Transforms and boundary value problem tutorial, Exercises of Differential Equations and Transforms

Transforms and boundary value problem exercise question of SRM

Typology: Exercises

2019/2020

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SRM Institute of Science and Technology
Kattankulathur
DEPARTMENT OF MEATHEMATICS
18MAB201T- TRANSFORMS AND
BOUNDARY VALUE PROBLEMS
UNIT - I Partial Differential Equations
Tutorial Sheet - 2
Sl. No.
Questions
Answer
Part - A
1
Find the singular integral of the PDE
2 2
= + +
z px qy p q
2 2
4
=
z y x
2
Find the complete integral of the PDE + =
3
2
2
4
2 3
= +
+ +
x a
z ax x
ay c
3
Solve
2 log
= +
yp xy q
2
= + + +
ay
e
z x ax c
a
4
Find the complete integral of
sin sin
+ = +
p q x y
cos cos
= +
z ax x y ay c
5
Solve
tan tan tan
+ =
p x q y z
sin sin
, 0
sin sin
φ =
x y
y z
Part - B
6
Solve
(3 4 ) (4 2 ) 2 3
+ =
z y p x z q y x
(
)
2 2 2
,2 3 4 0
φ + + + + =
x y z x y z
7
Solve
2 2 2
( ) ( )
+ =
x yz p y zx q z xy
, 0
φ + + =
x y xy yz zx
y z
8
Solve
(2 ) ( ) 2 0
+ + + + =
z y p x z q x y
(
)
2 2 2
, 2 0
φ + + + =
x y z z y x
9
Solve
( ) ( )
+ + + = +
y z p z x q x y
2
,( )( ) 0
φ + + =
x y x y z x y
y z
10
Solve
2 2 2
( ) ( ) ( )
+ =
x y z p y z x q z x y
1 1 1
, 0
φ + + =
xyz
x y z

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SRM Institute of Science and Technology

Kattankulathur

DEPARTMENT OF MEATHEMATICS

18MAB201T- TRANSFORMS AND

BOUNDARY VALUE PROBLEMS

UNIT - I Partial Differential Equations

Tutorial Sheet - 2

Sl. No. Questions Answer

Part - A

Find the singular integral of the PDE

2 2

z = px + qy + p −q

2 2

4 z = y −x

2 Find the complete integral of the PDE p + q = x

2 3

2

x a

z ax x

ay c

3 Solve^ yp^ =^2 xy^ +logq^

2

= + + +

ay

e

z x ax c

a

4 Find the complete integral of^ p^ +^ q^ =^ sin^ x^ +siny^ z = ax − cos x − cosy − ay +c

5 Solve^ p^ tan^ x^ +^ q^ tan^ y^ =tanz^

sin sin

sin sin

φ =  

x y

y z

Part - B

6 Solve^ (3^ z^ −^ 4 )y p^ +^ (4^ x^ −^ 2 )z q^ =^2 y^ −^3 x^ ( )

2 2 2

φ x + y + z ,2 x + 3 y + 4 z = 0

7 Solve

2 2 2

( x − yz p) + ( y − zx q) = z −xy ,^0

φ + + =  

x y

xy yz zx

y z

Solve (2 z − y p) + ( x + z q) + 2 x + y = 0

2 2 2

φ x + y + z , z + 2 y − x = 0

Solve ( y + z p) + ( z + x q) = x +y

2

, ( )( ) 0

 − 

φ + + − =  

−  

x y

x y z x y

y z

10 Solve^

2 2 2

x ( y − z p) + y ( z − x q) = z ( x −y )

φ + + =  

xyz

x y z