Test 4 Answer Key | General Physics I | PH 221, Exams of Physics

Material Type: Exam; Class: General Physics I; Subject: Physics; University: University of Alabama - Birmingham; Term: Fall 2009;

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GENERAL PHYSICS PH 221-3A
(Dr. S. Mirov)
Test 4 (12/03/07)
STUDENT NAME: ________________________ STUDENT id #: ___________________________
-------------------------------------------------------------------------------------------------------------------------------------------
Key
Sample
ALL QUESTIONS ARE WORTH 20 POINTS. WORK OUT FIVE PROBLEMS.
NOTE: Clearly write out solutions and answers (circle the answers) by section for each part (a., b., c., etc.)
Important Formulas:
1
Motion along a straight line with a constant acceleration
1
.
Motion
along
a
straight
line
with
a
constant
acceleration
vaver. speed = [dist. taken]/[time trav.]=S/t;
vaver.vel. =
Δ
x/
Δ
t;
vins =dx/
Δ
t;
aaver.=
Δ
vaver. vel./
Δ
t;
a = dv/
Δ
t;
v = vo + at; x= 1/2(vo+v)t; x = vot + 1/2 at2; v2 = vo2 + 2ax (if xo=0 at to=0)
2.
Free fall motion (with positive direction )
g
= 9.80 m/s2;
y
= vaver. t
vaver.= (v+vo)/2;
v = vo - gt; y = vo t - 1/2 g t2; v2 = vo2 – 2gy (if yo=0 at to=0)
3
Motion in a plane
3
.
Motion
in
a
plane
vx = vo cos
θ
;
vy = vo sin
θ
;
x
= vox t+ 1/2 ax t2; y = voy t + 1/2 ay t2; vx = vox + at; vy = voy + at;
4.
Projectile motion (with positive direction )
vx = vox = vo cos
θ
;
x
=
v
ox
t
xv
ox
t
x
max = (2 vo2 sin
θ
cos
θ
)/g = (vo2 sin2
θ
)/g for yin = yfin;
vy = voy - gt = vo sin
θ
- gt;
y
= voy t - 1/2 gt2;
5. Uniform circular Motion
a=v2/r,
T=2
π
r/v
6. Relative motion
P
APBBA
PA PB
vvv
aa
=+
=
rrr
rr
7.
Com
p
onent method of vector addition
1
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe

Partial preview of the text

Download Test 4 Answer Key | General Physics I | PH 221 and more Exams Physics in PDF only on Docsity!

GENERAL PHYSICS PH 221-3A

(Dr. S. Mirov)

Test 4 (12/03/07)

STUDENT NAME: ________________________ STUDENT id #: ___________________________ -------------------------------------------------------------------------------------------------------------------------------------------

Key

Sample

ALL QUESTIONS ARE WORTH 20 POINTS. WORK OUT FIVE PROBLEMS.

NOTE: Clearly write out solutions and answers (circle the answers) by section for each part (a., b., c., etc.)

Important Formulas:

Motion along a straight line with a constant acceleration

Motion

along a straight line with a constant acceleration

v aver. speed

= [dist. taken]/[time trav.]=

S/t;

v aver.vel.

x

/^ Δ

t;

v ins

=d

x

/^ Δ

t;

a

aver.

v aver. vel

t;

a

= d

v

/^ Δ

t;

v = v

o^

at;

x= 1/2(v

+v)t; x = vo^

t + 1/2 ato

v

2

= v

(^2) o

  • 2ax

(if

x

=0 at to

=0)o

Free fall motion (with positive direction

g

= 9.80 m/s

y = v

aver.

t

v aver.

= (v+v

)/2o

v = v

o^

  • gt

;^

y = v

o^

t - 1/2 g t

v 2

= v

(^2) o

  • 2gy

(if

y

=0 at to

=0)o

3

Motion in a plane

3

.^

Motion

in a plane

v x^

= v

o^

cos

v y^

= v

o^

sin

x = v

ox

t+ 1/2 a

x^

(^2) t

;^

y = v

oy

t + 1/2 a

y^

(^2) t

;^

v x^

= v

ox

  • at

;^

v y^

= v

oy

  • at

4.

