Transformer Losses & Efficiency, Slides of Electric Machines

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Typology: Slides

2013/2014

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Electrical Machines
Electrical Machines
LSEGG216A
9080V
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe
pff
pf12
pf13
pf14
pf15
pf16
pf17
pf18
pf19
pf1a
pf1b
pf1c
pf1d
pf1e
pf1f
pf20
pf21
pf22
pf23
pf24
pf25
pf26
pf27
pf28
pf29
pf2a
pf2b
pf2c
pf2d
pf2e
pf2f
pf30
pf31
pf32

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Electrical MachinesElectrical Machines

LSEGG216A 9080V

TransformerTransformer

Losses & Efficiency Losses & Efficiency

Week 3 Week 3

ObjectiveObjectivess

  1. Calculate the all day efficiency of a transformer
  2. Describe the relationship between transformer cooling and rating
  3. Describe the methods of cooling
  4. List the properties of transformer oil
  5. Describe the tests conducted on transformer oil

Transformer RatingsTransformer Ratings

Transformers are rated to supply a given output in

Volt Amps

or

VA

at a specified frequency and terminal voltage.

Transformer RatingsTransformer Ratings

They are NOT rated in Watts
The load power factor is unknown

ProblemProblem

V

1

V
V

2

= 230 V

S = 2 kVA Power output at unity PF? P = 2 kVA x 1 P = 2 kW Power = S x PF

Power SPF P  20 , 000  1. 0

V

2

V = 200 V

1

V

S = 20 kVA P = 20 kW (a) Power output at unity power factor

VxPF S I  200x1. 20, I 

V

2

V = 200 V

1

V

S = 20 kVA I = 100 A (c) Full-load secondary current at unity power factor

VxPF S I  200x0. 10, I 

V

2

V = 200 V

1

V

S = 20 kVA I = 62.5 A (d) Secondary current when transformer supplies 10 kW at 0.8 power factor

EfficiencyEfficiency

100 Input Power Output Power η%   Efficiency is normally expressed as a percentage

TransformerTransformer

Efficiency Efficiency

Power In Power Out Overcome Iron Losses Overcome Copper Losses Some Power is used to:

Power  SPF P  100  0.

V

1

= 230 V V

2

= 32 V

S = 20 kVA η = 90% PF = 0. (a) Power output of transformer P = 85 W

In Out η  η Out In 

V

1

= 230 V V

2

= 32 V

S = 20 kVA η = 90% PF = 0. (b) Power input P = 94.4 W

85 W In 