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Material Type: Notes; Class: Geodesy 1; Subject: Surveying Engineering; University: Ferris State University; Term: Unknown 1989;
Typology: Study notes
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b z⋅ a 2 b 2
a r⋅
z :=Z z =4487560.
r r =4517803.
Designating x' by r and z' by z
Solution:
Given Quantities:
ep 2 :=0.00673949677548 f :=0.
a := 6378137 b :=6356752.3141 e 2 :=0.
Constants for GRS 80: a and b are the semi-major and semi-minor axes of the ellipsoid respectively, e 2 and ep 2 are the first and second eccentricities squared respectively, f is the flattening
r2d
π
dms ang( ) degree ←floor ang( ) rem ←( ang −degree) 60⋅ mins ←floor rem( ) rem1 ←( rem −mins) secs ←rem1 60.0⋅
degree mins 100
secs 10000
radians ang( ) d ←dd ang( )
d
π
dd ang( ) degree ←floor ang( ) := mins ←( ang −degree) 100.0⋅ minutes ←floor mins( ) seconds ←( mins −minutes) 100.0⋅
degree
minutes
seconds
Some useful angle functions
Cartesian to Geodetic Coordinate Transformation
Borkowski Method Page 2 of 2
The height above the ellipsoid is:
1 t 2
2 b⋅ ⋅t
The latitude of the point is:
t G t =0. 2 F^ −v G⋅ 2 G⋅ −E
2
v v =0.
3 D − Q
3 := − D +Q
3 Q 2 := +
2 F 2
b z⋅ a 2 b 2
a r⋅