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This is the test examples for the Engineering dynamics course, Exams of Dynamics

Southern Union State Community CollegeDynamics

This is the test examples for the Engineering dynamics course. I hope this helps anyone who needs extra practice.

Typology: Exams

2021/2022

Uploaded on 03/15/2022

isaiah-prather
isaiah-prather 🇺🇸

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Name ____________________________________
ENGR 2350 – DYNAMICS
Fall 2021
Test 1
1. (25 points) The hockey puck is launched at an angle of = 35 degrees from horizontal.
With what velocity, vo, should the hockey player launch the puck so that it just makes it
inside the net at C? Also determine the speed of the puck at C.
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Name ____________________________________ ENGR 2350 – DYNAMICS Fall 2021 Test 1

  1. (25 points) The hockey puck is launched at an angle of D = 35 degrees from horizontal. With what velocity, vo, should the hockey player launch the puck so that it just makes it inside the net at C? Also determine the speed of the puck at C.
  1. (25 points) Initially, the motorcycle shown has a speed of 40 m/s at point A. Its speed is then decreased at a rate of - 0.005s (m/s^2 ) where s is in meters measured from A. Determine the magnitude of its acceleration when it reaches B. Also, at what position, s, will the velocity reach zero?
  1. (25 points) Car A is traveling with a speed of 38 ft/s and is increasing its speed at a rate of 3.2 ft/s^2. Car B is traveling with a speed of 24 ft/s and is decreasing its speed at a rate of 2.1 ft/s^2. Calculate: a) The velocity of B with respect to A. b) The acceleration of B with respect to A. [Write your answers as vectors]

Formulas 𝑠 = 𝑠 𝑣 = 𝑑𝑠 𝑑𝑡 𝑎 = 𝑑𝑣 𝑑𝑡 = 𝑑 2 𝑠 𝑑𝑡 2 = 𝑣𝑑𝑣 𝑑𝑠 𝑣𝑓 = 𝑣𝑖 + 𝑎𝑡 𝑣𝑓^2 = 𝑣𝑖^2 + 2𝑎(𝑠𝑓 − 𝑠𝑖 ) 𝑠𝑓 = 𝑠𝑖 + 𝑣𝑖 𝑡 + 𝑎𝑡 2 2 𝒓 = 𝑥𝒊 + 𝑦𝒋 𝒗 = 𝑥̇𝒊 + 𝑦̇𝒋 = 𝑣𝒆 (^) 𝒕 𝒂 = 𝑥̈𝒊 + 𝑦̈𝒋 = 𝑣̇𝒆 (^) 𝒕 + 𝑣 2 𝜌 𝒆 (^) 𝒏 𝑔 = 9. 𝑚 𝑠 2 = 32. 𝑓𝑡 𝑠 2 ∫ 𝑑𝑠 = ∫ 𝑣𝑑𝑡 ∫ 𝑑𝑣 = ∫ 𝑎𝑑𝑡 ∫ 𝑣𝑑𝑣 = ∫ 𝑎𝑑𝑠 𝑎 = 𝑎 𝑠 = 𝑠 𝒗 = 𝑣𝒆 (^) 𝒕 = 𝑠̇𝒆 (^) 𝒕 = 𝜌𝛽̇𝒆 (^) 𝒕 𝒂 = 𝑣̇𝒆 (^) 𝒕 + 𝑣 2 𝜌 𝒆 (^) 𝒏 𝑎𝑡 = 𝑣̇ = 𝑠̈ = 𝑣𝑑𝑣 𝑑𝑠 𝑎𝑛 = 𝑣 2 𝜌 = 𝜌𝛽̇ 2 = 𝑣𝛽̇ 𝒓𝐴 = 𝒓 (^) 𝐵 + 𝒓𝐴/𝐵 𝒗𝐴 = 𝒗 (^) 𝐵 + 𝒗𝐴/𝐵 𝒂𝐴 = 𝒂 (^) 𝐵 + 𝒂𝐴/𝐵