Projectile motion (with positive direction

v x^

= v

ox

= v

o^

cos

x = v

ox

t

x

v ox

t

x max

= (2 v

(^2) o sin

cos

)/g = (v

(^2) o

sin

)/g

for

y

in

= y

fin

v y^

= v

oy

  • gt = v

o^

sin

  • gt

y = v

oy

t - 1/2 gt

Uniform circular Motion

a=v

2 /r,

T=

r/v

Relative motion

P^ A

P B

B A

P A

P B

v^

v^

v

a^

a

=^

r^

r^

r

r^

r

7.

Component method of vector addition

A

A

1

A

2

; A

= x

A

x

A

x

and

A

y^

A

y

A

y

;^

A^

A^

A

x^

y

=^

2

2

= tan

A

y^

/A

⏐x

The scalar product

A

=^

c o s

a^

b^

a b

φ

⋅^

r

r

ˆ^

ˆ^

ˆ^

ˆ^

(^

)^

(^

x^

y^

z^

x^

y^

z

a^

b^

a^

i^

a^

j^

a^

k^

b^

i^

b^

j^

b^

k

⋅^

=^

+^

+^

⋅^

+^

r

r

r^

=^

x^

x^

y^

y^

z^

z

a^

b^

a^

b^

a^

b^

a^

b

⋅^

+^

r The vector product

ˆ^

ˆ^

ˆ^

ˆ^

(^

)^

(^

x^

y^

z^

x^

y^

z

a^

b^

a^

i^

a^

j^

a^

k^

b^

i^

b^

j^

b^

k

×^

=^

+^

+^

×^

+^

r

r

ˆ^

ˆ^

y^

z^

x^

y

x^

z

x^

y^

z

y^

z^

x^

y

x^

z

x^

y^

z

i^

j^

k^

a^

a^

a^

a

a^

a

a^

b^

b^

a^

a^

a^

a^

i^

j^

k

b^

b^

b^

b

b^

b

b^

b^

b

×^

=^

−^

×^

=^

=^

−^

+^

r^

r

r^

r

ˆ^

(^

)^

(^

)^

(^

y

y^

z^

y^

z^

z^

x^

z^

x^

x^

y^

x^

y

a^

b^

b^

a^

i^

a^

b^

b^

a^

j^

a^

b^

b^

a^

k

=^

−^

+^

−^

+^

Second Newton’s Law m

a

F

net

;

Kinetic friction

f =k^

μ

Nk

;

St ti

f i ti

f^

N

St

atic friction

f

=s

μ

N;s

Universal Law of Gravitation:

F=GMm/r

2 ;

G=6.67x

Nm

2 /kg

2 ;

Drag coefficient

2

D

C

A v

ρ

6.

Terminal speed

t

m g

v^

C^

A

ρ

Centripetal force:

F

=mvc

2 /r

Speed of the satellite in a circular orbit:

v

2 =GM

/rE

r

The work done by a constant force acting on an object:

c o s

W

F d

F^

d

φ

=^

=^

⋅^

r

r

Kinetic energy:

2

K

m v

Total mechanical energy:

E=K+U

The work-energy theorem:

W=K

-Kf

;o W

nc

=

Δ

K+

Δ

U=E

-Ef

o

The principle of conservation of mechanical energy:

when

W

nc

=0, E

=Ef^

o

Work done by the gravitational force:

c o s

g

W

m g d

φ

=^

Linear Momentum and Newton’s Second law for a system of particles:

a n d c o m

n e t

d P

P^

M v

F^

d t

=^

r

r^

r

r

Collision and impulse:

(^

)^

;^

t^ f i

a v g

t

J^

F^

t^

d t

J^

F^

t

=^

=^

r^

r^

when a stream of bodies with mass m and

speed v, collides with a body whose position is fixed

a v g

n^

n^

m

F^

p^

m

v^

v

t^

t^

t Δ

=^

−^

Δ^

=^

−^

Δ^

=^

−^

Δ^

Δ^

t^

t^

t

Δ^

Δ^

Impulse-Linear Momentum Theorem:

f^

i

p^

p^

J

−^

=^

r

r^

r

3.

