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see it and get the ability to solve arctan arccos and arcsin questions
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Quiz 10 - Math 1022 Name:
Directions: Complete these problems on this paper or separate paper and show all work. Afterwards,
take a picture of your solutions and convert the pictures into a single .pdf file. You can use an app such
as Adobescan, camscanner, or iphone notes to do this easily. Go to Canvas → Assignments and find this
assignment and upload your .pdf file there and submit it.
We have
5 π
4
is outside the range of arctan, which is (−π/ 2 , π/2). However, we know
tan
5 π
4
= 1 = tan
π
4
Since π 4 is in the range of arctan, we have that
arctan(tan(5π/4)) = π/ 4.
Set θ = arctan(2/3). Then θ lies in a right triangle with opposite 2 and adjacent 3, thus hypotenuse equal to
sin(arctan(2/3)) = sin(θ) =
Set θ = arcsin(x/4). Then θ is the interior angle of a right triangle with opposite x, hypotenuse 4, and adjacent
16 − x^2. Thus
tan(arcsin(x/4)) = tan(θ) =
x √ 16 − x^2
Set θ = arccos(x). Then θ is the interior angle of a right triangle with adjacent x, hypotenuse 1, and opposite
1 − x^2. We have
cos(2 arccos(x)) = cos(2θ) = cos 2 (θ) − sin 2 (θ) =
x^2
1
1 − x^2
1
= 2x 2 − 1.