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Problems: supplemental problems (8A, etc.) and from Onouye Chapters 9 & 10
Notes: Problems marked with a * have been altered with respect to the problem stated in the text.
Multiframe4D or other methods may be used for V & M diagrams and maximums when the
method is not specified.
*
Partial answer to check with: Sreq’d
26.4 in.3, Areq’d
9.8 in.2, and ∆ > 0.273 in.
*
Partial answers to check with:
Sreq’d
221.1 in.3, Areq’d
91.4 in2. First trial self weight
23 lb/ft and probably won’t
work. Some that do have S > 230 in.3 and
(LL)
0.3-0.4 in., and
(LL+DL)
0.5-0.6 in.
*
Partial answers to check with:
(CD = 1.33) F’c = 1080 psi, Pa = 76.5 k
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(20%)
(35%)
(20%)
supporting a floor is to be a glue-lam member.
most economical member to use assuming
a self weight of 10 lb/ft, normal load duration (CD = 1), tabulated stresses of
Fb = 2000 psi and Fv = 250 psi, E = 1.7 x 106 psi. Calculated and locate the
maximum deflection due only to the 400 lb/ft for the member found.
(timber strength design and deflection)
* = 32 lb/ft3
*allowed (LL+DL) = L/240
(timber beam design)
Assume a 7-day live load (construction) duration.
= 18.5
(timber column analysis)
Assume the critical
load duration is for one-day live load (wind).
economical
^
*Use superpositioning with the Beam Diagrams and Formulas
to get support reactions and to construct the V & M diagrams.
