Math 20C Lecture Examples: Triple Integrals, Study notes of Mathematics

Lecture examples on triple integrals from math 20c. It includes five examples with detailed answers, covering topics such as finding the volume of a region, expressing integrals as iterated integrals, and evaluating iterated integrals. Students of calculus and related fields may find these examples useful for understanding triple integrals.

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Pre 2010

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(9/7/08)
Math 20C. Lecture Examples.
Section 15.3. Triple integrals
Example 1 What is the geometric significance of ZZZV
1dx dy dz?
Answer: ZZZV
1dx dy dz = [Volume of V]
Example 2 Express ZZZV
4xyz dx dy dz as an iterated integral of the form,
ZZR(Zz=h(x,y )
z=g(x,y)
f(x, y, z)dz)dx dy
where Vis the box defined by 0 x3,0y2,0z1.
Answer: ZZZV
4xyz dx dy dz =ZZRZz=1
z=0
4xyz dz dy dx with R: 0 x3,0y2 in Figure A2.
x3
y
2
R
Figure A2
Example 3 Evaluate the integral ZZZV
4xyz dx dy dz =ZZRZz=1
z=0
4xyz dz dy dx from
Example 2, where Ris the rectangle in Figure A2.
Answer: Figure A3 ZZZV
4xyz dx dy dz = 18
x3
y
2
x
y= 2
R
Figure A3
Lecture notes t o accompany Section 15.3 of Calculus , Early Transcendentals by Rogawski.
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(9/7/08)

Math 20C. Lecture Examples.

Section 15.3. Triple integrals†

Example 1 What is the geometric significance of

V

1 dx dy dz?

Answer:

V

1 dx dy dz = [Volume of V ]

Example 2 Express

V

4 xyz dx dy dz as an iterated integral of the form,

R

z=h(x,y)

z=g(x,y)

f (x, y, z) dz

dx dy

where V is the box defined by 0 ≤ x ≤ 3 , 0 ≤ y ≤ 2 , 0 ≤ z ≤ 1.

Answer:

V

4 xyz dx dy dz =

R

∫ z=

z=

4 xyz dz dy dx with R: 0 ≤ x ≤ 3 , 0 ≤ y ≤ 2 in Figure A2.

3 x

y

2

R

Figure A

Example 3 Evaluate the integral

V

4 xyz dx dy dz =

R

∫ z=

z=

4 xyz dz dy dx from

Example 2, where R is the rectangle in Figure A2.

Answer: Figure A3 •

V

4 xyz dx dy dz = 18

3 x

y

2

x

y = 2

R

Figure A

†Lecture notes to accompany Section 15.3 of Calculus, Early Transcendentals by Rogawski.

Math 20C. Lecture Examples. (9/7/08) Section 15.3, p. 2

Example 4 The solid V in xyz-space with distances measured in meters is bounded by z = 0, z = y, y = x^2 , and y = 1. Its density at (x, y, z) is ρ(x, y, z) = 8yz kilograms per cubic meter. (a) Express the mass of V as an iterated integral. (b) Evaluate the integral.

Answer: (a) Figure A4 • [Mass] =

V

ρ(x, y, z) dx dy dz =

R

∫ z=y

z=

8 yz dx dy dz

=

∫ x=

z=− 1

∫ y=

y=x^2

∫ z=y

z=

8 yz dz dy dx (b) [Total charge] = 169 kilograms

− 1 1 x

y

x

y = 1

R (^) y = x^2

Figure A

Example 5 What is the average value of g(x, y, z) = xey^ sin z on the cube V : 0 ≤ x ≤ 2 , 0 ≤ y ≤ 2 , 0 ≤ z ≤ 2? Answer: [Average value] = 14 (e^2 − 1)[1 − cos(2)]