Transfer Function-Electrical Circuit Analysis-Lecture Slides, Slides of Electrical Circuit Analysis

This lecture is part of lecture series on Electrical Circuit Analysis course. It was delivered by Prof. Mursleen Sayed at Bengal Engineering and Science University. It includes: Transfer, Function, State, Sinusoidal, Response, Poles, Phase, Angle, Magnitude, Frequency

Typology: Slides

2011/2012

Uploaded on 07/23/2012

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Mid-II - Announcements
Course: Chapters 12 & 13
Paper: 4 questions (2 from each chapter)
Difficulty Level: Tough
Formula Sheet(s) will be provided attached to question papers.
Books/Notes NOT ALLOWED.
Marking: No marks for matching formulas to questions. Concise and
clear-cut solution is required.
Obviously partial attempts will get partial marks but that partial attempt
should point towards a correct solution.
Myth Busted: Writing something will get some marks!
Mistakes: Stupid mistakes (like I = Z/V) are heavily punished. Calculation
mistakes are taken lightly as they can be done by the most genius!
An unfinished attempt can get maximum marks. A finished attempt may
get lesser marks due to some mistakes.
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Download Transfer Function-Electrical Circuit Analysis-Lecture Slides and more Slides Electrical Circuit Analysis in PDF only on Docsity!

Mid-II - Announcements

Course

: Chapters 12 & 13

Paper

: 4 questions (2 from each chapter)

Difficulty Level

: Tough

Formula Sheet(s

) will be provided attached to question papers.

Books/Notes NOT ALLOWED

.

Marking

: No marks for matching formulas to questions. Concise and

clear-cut solution is required.

Obviously

partial attempts

will get partial marks but that partial attempt

should point towards a correct solution.

Myth Busted:

Writing something will get some marks!

Mistakes

: Stupid mistakes (like I = Z/V) are heavily punished. Calculation

mistakes are taken lightly as they can be done by the most genius!

An unfinished attempt can get

maximum marks

. A finished attempt may

get lesser marks due to some mistakes.

Transfer function and the Steady-State Sinusoidal response 

Transfer function is used to relate the steady-stateresponse to the excitation source

x(t) = ACos(

t +

x(t) = ACos

tCos

  • ASin

tSin

X(s) =(ACos

)s/(s

2

2

) - (ASin

/(s

2

2

=A(sCos

Sin

)/(s

2

2

Y(s) = H(s)A(sCos

Sin

)/(s

2

2

Y(s) = K

1

/(s-j

) + K

1

/(s+j

) + terms generated by

poles of H(s)

Transfer function and the Steady-State Sinusoidal response  

y(t) = A|H(j

)|Cos[

t +

]

The terms generated by poles of H(s) have been ignored

Amplitude of the response equals the amplitude of thesource ‘A’ times the magnitude of the transfer functionH(j

)

Phase angle of the response is equal to the sum of phaseangles of the source and transfer function

Transfer function is evaluated at source frequency

)

( j

j

j

1

e )

j (

H

A^2

Ae

e ) j ( H K

 

Example 

v

g

Steady Stateexpression for v

o

 

Frequency is 5000rad/s

6

2

x

s

s

s (

s (

H

6

6

x

j (

x

j (

j (

H

t

Cos

0

Impulse function in circuitanalysis 

Impulse functions occur in circuits 

switching operation

circuit is excited by an impulsive source

Laplace Transform used to predict 

The impulsive currents and voltages due toswitching

Response of a circuit to an impulsive source

Switching Operation 

C

1

is charged to v

o

C

2

is not charged

At t = 0 i(t)? 

C

e

is series combination

of C

1

& C

2

sC /

1 (

sC /

1 (

R

s /

V

I

2

O^1

RC

s

R

V

I

e

O

Switching Operation 

Area under i vs. t curve represents the total chargetransferred to C

2

(Q=IT)

 

Total charge transferred to C

2

is independent of R

As R

0

i

V

O

C

e

(t)

When R = 0 a finite amount of charge is transferred to C

2

instantaneously

e

O

0

RC / t

O

C V ) t ( d e R

V

q

e

Switching Operation 

Contradiction 

when R is absent and switch is closed, voltageacross C

2

is not V

O

but V

2

= C

1

V

O

/(C

1

+C

2

Using Laplace transform

i = Ce

V

O

(t)

O

e

2

1

O

2

1

2

1

O

V

C

C

C

V

C

C

sC /

1 (

sC /

1 (

s /

V

I

Switching Operation  

vo

contains an impulse term as second term

is an improper rational function

 

s

) 5. 7 s (

s ( s

) 5. 7 s (

V

O

s

s 60

s

s

s 60

V

O

) t ( u ) e

t ( δ

v

t 5

O

Switching Operation 

At t = 0 when the switchis opened

) t ( u ) e 2 4 ( i

t 5 

s

4 s

s

s

4 s

s

6 ) 5 s ( s

s 5

s /

I

Impulsive Sources 

Impulse function occur in 

Circuit Sources

Circuit Responses

Impulsive source driving a circuit 

Imparts energy to the circuit instantaneously

The natural response of the circuit determines theoutput of the circuit

Analogy to striking a bell

Impulsive Source 

An impulsive source V

O

(t) applied to a series

connection of a resistor and inductor

There is no voltage drop across R and the impulsivevoltage appears across L

Current through circuit is

i(

) = V

o

/L A

Energy stored in inductor is ½LI

2

= ½(V

o

2

/L) J

Current decays to zero according to the naturalresponse of the circuit

t 0

O

dx )

x ( δ

V

1 L

i

) t ( u e L V i

) R / L /( t

O

Multiple Impulses 

An external signal impulsesource is appliedsimultaneously with aninternally generated impulsesignal

A 50

(t) source is

connected in series with the100 V source produces animpulse signal at t = 0

Switch is opened at t = 0 togenerate an internallygenerated impulse signal

δ

Multiple Impulses 

At t < 0 

i

1

= 10 A, i

2

= 0 A

    

s

s

I

s

4 s

s

s

4 s

s

s ( s

) t ( u ) e

i

t 5 

s 60

s

s ( s

) 5. 7 s (

s

) 5. 7 s (

I

s 2

V

O

t (

u )

e

t ( δ

v

t 5

o

δ