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TEST PAPER ON LIGHT- REFLECTION & REFRACTION with complete Solution Based on Class 10 Board Examination
Typology: Exams
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Q1. In the following questions, a statement of Assertion is given by the corresponding statement of Reason. Of the statements, mark the correct answer as:
1 Mark
Q2. In the following questions, a statement of Assertion is given by the corresponding statement of Reason. Of the statements, mark the correct answer as:
1 Mark
Q3. In the following questions, a statement of Assertion is given by the corresponding statement of Reason. Of the statements, mark the correct answer as:
1 Mark
Q4. A student has obtained an image of a distant object on a screen to determine the focal length F of the given lens. His teacher after checking the image, gave him another lens of focal length F and asked to focus the same object on the same screen. The student found that to obtain a sharp image he has to move the lens away from the screen. From this finding we may conclude that both the lenses given to the student were:
1 Mark
BHANDARA
Test / Exam Name: Light, Reflection & Refraction
Standard: 10th Subject: Science
Student Name: Section: Roll No.:
Questions: 22 Time: 01 00 hh:mm Marks: 50
Instructions
13
1 2
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Q6. A student obtains a sharp image of the distant window (W) of the school laboratory on the screen (S) using the given concave mirror (M) to determine its focal length. Which of the following distances should he measure to get the focal length of the mirror?
1 Mark
Q7. A student is using a convex lens of focal length 10 cm to study the image formation by a convex lens for the various positions of the object. In one of his observations, he may observe that when the object is placed at a distance of 20 cm from the lens, its image is formed at (select the correct option):
1 Mark
Q8. Beams of light are incident through the holes A and B and emerge out of box through the holes C and D respectively as shown in the Figure. Which of the following could be inside the box?
1 Mark
Q9. A convex mirror of focal length f forms an image of the size of the object. The
distance of the object from the mirror is:
1 Mark
Q10. A perfecting reflecting mirror has an area of 1cm. Light energy is allowed to fall on it for an hour at the rate of 10cm. The force that acts on the mirror is:
1 Mark
Q11. The boy walks towards the mirror at a speed of 1m/ s. At what speed does his image approach him?
2 Marks
Q12. List four precautions which a student should observe while determining the focal length of a given convex lens by obtaining image of a distant object on a screen.
2 Marks
1 nth n+1n f (n + 1)f (n − 1)f n - 1n f 2
Q20.
The bending of light as it passed from one transparent medium into another is called refraction. Place a pencil in an inclined position in a glass trough and fill three fourth of the trough with water.
Sunil wants to see the micro organisms present in soil. He knows that he needs a microscope to see those tiny things. A microscope is an instrument used to see a small object to look bigger which helps us in a study of many tiny little species. Well, refraction also plays a huge role in the microscope.
4 Marks
n = cv n = vc n = cv v = nc
Abin wanted to see the stars of the night sky. He knows that he needs a telescope to see those distant stars. There are two types of telescopes, reflecting telescopes which are made of mirrors and refracting telescope which are made of lenses. So he decided to take a refracting telescope. There are two lenses, the larger lense gathers and bends the light, while the smaller lens magnifies the image.
4 Marks
1 Mark
Ans: 3. Convex and F > F. Explanation: The lens is convex, as it forms real image. As mentioned in the second case, the image distance (v) is increasing; hence, the object distance (u) is decreasing. The lens formula is 1/ F = 1/ v - 1/ u ⇒ F = uv/ u - v For convex lens, object distance = -u Image distance = v ⇒ F = uv/ u + v where F is the focal length of the lens. Therefore, F is lesser for the second lens of focal length F. Hence, F > F. Hence, the correct option is C. Q5. Study the following diagram and select the correct statement about the device 'X':
1 Mark
Ans: 3. Device 'X' is a concave mirror of focal length 12cm. Explanation: From the figure, we can see that the light rays coming from infinity get reflected by the device 'X' and converge at a point at a distance 12cm from it. Therefore, the device 'X' is a concave mirror of focal length 12cm. Q6. A student obtains a sharp image of the distant window (W) of the school laboratory on the screen (S) using the given concave mirror (M) to determine its focal length. Which of the following distances should he measure to get the focal length of the mirror?
1 Mark
Ans: 2. MS.
1 2
1 2
2 1 2
Explanation: To get the focal length of the mirror, the student should measure the distance between mirror and screen because when the object is at infinity, the image is formed at focus i.e. between screen and mirror. So, the distance between screen and mirror should be measured. Q7. A student is using a convex lens of focal length 10 cm to study the image formation by a convex lens for the various positions of the object. In one of his observations, he may observe that when the object is placed at a distance of 20 cm from the lens, its image is formed at (select the correct option):
1 Mark
Ans: 3. 20cm on the other side of the lens and is of the same size, real and inverted. Explanation: 20cm on the other side of the lens and is of the same size, real and inverted. Given, focal length of the image, f = 10cm. Thus, the object is placed at 2F (2 × 10 = 20cm). Hence, the image is also formed at 2F. The image will be of same size as that of the object and is real and inverted.
Q8. Beams of light are incident through the holes A and B and emerge out of box through the holes C and D respectively as shown in the Figure. Which of the following could be inside the box?
