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This assignment solution was submitted to Amar Sharma for Finite Element Method course at Aligarh Muslim University. It includes: Transformation, Matrix, Local, Degree, Freedom, Global, Planar, Frame, Element
Typology: Exercises
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The transformation matrix between local degrees of freedom and global degree of for the planer frame element shown in the figure below is given by
ox ox oz oz
ox ox oz oz
l m l m
l m l m
Where
lox cos
mox sin
Using this generate the transformation matrix for the three elements shown in the figure below;
Putting values of
lox , mox , loz and moz we get the matrix in the form as given below;
cos sin 0 0 0 0 sin cos 0 0 0 0 0 0 1 0 0 0 0 0 0 cos sin 0 0 0 0 sin cos 0 0 0 0 0 0 1
Now applying this transformation matrix for each of the element one by one.
For Element # 3;
For the third element we have θ = 900 and the matrix becomes