Law of Conservation of Linear momentum:

f o r

c l o s e d , i s o l a t e d

s y s t e m

i^

f

P^

P

r^

r

4.

Inelastic collision in one dimension:

1

2

1

2

i^

i^

f^

f

p^

p^

p^

p

+^

=^

r^

r^

r^

r

Motion of the Center of Mass:

The center of mass of a closed, isolated system of two colliding bodies is

not affected by a collision.

Elastic Collision in One Dimension:

1

2

1

1

1

2

1

1

2

1

2

f^

i^

f^

i

m

m

m

v^

v^

v^

v

m

m^

m

m

=^

+^

Collision in Two Dimensions:

1

2

1

2

1

2

1

2

i x^

i x^

f x^

f x^

i y^

i y^

f y^

f y

p^

p^

p^

p^

p^

p^

p^

p

+^

=^

+^

+^

=^

Variable-mass system:

( f i r s t r o c k e t

e q u a t i o n )

l n

( s e c o n d

r o c k e t e q u a t i o n )

r e l

i

f^

i^

r e l

f

R v

M a

M

v^

v^

v^

M

−^

S

Angular Position:

( r a d i a n

m e a s u r e )

S^ r

θ^

Angular Displacement:

2

1

( p o s i t i v e

f o r

c o u n t e r c l o c k w i s e

r o t a t i o n )

θ^

θ^

Δ^

=^

Angular velocity and speed:

;^

( p o s i t i v e

f o r

c o u n t e r c l o c k w i s e

r o t a t i o n )

a v g

d

t^

d t

=^

Angular acceleration:

a v g

d

t^

d t

=^

angular acceleration:

2

(^

o o

o

o^

t o

t

t^

t

ω^

ω^

θ^

θ^

θ^

=^

−^

=^

−^

=^

2

2

2

(^

o^

o

o^

t^

t

ω^

α^

θ^

θ^

θ^

=^

+^

−^

=^

Linear and angular variables related:

2

2

v^

r

T

π

π

θ^

2

;^

;^

;^

t^

r

s^

r^

v^

r^

a^

r^

a^

r^

T

r^

v

θ

ω

α

ω

ω

=^

=^

=^

=^

=^

=^

3.

Rotational Kinetic Energy and Rotational Inertia:

2

2

2 1

;^

f o r

b o d y

a s

a

s y s t e m

o f

d i s c r e t e

p a r t i c l e s ;

f o r

a

b o d y

w i t h

c o n t i n u o u s l y

d i s t r i b u t e d

m a s s.

i^

i

K^

I^

I^

m

r

I^

r^

ω d m

=^

∫^

y^

y

4.

The parallel axes theorem:

2

c o m

I^

I^

M

h

=^

5.

Torque:

s i n

t r F

r^

F^

r F

=^

=^

6.

Newton’s second law in angular form:

n e t

I

τ

α

7.

Work and Rotational Kinetic Energy:

;^

(^

)^

f o r

f i

f^

i

d^

W

c o n s t

W

θ θ

τ^

τ^

θ^

=^

−^

=^

2

2

;^

w o r k

e n e r g y

t h e o r e m

f o r

r o t a t i n g

b o d i e s

f^

i^

f^

i

d W

P^

K^

K^

K^

I^

I^

W

d t

=^

Δ^

=^

−^

=^

−^

d t

8.

Rolling bodies:

2

2

s i n

f o r

r o l l i n g

s m o o t h l y

d o w n

t h e

r a m p

c o m

c o m

c o m

c o m v^

R

K^

I^

m v

a^

R

g

a

α^

=^

= =^

2

f o r

r o l l i n g

s m o o t h l y

d o w n

t h e

r a m p

c o m

c o m

a^

I^

M

R

=^

9.

Torque as a vector:

;^

s i n

r^

F^

r F

r F

r^

F

φ^

⊥^

=^

×^

=^

=^

r

r^

r

1.

Damped Harmonic Motion:

2

2

2

2

1

(^

)^

c o s (

'^

) ,

'^

,^

(^

)

4

2

b t^

b t

m^

m

m^

m

k^

b

x^

t^

x^

e^

t^

E^

t^

k x

e

m^

m

ω

φ^

ω

−^

=^

+^

=^

−^

2

1

(^

)^

i^

(^

)

k^

k^

f^

f

π^

ω

ω^

λ^

λ

2.

Sinusoidal waves:

(^

,^

)^

s i n (

) ,

,^

,

2

m

y^

x^

t^

y^

k x

t^

k^

f^

v^

f

T^

k^

T

ω

λ

λ

π

=^

−^

=^

=^

=^

=^

=^

=

3.

Wave speed on stretched string:

v

τ μ

=

4.

Average power transmitted by a sinusoidal wave on a stretched string:

2

2

1 2

a v g

m

P^

v^

y

μ^

ω

=

5.

Interference of waves:

1

1

' (^

,^

)^

[ 2

c o s

] s i n (

)

2

2

m

y^

x^

t^

y^

k x

t

φ

ω

φ

=^

−^

6.

Standing waves:

' (^

,^

)^

[ 2

s i n

] c o s

m

y^

x^

t^

y^

k x

t ω

=

7.

Resonance:

,^

f o r

1 , 2 , 3 ,...

2

v^

v

f^

n^

n

L

λ =^

=^

=

8.

Sound waves:

, B

v

ρ

=

9.

Interference:

2

( 2

)^

f o r

0 , 1 , 2 , 3... ,

c o n s t r u c t i v e

i n t e r f e r e n c e

2

( 2

1 )

f o r

0

1

2

3

d e s t r u c t i v e

i n t e r f e r e n c e

L^

m^

m

L^

m^

m

φ

π

π

λ

φ

π

π

Δ =^

=^

=

Δ =^

=^

+^

=

2

( 2

1 )

f o r

0 , 1 , 2 , 3... ,

d e s t r u c t i v e

i n t e r f e r e n c e

m^

m

φ

π

π

λ =^

=^

+^

=

10.

Sound Intensity:

2

2

2

1

,^

,

2

4

s

m

P^

P

I^

I^

v^

s^

I

A^

r

ρ^

ω

π

=^

=^

=

11.

Sound level in decibels:

1 2

2

( 1 0

) l o g

,^

1 0

/

o

I o

d B

I^

W^

m

I

β^

=^

=

12.

Standing wave patterns in pipes:

,^

1 , 2 , 3 ,... ,

f o r

p i p e

o p e n e d

f r o m

b o t h

e n d s

2

,^

1 , 3 , 5 ,... ,

f o r

p i p e

c l o s e d

a t

o n e

e n d

a n d

o p e n e d

a t

t h e

o t h e r

4

v^

n v

f^

n L

v^

n v

f^

n L

λ λ =^

=^

=

=^

=^

=

13.

Beats:

1

2

f^ b e a t

f^

f

=^

The Doppler effect:

f^

f^

v v

R s

'^

(^

)

=

± 1

,^

v^ R

the speed of the receiver; v

s^ the speed of the

sound;(v

=331m/s);s

  • f

i^

hi

i^

i

  • for receiver approaching stationary emitter,- for receiver moving away from the stationary emitter;

f^

f^

v

E

'^ =

⎛ ⎜ ⎜⎜

⎞ ⎟ ⎟⎟

1

1

m

,^

v^ E

the speed of the emitter, v

s^ the speed of the sound,

v E

s

⎜^ ⎝

⎟⎠

1

m

  • for emitter approaching stationary receiver,+ for emitter moving away from the stationary receiver;

'^

general Doppler Effect

s^

R

v

v

f^

f^

±

=

general Doppler Effect

s^

E

f^

f

v

v m

Your grandfather clock’s pendulum has a length of 0.9930 m. if the clockloses half a minute per day, how should you adjust the length of thependulum?

L

For a simple pendulum

Suppose clock's pendulum oscillates "n" times in a day.

L

T

g

1

pp

p

y

after the adjustment of the pendulum's length

nT

s

⋅^

2

2

nT

s

L g

T

L

⋅^

2 1

1

Take ratio

g

T

L

T

L g

2 1

L

2

2

2

4

L L

L

m

2

1

L

L

m