1 Mark
Ans: 1. A rectangular glass slab. Explanation: In this case, incident rays fall perpendicularly on the point of incidence. A rectangular glass slab would refract and then re-refract it. Q9. A convex mirror of focal length f forms an image of the size of the object. The distance of the object from the mirror is:
1 Mark
Ans: 3. Explanation: Will use the formula, HERE,
f = +f ; u = –u. (since mirror is convex). So, using those, equation (1) becomes,
(f + u) = nf u = nf – f u = (n - 1) f. Q10. A perfecting reflecting mirror has an area of 1cm. Light energy is allowed to fall on it for an hour at the rate of 10cm. The force that acts on the mirror is:
1 Mark
1 nth n+1n f (n + 1)f (n − 1)f n - 1n f (n − 1)f
m = (^) (f-u)f... (1)
m = + (^1) n;
( (^1) n) = (f+u)f
2
Its image would be formed at 2F. So, the screen needs to be moved towards the lens in order to get a sharp image. Its approximate focal length is 10cm (less than image distance in earlier case). Q16. A man sits in an optician's chair looking into plane mirror which is 2m away from him and views the image of a chart which faces the mirror and is 50cm behind his head. How far away from his eyes does the chart appear to be?
3 Marks
Ans: Distance between the man and the mirror = 2cm. Distance between man and chart = 50cm. = 0.5m. Distance between chart and mirror = 0.5m. + 2m. = 2.5m. Distance between mirror and the image of the chart = 2.5m. Distance between man and the image of chart = Distance between man and the mirror + Distance between mirror and the image of the chart = 2m. + 2.5m. = 4.5m. Q17. A 2.0cm tall object is place perpendicular to the principal axis of a concave lens of focal length 15cm. At what distance from the lens, should the object be placed so that it forms an image 10cm from the lens? Also find the nature and the size of image formed.
3 Marks
Ans: For the object, h = 2cm, f = 10cm, u = -15cm From lens formula,
As v is positive, the image is real. The other aspects about the nature canbe determined from the value of magnification.
Hence, the height of the image is 4cm. This suggests that the image is enlarged. The negative sign of the magnification suggests that the image is inverted. Hence, the image is real, inverted and enlarged. OR Q17. A dentist’s mirror has a radius of curvature of 3cm. How far must it be placed from a small dental cavity to give a virtual image of the cavity that is magnified five times? Ans: R = -3cm (concave mirror) m = (virtual image)
and
We have
The mirror should be placed 1.2cm away from the dental cavity.
Q18. 1. Define focal length of a spherical lens.
5 Marks
(^1) v − (^1) u = (^1) f ∴ (^1) v = (^1) f +^1 u (^1) v = 101 + (^) −15 (^1) = 101 − 151 ∴ (^1) v = 3−2 30 = 301 ∴ v = 30cm
m = (^) uv = h
′ h ∴ (^) −15^30 = h
′ 2 ∴ h′^ = −
f = R 2 = 32 = 1.5cm
m = 5 = − vu ⇒ v = −5u (^1) v + (^1) u = (^1) f ⇒ (^) (5u)^1 + (^) u^1 = (−1.5)^1 ⇒ (^) 5u^4 = −1.5^1 ⇒ u = − 4×1.5 5 = −1.2cm
Ans: 1. Optical center of the lens is defined as the point which lies on the principal axis through the rays of light passes without any deflection.
Therefore u = -20cm Height of image can be caliculated by using the formula:
Therefore, The ray diagram is as follows:
Q18. One-half of a convex lens is covered with a black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations. Ans: The convex lens will form complete image of an object, even if its one half is covered with black paper It can be understood by the following two cases. Case I:
When the upper half of the lens is covered. In this case, a ray of light coming from the object will be refracted by the lower half of the lens. These rays meet at the other side of the lens to form the image of the given object, as shown in the above figure. Case II:
When the lower half of the lens is covered. In this case, a ray of light coming from the object is refracted by the upper half of the lens. These rays meet at the other side of the lens to form the image of the given object, as shown in the above figure. Q19. List the sign conventions that are followed in case of refraction of light through spherical lenses. Draw a diagram and apply these conventions in determining the nature and focal length of a spherical lens which forms three times magnified real image of an object placed 16cm from the lens.
5 Marks
Ans: Sign Convention for Lenses
(^1) f = (^1) v − (^1) u
−20^1 = −^101 − u^1 (^1) u = − 101 + − 201 (^1) u = − 201
h h (^21) = vu
h 2 = vuh 1 = −10cm−20cm × 4 = 2cm
Ans: 1. (b) No
The bending of light as it passed from one transparent medium into another is called refraction. Place a pencil in an inclined position in a glass trough and fill three fourth of the trough with water.
Sunil wants to see the micro organisms present in soil. He knows that he needs a microscope to see those tiny things. A microscope is an instrument used to see a small object to look bigger which helps us in a study of many tiny little species. Well, refraction also plays a huge role in the microscope.
4 Marks
n = cv v = nc
n = (^) vc
Abin wanted to see the stars of the night sky. He knows that he needs a telescope to see those distant stars. There are two types of telescopes, reflecting telescopes which are made of mirrors and refracting telescope which are made of lenses. So he decided to take a refracting telescope. There are two lenses, the larger lense gathers and bends the light, while the smaller lens magnifies the image.
4 Marks
Ans: 1. (b) Convex lens