Truss(Method of Section)-Basic Mecanical Engineering-Lecture Slides, Slides of Mechanical Engineering

Prof. Dasmaya Sidhu delivered this lecture at National Institute of Industrial Engineering for Basic Mechanical Engineering course. It includes: Simple, Truss, Joints, Wooden, Strut, Forces, Compression, Tension, Planar, Rigid

Typology: Slides

2011/2012

Uploaded on 07/31/2012

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A Truss is a structure composed of slender members (two-force members) joined
together at their end points.
Members are either under tension or compression.
Joints are usually formed by bolting or welding the members to a common plate,
called a gusset plate, or simply passing a large bolt through each member.
Simple Truss
2
Joint-Welded
(Gusset Plate)
Member
(Wooden Strut)
Joint-Welded
(Gusset Plate)
Member
(Wooden Strut)
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A Truss is a structure composed of slender members (two-force members) joinedtogether at their end points. Members are either under tension or compression. Joints are usually formed by bolting or welding the members to a common plate,called a gusset plate, or simply passing a large bolt through each member.

Simple Truss

2

Joint-Welded

(Gusset Plate)

Member

(Wooden Strut)

Joint-Welded

(Gusset Plate)

Member

(Wooden Strut)

Loading of the Truss

The roof load is transmitted to the truss at the joints by means of a series

3

truss at the joints by means of a series of purlins.

Loads on a truss are applied at the joints

only

Simple Planar Truss

When all members of a truss lie in a single plane, that truss is planar.

A plane truss is rigid if it does not change shape when subjected to a

general system of forces at it’s joints. The simplest stable or rigid form of a truss is a triangle, which is thebasic truss element

C

D

5

A

B

C

E

The basic truss ABC can be extended by adding

new members BD

and CD to the existing joints B and C and connecting them to form anew joint D.

Truss Connections and Supports

When welded or riveted connections are used to join the truss members It is usually assume that the connection is a pin joint if the centerlines of the membersare concurrent at the joint as in Fig

6

For large trusses, a roller, rocker, or somekind

of

slip

joint

is

used

at

one

of

the

supports

to

provide

for

expansion

and

contraction due to temperature changes andfor deformation from applied loads

• Typically used to find forces in all or several of the

members

• Each joint is a particle • Particle equilibrium in 2D:

F

F

The Method of Joints

8

• For each joint, we have 2 equations, therefore, we

can solve for 2 unknowns

• Must start process at a joint with only 2 unknown

forces

x

y

F

F

  • Find a joint with only two unknown forces
    • First, may need to draw an FBD of the entire truss

and find support reactions

Draw FBD of selected joint

The Method of Joints

9

Draw FBD of selected joint

  • Draw each force along the direction of the member
    • Draw in tension (away from joint)
      • Find angle of force from truss geometry– Resolve angled forces into x, y components

B

C

F

1

In this structure there are 5 joints each having afree body diagram as follows

The Method of Joints

11

A

B

C

D

E

F

2

F

3

A

y

D

y

D

x

FBD

∑∑∑∑ ∑∑∑∑ ∑∑∑∑

====

==== ====

0

M

0

F

0

F

y x

For example, in this structure There are 5 jointseach having a free body diagram as follows

Joint A

The Method of Joints

0

F

0

F

x y

==== ====

∑∑∑∑ ∑∑∑∑

12

B

F

1

F

BE

F

BC

F

BA

F

AE

F

AB

A

A

Joint A

Joint B

0

F

y

====

∑∑∑∑

500 N

Determine the support reactions in the joints ofthe following truss and forces in each member ofthe truss

Example 6.

14

A

y

A

x

C

y

FBD

∑∑∑∑ ∑∑∑∑ ∑∑∑∑

====

=

=

====

0

M

0

F

0

F

x y

sin

F
F

o

BC

x

∑∑∑∑

500 N

F

BC

F

BA

Example 6.

15

N
F

sin

F

BC

BC

N
F

cos

F
F
F

BA

o

BC

BA

y

∑∑∑∑

A

y

A

x

C

y

F

BC

A

X

A

y

F

BA

F

CA

Example 6.

17

N
A
F
A
F

x

CA

x

x

∑∑∑∑

N
A
F
A
F

y

BA

y

y

∑∑∑∑

Problem 6.

A truss used to support a balcony is subjected to the loading as shown in figure. Approximate each joint as a pin and find out the force in each member of the truss State whether the members are in tension or in compression. P

1

= 600N

P

2

= 400N

18

A

P

1

F

AB

sin

F
P
F

o

y

∑∑∑∑

Problem 6.

Joint A

20

F

AD

45

o

F

AD

Tension

N
F

cos

F
F
F

AB

0

AD

AB

x

∑∑∑∑

force

e

compressiv

N
F

sin

F
P

AD

o

AD

1

B

P

2

F

AB

F

BC

F
F
F

BC

AB

x

∑∑∑∑

Problem 6.

Joint B

F

BD

=

-400 N

F

AD

= - 848.9 N

21

F

BD

N
F
F
F

BC

BC

AB

n

Compressio

N
F
F
P
F

BD

BD

2

y

∑∑∑∑