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A collection of questions and answers related to the texas journeyman electrician exam. It covers various topics including resistance calculations, voltage drop, load calculations, conductor sizing, conduit fill, box sizing, grounding, motor circuits, overcurrent protection, and more. A valuable resource for individuals preparing for the texas journeyman electrician exam.
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Resistance with 2 resistors - - - correct answer ✅(R1+R2)/(R1xR2) Resistance with more than 2 resistors - - - correct answer ✅1/{(1/r1)+(1/r2)+(1/r3)} voltage drop single phase - - - correct answer ✅(2 x conductor length x I x kRating)/cmils voltage drop 3 phase - - - correct answer ✅(1.732 x conductor length x I x kRating)/cmils K rating of copper - - - correct answer ✅12. K rating of aluminum - - - correct answer ✅21.
Standard method of residential load calculation - - - correct answer ✅[(Total load - 3,000va) x 35%] + 3,000va + range load
Optional method of residential laid calculation - - - correct answer ✅[(Total load - 10,000va) x 40%] + 10,000va Farm Load Calculation - - - correct answer ✅Largest = 100% Second Largest = 75% Third Largest = 65% Remaining = 50% Branch circuits required - - - correct answer ✅(Total lighting load / 120v) / 15amps Residential feeder service conductor rating - - - correct answer ✅83% of service rating Article 310.15(B)(7); pg
Box Sizing - - - correct answer ✅Straight = raceway size x 8 + width of additional raceways Turn = Raceway size x 6 + width of additional raceways Volume allowance per conductor - - - correct answer ✅314.16(B); pg Metal box volume - - - correct answer ✅314.16(A); pg RV service loads - - - correct answer ✅50amp = 12,000va 30amp = 3,600va 20amp = 2,400va Tent sites = 600va Grounding electrode conductor - - - correct answer ✅250.
Sizing bonding jumper (load side) - - - correct answer ✅250. Sizing bonding jumper (supply side) - - - correct answer ✅250.102(C)(1) Equipment Grounding Conductor - - - correct answer ✅250. Motor branch circuit conductors - - - correct answer ✅FLC x 125% —> 310.15(B)(16) Motor overcurrent protection (of branch circuit) - - - correct answer ✅FLC x %430.52—>240. Motor overload protection - - - correct answer ✅NP-FLC x %430.32(A)(1)—> 240.6(A) Either 115% or 125%
Over current protection for small conductors - - - correct answer ✅240.4; pg Minimum cover requirements - - - correct answer ✅300.5; pg Conductor applications and insulation ratings - - - correct answer ✅310.104(A); pg Branch circuit rating of appliance - - - correct answer ✅125% or marked rating Over current protection of xfmr 1,000V or less - - - correct answer ✅125% of FLC 450.4(A) Maximum cord and plug connected load to receptacle - - - correct answer ✅Table 210.21(B)(2); pg
Over current protection of fixture wire - - - correct answer ✅240.5(B)(1); pg Minimum wire bending space at terminals - - - correct answer ✅312.6(B); pg Overload protection of motor compressor - - - correct answer ✅Separate overload relay - Not more than 140% of rated load Inverse time circuit breaker - 125% of rated load Hazardous Locations - - - correct answer ✅Article 500; pg CMIl thickness - - - correct answer ✅Table 8 Conductor Properties pg Service/Feeder Amp Rating - - - correct answer ✅Annex D; pg
