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The concepts of weak and weak* topologies in the context of real vector spaces and their duals. It covers the definitions, properties, and relationships between these topologies, including tychonoff's product topology, the topology of pointwise convergence, and the banach-alaoglu theorem. The document also includes proofs for various propositions and lemmas.
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Definition 5.1. Let Z be a set and let (Zi, Ti)i∈I be a family of topological spaces. For each i let pi : Z → Zi be a mapping. We define the initial topology on Z (associated with the mappings pi) to be the coarsest topology on Z for which all the mappings pi are continuous. Its basic open sets are of the form (^) ⋂
i∈F
p− i 1 [Ui],
with F a finite subset of I and Ui ∈ Ti for each i. There are many important examples. For instance, given the family (Zi)i∈I as above, we may consider the product space
Z =
i∈I
Zi,
whose elements are all functions f that assign to each i ∈ I an element f (i) of Zi. (We sometimes prefer to use “family” notation (zi)i∈I for such things, in order to emphasize the similarity with sequences and the idea that f (i) is the “ith^ co-ordinate” of f .) If all the spaces Zi are copies of a single space Z, we write ZI^ for the product space. On the product space Z we introduce the co-ordinate mappings πi : Z → Zi; f 7 → f (i),
and define the (Tychonoff) product topology to be the initial topology with respect to the mappings πi. It is an important theorem (Tychonoff’s Theorem) that if all the spaces Zi are compact and Hausdorff, then so is Z. This theorem is presented in the C Analytic Topology course. If L is a topological space then the space of all continuous real-valued functions C (L) is a subspace of RL. The topology induced by the product topology is the topology of pointwise convergence, basis open neighbourhoods of a function f being of the form
{y ∈ C (L) : |y(ti) − x(ti)| < for i = 1, 2 ,... , n},
where n is a natural number, > 0 and t 1 ,... , tn ∈ L. Let X be a real vector space and let Y be a subspace of the algebraic dual X#. We define the topology σ(X, Y ) to be the coarsest topology on X for which all the maps g : X → R (g ∈ Y ) are continuous. Basis open sets have the form
{x′^ ∈ X : |gi(x′) − gi(x)| < for i = 1, 2 ,... , n}. In the important case where X is a normed space and Y = X∗^ we call this topology the weak topology on X. When X is a normed space, we can also introduce a topology on X∗, defined to be the coarsest topology for which all the mappings f 7 → f (x) (x ∈ X) are continuous. This is called the weak* topology on X∗. In the σ-notation, this topology is just σ(X∗, JX [X]) (or, less pedantically, σ(X∗, X). Notice that the weak topology on X is coarser than the norm topology (because all f ∈ X∗^ are norm-continuous). In Proposition 5.4 we show that the weak topology is strictly coarser than the norm topology whenever X is infinite-dimensional. Note also that the weak* topology on X∗^ is coarser (and in the non-reflexive case strictly coarser) than the weak topology σ(X∗, X∗∗).
Lemma 5.2. If X is a real vector space and Y is a subspace of X#^ then every σ(X, Y )-open neighbourhood of 0 contains a finite-codimensional subspace X 1 of X.
Proof. A basic σ(X, Y )-open neighbourhood of 0 is of the form
{x ∈ X : |gj (x)| < i for i = 1, 2 ,... , n}
where gi ∈ Y and i > 0. This set contains the finite-codimensional subspace
X 1 =
i≤n
ker gi.
Proposition 5.3. If X is a real vector space and Y is a subspace of X#^ then a linear mapping g : X → R is σ(X, Y )-continuous if and only if g ∈ Y.
Proof. If g ∈ Y then g is σ(X, Y )-continuous by definition of the topology. On the other hand, if g is linear and σ(X, Y )-continuous then there exists a σ(X, Y )-open neighbourhood U of 0 such that |g(x)| ≤ 1 for all x ∈ U. It follows that g is zero on the subspace X 1 =
i≤n ker^ gi^ of Lemma 5.2. It follows “by algebra” that^ g^ is a linear combination^
i≤n λigi^ and hence in the subspace^ Y^.^
Proposition 5.4. If X is an infinite-dimensional normed space then the weak topology on X is strictly coarser than the norm topology.
Proof. Each f ∈ X∗^ is continuous for the norm topology, and so this topology if finer than the weak topology (by the definition of σ(X, X∗) as the coarsest topology making all f ∈ X∗^ continuous. The unit sphere SX = {x ∈ X : ‖x‖ = 1} is closed in the norm topology. I shall show that SX is not closed in the weak topology whenever X is infinite-dimensional. By Lemma 5.2, every weak neighbourhood U of 0 contains a subspace X 1 of X which is of
27
28
finite codimension, and hence non-trivial. Thus U ∩ SX ⊇ X 1 ∩ X = SX 1 6 = ∅. This shows that 0 ∈ SX weak , so that SX is not weakly closed.
Theorem 5.5 (Banach–Alaoglu). If X is a normed space, then the dual unit ball BX∗ is weak*-comnpact.
Proof. A functional f ∈ BX∗^ is a (linear) mapping with the property that f (x) ∈ [−‖x‖, ‖x‖] for each x ∈ X. So we can regard BX∗^ as being a subset of the product space K =
x∈X [−‖x‖,^ ‖x‖]. [Recall that the elements of^ K^ are^ all^ functions^ f^ on^ X^ such that |f (x)| ≤ ‖x‖ for all x ∈ X.] Moreover, the topology induced on BX∗^ by the product topology on K is exactly the weak* topology on BX∗^ [in each case, we are looking at the coarsest topology that makes all the maps f 7 → f (x) continuous]. Since each [−‖x‖, ‖x‖] is a compact Hausdorff space, so too is K, by Tychonoff’s theorem. To prove our theorem it is enough, therefore, to show that BX∗^ is a closed subset of K. Now, for every x ∈ X the map f 7 → f (x) is continuous on K; so if x 1 , x 2 ∈ X and λ ∈ R the mapping qx 1 ,x 2 ,λ : K → R : f 7 → f (x 1 + λx 2 ) − f (x 1 ) − λf (x 2 )
is continuous on K. Hence the intersection (^) ⋂
x 1 ,x 2 ∈X; λ∈R
q− x 11 ,x 2 ,λ(0),
which is exactly BX∗^ , is closed in K.
Corollary 5.6. For every normed space X there exists a compact Hausdorff space K and a linear isometric embedding X → C (K).
Proof. Take K = BX∗ in the weak* topology. For each x ∈ X the function Jx : K → R; f 7 → f (x) is continuous on K (by definition of the weak* topology), and ‖Jx‖∞ = sup f ∈BX∗
|f (x)| = ‖x‖,
by a standard corollary to the Hahn–Banach theorem.
Theorem 5.7 (Non-examinable). For a normed space X, the dual ball BX∗ is weak* metrizable if and only if X is separable.
Proof. One implication (X separable =⇒ BX∗^ metrizable) has been set as a problem. The converse can be deduced from the fact that C (K) is a separable Banach space whenever K is compact and metrizable. This in turn follows from the Weierstrass–Stone Theorem (not on this course), or from a direct argument involving partitions of unity which we shall not give here.
It follows that every separable normed space embeds into C (K) for some compact metric space K. One can do even better: every separable normed space embeds isometrically into C [0, 1]. The proof of this refinement is related to the “Hahn–Mazurkiewicz” theorem of General Topology.
Proposition 5.8 (A variant of the H–B Separation Theorem). