Math 241 Final Exam Answers, 1998, Exams of Calculus

The answers to the math 241 final exam held in 1998. It includes solutions to various mathematical problems covering topics such as vectors, trigonometry, calculus, and quadratic equations.

Typology: Exams

Pre 2010

Uploaded on 09/02/2009

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Answers to Math 241 Final, 1998
Part I:
(1) (a) hโˆ’9,6,โˆ’2i
(b) 11
(c) x= 11 โˆ’9t
y= 3 + 6t
z= 8 โˆ’2t
(2) 3ฯ€/4
(3) โˆš29/2
(4) (a) (2, ฯ€/2,2ฯ€/3)
(b) (โˆ’3,0,0)
(5) xexy
(6) (a) 1/12
(b) ฯ€/4
(c) 2ฯ€
(7) a saddle point
(8) 6xโˆ’8yโˆ’z= 1
(9) Abs. Max. is 10
Abs. Min. is 6
(10) 0
Part II:
(1) (a) Check that 3(2 โˆ’t)โˆ’t+ 4(2 + t) = 14 for all t.
(b) 5x+ 7yโˆ’2z= 6
(2) Abs. Max. is 11/โˆš10
Abs. Min. is โˆ’11/โˆš10
(3) 19ฯ€/15
(4) 4/3
(5) ฯ€/2

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Answers to Math 241 Final, 1998

Part I:

(1) (a) ใ€ˆโˆ’ 9 , 6 , โˆ’ 2 ใ€‰ (b) 11 (c) x = 11 โˆ’ 9 t y = 3 + 6t z = 8 โˆ’ 2 t

(2) 3 ฯ€/ 4

(4) (a) (2, ฯ€/ 2 , 2 ฯ€/3) (b) (โˆ’ 3 , 0 , 0)

(5) xexy

(6) (a) 1 / 12 (b) ฯ€/ 4 (c) 2 ฯ€

(7) a saddle point

(8) 6 x โˆ’ 8 y โˆ’ z = 1

(9) Abs. Max. is 10 Abs. Min. is 6

(10) 0

Part II:

(1) (a) Check that 3(2 โˆ’ t) โˆ’ t + 4(2 + t) = 14 for all t. (b) 5 x + 7y โˆ’ 2 z = 6

(2) Abs. Max. is 11 /

Abs. Min. is โˆ’ 11 /

(3) 19 ฯ€/ 15

(4) 4 / 3

(5) ฯ€/ 2