Traditional Problems - Calculus - Exam, Exams of Calculus

These are the notes of Exam of Calculus which includes Traditional Problems, Symmetric Matrix, Property, Conditions, Constants, Matrix, Positive, Anti Symmetric etc. Key important points are: Traditional Problems, Symmetric Matrix, Property, Conditions, Constants, Matrix, Positive, Anti Symmetric, Real Matrix, Helix

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2012/2013

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Math 260 Exam 2 Jerry L. Kazdan
March 13, 2012 12:00 1:20
Directions This exam has two parts. Part A has 6 short answer questions (7 points each, so 42
points) whilePart B has 4 traditional problems (15 points each, so 60 points). Total: 102 points.
Neatness counts.
Closed book, no calculators, computers, ipods, cell phomes, etc but you may use one 300 ×500 card
with notes on both sides.
Part A: six short answer questions (7 points each, so 42 points).
1. Find a 3 ×3 symmetric matrix Awith the property that
hX, AXi=x2
1+ 6x1x2x1x3+ 2x2x3+ 3x2
2
for all X= (x1, x2, x3)R3.
2. Under what conditions on the constants a,b,c, and dis the following matrix Apositive
definite?
A:=
a0 0 0
0b0 0
0 0 c0
0 0 0 d
3. Let Bbe an anti-symmetric n×nreal matrix, so B=B. Show that hV, BV i= 0 for all
VRn.
4. Find the arc length of the segment of the helix X(t) := (cos 3t, 14t, sin 3t), for 0 tπ.
5. Find some function u(x, y) that satisfies 2u
∂x∂y = 4 cos(x+ 2y)2xy .
6. Let v(s) be a smooth function of the real variable sand let u(x, t) := v(x+ 3t) . Show that u
satisfies the homogeneous partial differential equation ut3ux= 0 .
[Part B is on the next page]
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Math 260 Exam 2 Jerry L. Kazdan

March 13, 2012 12:00 – 1:

Directions This exam has two parts. Part A has 6 short answer questions (7 points each, so 42 points) whilePart B has 4 traditional problems (15 points each, so 60 points). Total: 102 points. Neatness counts.

Closed book, no calculators, computers, ipods, cell phomes, etc – but you may use one 3′′^ × 5 ′′^ card with notes on both sides.

Part A: six short answer questions (7 points each, so 42 points).

  1. Find a 3 × 3 symmetric matrix A with the property that

〈X, AX〉 = −x^21 + 6x 1 x 2 − x 1 x 3 + 2x 2 x 3 + 3x^22

for all X = (x 1 , x 2 , x 3 ) ∈ R^3.

  1. Under what conditions on the constants a, b, c, and d is the following matrix A positive definite?

A :=

a 0 0 0 0 b 0 0 0 0 c 0 0 0 0 d

  1. Let B be an anti-symmetric n × n real matrix, so B∗^ = −B. Show that 〈V, BV 〉 = 0 for all V ∈ Rn^.
  2. Find the arc length of the segment of the helix X(t) := (cos 3t, 1 − 4 t, sin 3t), for 0 ≤ t ≤ π.
  3. Find some function u(x, y) that satisfies

∂^2 u ∂x∂y = 4 cos(x + 2y) − 2 xy.

  1. Let v(s) be a smooth function of the real variable s and let u(x, t) := v(x + 3t). Show that u satisfies the homogeneous partial differential equation ut − 3 ux = 0.

[Part B is on the next page]

Part B: four traditional problems (15 points each, so 60 points).

B–1. In an experiment, at time t you measure the value of a quantity R and obtain:

t -1 0 1 2 R -1 1 1 -

Based on other information, you believe the data should fit a curve of the form R = a+bt^2. a) Write the (over-determined) system of linear equations you would ideally like to solve for the unknown coefficients a and b. b) Use the method of least squares to find the normal equations for the coefficients a and b. c) Solve the normal equations to find the coefficients a and b.

B–2. Find and classify all the critical points of f (x, y, z) := x^3 − 3 x + y^2 + z^2.

B–3. For a certain rod of length π , the temperature u(x, t) at the point x at time t satisfies the heat equation ut = uxx. Find all solutions of the special form

u(x, t) = w(x)T (t) for 0 ≤ x ≤ π

that satisfy the boundary conditions u(0, t) = 0 and u(π, t) = 0 for all t ≥ 0.

B–4. Say the equation f (X) := f (x, y, z) = 0 implicitly defines a smooth surface in R^3 (an example is the sphere x^2 + y^2 + z^2 − 4 = 0). Let P ∈ R^3 be a point not on this surface. Assume Q is a point on the surface that is closest to P. Show that the vector from P to Q is orthogonal to the tangent plane to the surface at Q. [Suggestion: Let X(t) be a smooth curve in the surface with X(0) = Q. Then Q is the point on the curve that is closest to P .]