Discrete Mathematics Problems and Solutions, Exercises of Mathematics

Solutions to selected problems from the discrete mathematics textbook, specifically problems 1.5.15, 1.5.28, 1.5.38. The problems involve logical statements and their negations, and students of computer science are assumed to be the subject of the statements.

Typology: Exercises

2019/2020

Uploaded on 05/20/2020

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Discrete Mathematics
1.5.15
(a)xP(x), x:a computer science student in this class, P(x):x needs a
course in discrete mathematics.
(c)xyP(x,y), x:a student in this class, y:a computer science course,
P(x,y):x has taken y.
1.5.28
(a)This statement is true because we can let y be a function of x, and
y=x^2. So for every x there exists a number y satisfying the statement.
(b)This statement is false because when x<0, there isn’t any number
whose square is negative.
(h)We can solve these equation and find that there isn’t any solution
(x,y), so this statement is false.
1.5.38
(a)¬(xP(x))x¬P(x), x:a student in this class, P(x):x likes mathematics.
Negation: There exists a student in this class who doesn’t like
mathematics.
(b)¬(xP(x))x¬P(x), x: a student in this class, P(x):x has never seen a
computer.
Negation: Every student in this class has seen a computer.
(c)¬(xyP(x,y))x¬(yP(x,y))xy¬P(x,y), x: a student in this class,
y:a mathematics course offered at this school, P(x,y):x has taken y.
Negation: For every student in this class there exists a mathematics
course offered at this school which he or she hasn’t taken.
(d)¬(xyzP(x,y,z))x¬(yzP(x,y,z))xy¬(zP(x,y,z))xyz¬P
(x,y,z), x: a student in this class, y: a building on campus, z: a
room,P(x,y,z):x has been in y’z
Negation: For every student in this class there exists a building on
campus, and he or she hasn’t been in any room of it.

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Discrete Mathematics 1.5. (a)∀xP(x), x:a computer science student in this class, P(x):x needs a course in discrete mathematics. (c)∀x∃yP(x,y), x:a student in this class, y:a computer science course, P(x,y):x has taken y. 1.5. (a)This statement is true because we can let y be a function of x, and y=x^2. So for every x there exists a number y satisfying the statement. (b)This statement is false because when x<0, there isn’t any number whose square is negative. (h)We can solve these equation and find that there isn’t any solution (x,y), so this statement is false. 1.5. (a)¬(∀xP(x))≡∃x¬P(x), x:a student in this class, P(x):x likes mathematics. Negation: There exists a student in this class who doesn’t like mathematics. (b)¬(∃xP(x))≡∀x¬P(x), x: a student in this class, P(x):x has never seen a computer. Negation: Every student in this class has seen a computer. (c)¬(∃x∀yP(x,y))≡∀x¬(∀yP(x,y))≡∀x∃y¬P(x,y), x: a student in this class, y:a mathematics course offered at this school, P(x,y):x has taken y. Negation: For every student in this class there exists a mathematics course offered at this school which he or she hasn’t taken. (d)¬(∃x∀y∃zP(x,y,z))≡∀x¬(∀y∃zP(x,y,z))≡∀x∃y¬(∃zP(x,y,z))≡∀x∃y∀z¬P (x,y,z), x: a student in this class, y: a building on campus, z: a room,P(x,y,z):x has been in y’z Negation: For every student in this class there exists a building on campus, and he or she hasn’t been in any room of it.