Taylor Theorem - Calculus - Exam, Exams of Calculus

Some past exams of Calculus for students. Keywords of the exam are: Taylor Theorem, Derivatives, Approximation, Third Degree, Theorem Guarantees, Maximum Guaranteed Error, Interval, Decimal Places, Error, Same

Typology: Exams

2012/2013

Uploaded on 03/16/2013

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Math 106 BC Exam 02 page 1 11/05/2010 Name
1. Let f(x) = (x1)5= (x1)5/2.
1a. Use the following table of derivatives of fto find the third degree Taylor polynomial approximation P3(x) of f(x), in
powers of x5, ie, x0= 5.
k f(k)(x)f(k)(5)
0 (x1)5= (x1)5/232
15
2(x1)3/220
215
4x115
2
315
8
1
x1
15
16
415
16 (x1)3/215
128
1b. Taylor’s theorem guarantees that fand P3will separate by no more than what value (call it ), on the interval
[2.5,6]? Show all your work. (Find K4to two decimal places. Find the maximum guaranteed error to 4 decimal places.)
1c. Since f(x) = (x1)5, we could use it to find (3)5= 35/2by taking x= 4. Use the same xto approximate (3)5
with your Taylor polynomial P3(x). What do you get? What’s the error in this approximation? (Write your answers to 4
decimal places).
pf3
pf4
pf5

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  1. Let f(x) = (

x − 1) 5 = (x − 1) 5 / 2 .

1a. Use the following table of derivatives of f to find the third degree Taylor polynomial approximation P 3 (x) of f(x), in

powers of x − 5, ie, x 0 = 5.

k f(k)^ (x) f(k)^ (5)

x − 1) 5 = (x − 1) 5 / 2 32

(x − 1)

3 / 2 20

x − 1

x − 1

(x − 1)

− 3 / 2 −^15

1b. Taylor’s theorem guarantees that f and P 3 will separate by no more than what value (call it ), on the interval

[2. 5 , 6]? Show all your work. (Find K 4 to two decimal places. Find the maximum guaranteed error  to 4 decimal places.)

1c. Since f(x) = (

x − 1)^5 , we could use it to find (

3)^5 = 3^5 /^2 by taking x = 4. Use the same x to approximate (

3)^5

with your Taylor polynomial P 3 (x). What do you get? What’s the error in this approximation? (Write your answers to 4

decimal places).

  1. Find

x 3 − 4 x √ 4 + x^2

dx by introducing an appropriate trig substitution, say, x = 2 tan t. Express your answer in terms of

x and

4 + x^2 (leave no trig functions in your answer if possible)

  1. At some point, most calculus students learn that

d

dt

arcsin t is

1 − t^2

. But to find

arcsin x dx requires integration

by parts. Show how.

5A. Find

4 x − 5 + 7 x 2

(1 + x^2 ) (x − 3)

dx.

Show all your work, from setting up the partial fraction decomposition to solving for A, B, C, etc, to final integrations.

5B. Explain why

0

4 x − 5 + 7 x 2

(1 + x^2 ) (x − 3)

dx is an improper integral.

5C. Does the integral in 5B converge? Explain! (You do not have to make a table. Just make a good argument, knowing

standard behavior of the functions involved in the anti-derivative in 5A).

  1. Here is the graph of f(x) =

0 if x < − 1

0 .25(x + 1) if − 1 ≤ x < 1

λe −λx if 1 ≤ x for a certain value of λ:

6a. By definition, what is the total area of the entire (both the light and dark parts combined) shaded region required to

be in order for f to be a probability density function?

6b. It’s easy to find the area of the lightly-shaded region. What is it?

6c. Find λ so that the area of the darkly-shaded region is what it needs to be, according to your answers in 6a and 6b.

You may use without verification this fact:

a

λe −λx dx = e −λa .

6d. Suppose that X is a random variable with this f as its probability density function. What’s the probability that X

is negative?

6e. What’s the probability that X is in the interval [0, 1]?

6f. What’s the probability that X is greater than 4?