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Prof. T.E. Coan
version: 24 Nov ‘
Introduction
In a previous laboratory experiment on diffraction, you should have noticed that
the light from the mercury discharge tube was composed of only three colors, or three
distinct wavelengths of light. Indeed, each element of the periodic table emits its own
characteristic wavelengths of light. The collection of the different distinct wavelengths
emitted by an atom is called the emission spectrum of the atom. Spectra composed from
white light but with distinct wavelengths absorbed or removed are called absorption
spectra. Each element’s unique emission spectra can be thought of as a kind of
“fingerprint” for the element. The element helium was first discovered in this manner
through the spectroscopic analysis of light from the Sun and was only later discovered in
natural gas deposits on Earth.
But why are distinct wavelengths observed? And why are they different for
particular elements? There is nothing distinct about the light from an incandescent
source. In an empirical study of the spectrum of hydrogen, it was discovered that the
precise frequencies and wavelengths of the light produced could be described by an
equation involving a constant and an integer. This equation was then expanded to
describe the entire spectrum of hydrogen, including the ultra-violet and the infrared
spectral lines. This equation is called the Rydberg equation :
l
= R (- ),
where R is the Rydberg constant, and n 1
and n 2
are integers. That such a simple formula
describes the emission spectrum of hydrogen is nothing short of amazing. You don’t need
to know the speed of the electron or the proton, and you do not need to know how rapidly
the atom is moving. All you need to know are the constant R and two integers. The
presence of integers in this equation created a real problem for physicists until the
development of the quantum theory of the atom by Neils Bohr. Bohr's theory suggested
that the electron orbiting the nucleus could only have certain quantized angular momenta.
Ignoring the precise technical meaning of this quantity, the implication of it is that the
electron can orbit only at discrete radii and speeds around the nucleus and subsequently
can only possess certain discrete energies. The discrete radii can be labeled by integers
and the integers are the ones found in the Rydberg equation. The integer n 1 is the
quantum number of the initial state or energy level, and n 2 is the quantum number of
the final state.
Transitions of an electron from one orbit to another of smaller size produce a
burst of light. It is this light which you eventually see with your own eye. Since the
energy of an electron in a given orbit is discrete, this implies that the energy of the photon
emitted during the electron transition is also discrete. This is why we see discrete colors
from the gas in the discharge tube and not a continuous rainbow spectrum. In a future lab,
we shall see that the allowed orbit sizes and energies of an electron depend on the number
of protons in the nucleus. It is because of this that each element has its own characteristic
emission spectrum.
In this experiment, we will be measuring the various wavelengths of the spectral
lines of hydrogen, correlating them with their proper quantum numbers, and
experimentally determining the Rydberg constant.
Procedure
Set up the same apparatus as was used for measuring the mercury spectrum,
except use a mercury discharge lamp rather than hydrogen one. You will notice four
lines in the so-called Balmer series. (The Balmer series is just the Rydberg equation when
n
2
.) These are as follows:
Red 656.28 nm
Blue-Green 486.13 nm
Blue 434.05 nm
Violet 410.17 nm
Measure the wavelengths of these four spectral lines for yourself using the method from
the mercury lab, recording their color and wavelength. You only need to measure the
wavelength for the first order diffraction of each spectral line. Note that for today’s
grating, d = (1/7500) cm = 1333 nm.
Analysis
The integer numbers in the Rydberg equation label the orbit of the electron. For
emissions in the visible range, the final state ( n 2
) is level 2. Substituting this into the
Rydberg equation gives us the equation for the so-called Balmer series of spectral lines.
= R (- ) n = 3, 4, 5 ...
where the quantum number n is equal to 3, 4, 5... with each larger integer corresponding
to a more energetic transition and a shorter wavelength for the emitted light. You will
have to associate which value of n goes with each particular spectral line. The observed
emission lines should be in order (red=3, blue-green = 4, etc...) but a certain line may be
faint and hard to detect. In addition, since R is a constant, your choices for the integers
should yield values of R close to one another.
Substitute the proper measured wavelength and the quantum number to get
experimental values for the Rydberg constant. Take caution to get the unit right for R.
Prof. T.E. Coan
Name ____________________________________ Section:_________
Abstract
Data
Color N 2 x x y θ λ
Calculations (Use back if necessary. Show units!)
Calculations
Calculate the Rydberg constant from each of the wavelengths.
Wavelength λ
initial state n Rydberg constant R
ave