2 of 2)

Example

4: Linear Dependence

(2 of 2)

-^

We thus reduce the augmented matrix (

A

| b

) as

We thus reduce the augmented matrix (

A

| b

), as

before.^ (

)^

⎞ ⎟ ⎟ ⎟

⎛^ ⎜ ⎜ ⎜

⎞⎟ →⎟ ⎟

⎛⎜ −⎜ ⎜

− −

=^

0 5 3

0

0 1 2 1 0 6 5 1

0 1 2 1

b A (^

)

⎞ ⎟ ⎟ ⎛⎜ ⎜

⎞⎟ ⎟

⎛ −⎜ ⎜

=

⎟⎠

⎜⎝ ⎟⎠

⎜⎝^

7 5

(^3) / 5

(^3) / 7

0

5

3

0

1

2

0 0 0 0 0 5 4 5

3

3

2

1

k

c

c

c

c

Thus the original vectors are linearly dependent with

⎟ ⎟⎠ ⎜ ⎜−⎝ = →⎟ ⎟⎠

−⎜ ⎜⎝

→ = =

5 3

(^3) / 5

0

0

0

5

3

3 3

3 3

2

k

c c

c c

c^

c

c

Thus

the original vectors are linearly dependent, with

⎞ ⎟ ⎟ ⎛⎜ ⎜ ⎞⎟ ⎟ ⎛ −⎜ ⎜ ⎞⎟ ⎟ ⎛ −⎜ ⎜ ⎞⎟ +⎟ ⎛⎜ ⎜

0 0

(^16) 3 2 5 5 1 1 7

⎟ ⎟⎠ ⎜ ⎜⎝ =⎟ ⎟⎠

⎜ ⎜⎝ −⎟ ⎟⎠

⎜ ⎜−⎝ +⎟ ⎟⎠ −⎜ ⎜⎝

(^00)

6 5 3 5 4 5 (^15) 7

Linear Independence and InvertibilityLinear

Independence and Invertibility

-^

Consider the previous two examples:

-^

Consider the previous two examples:– The first matrix was known to be nonsingular, and its

column vectors were linearly independent.

y^

p

  • The second matrix was known to be singular, and its

column vectors were linearly dependent.

-^

This is true in general: the columns (or rows) of A

are linearly independent if and only if

A

is

nonsingular if and only if

A

exists

nonsingular if and only if

A

(^1)

exists.

-^

Also,

A

is nonsingular if and only if det

A

hence columns (or rows) of

A

are linearly

hence columns (or rows) of

A

are linearly

independent if and only if det

A

Eigenvalues and EigenvectorsEigenvalues

and Eigenvectors

-^

The eqn

Ax

=

y

can be viewed as a map of the

The eqn.

Ax

y

can be viewed as a map of the

vector

x

into a new vector

y

.

-^

Nonzero vectors

x

that

A

maps to multiples of

themselves are important in applications.

-^

We

will be interested in finding numbers

λ^

and

corresponding vectors

x

such that

Ax

=

λ

x

or

corresponding vectors

x

such

that

Ax

=

λ

x

or

equivalently, (

A

-^ λ

I )

x

=

^0

.

-^

This equation has a nonzero solution if we

q

choose

λ^

such that det (

A

-^ λ

I ) = 0.

-^

Such values of

λ^

are called

eigenvalues

of

A

,

and the corresponding nonzero solutions

x

are

and the corresponding nonzero solutions

x

are

called

eigenvectors

.

Example 5: Eigenvalues

(1 of 3)

Example

5: Eigenvalues

(1 of 3)

-^

Find the eigenvalues and eigenvectors of the matrix

A

Find the eigenvalues and eigenvectors of the matrix

A

=^
A

-^

Solution: Choose

λ^

such that det(

A

-^ λ

I ) = 0, as follows.

⎛^

(^

det

det

⎛^ ⎜

λ I

A

(^

)(^

)^

det

(^

)(^

2

Example 5: Second Eigenvector

(3 of 3)

Example

5: Second Eigenvector

(3 of 3)

-^

Eigenvector for

λ^

=^

- 7:

Solve

Eigenvector

for

λ^

Solve

(^

)^

−^

1 2

1 2

x x

x x

x I

A

by row reducing the augmented matrix:

⎝^
+^

2

2

x

x

2 2

1

x x

x

choose

arbitrary , 1

) (^2) (

2 2

) (^2) (

x

x^

c

c

x x

Normalized EigenvectorsNormalized

Eigenvectors

-^

From the previous example we see that eigenvectorsFrom the previous example, we see that eigenvectorsare determined up to a nonzero multiplicativeconstant.

-^

If this constant is specified in some particular way,then the eigenvector is said to be

normalized

-^

For example eigenvectors are sometimes normalized

-^

For example, eigenvectors are sometimes normalizedby choosing the constant so that ||

x || = (

x ,

x

Eigenvectors and Linear IndependenceEigenvectors

and Linear Independence

-^

If an eigenvalue

λ^

has algebraic multiplicity 1 then it is

If an eigenvalue

λ^

has algebraic multiplicity 1, then it is

said to be

simple

, and the geometric multiplicity is 1

also.

-^

If each eigenvalue of an

n

x

n

matrix

A

is

simple

, then

A

has

n

distinct eigenvalues. It can be shown that the

n^

eigenvectors corresponding to these eigenvalues

n^

eigenvectors corresponding to these eigenvalues

are linearly independent.

-^

If an eigenvalue has one or more

repeated

i^

l^

th

th

b^

f^

th

li^

l

eigenvalues

, then there may be fewer than

n

li

nearly

independent eigenvectors.

This may lead to

complications in solving systems of differential

p^

g^

y

equations.

Example 6: Eigenvalues

(1 of 5)

Example

6: Eigenvalues

(1 of 5)

-^

Find the eigenvalues and eigenvectors of the matrix

A

Find the eigenvalues and eigenvectors of the matrix

A

=^
A

-^

Solution: Choose

λ^

such that det(

A

-^ λ

I ) = 0, as follows.

⎜⎝^

(^

)^

det

det

λ I

A

2

3

⎜⎝^

3

2

1

2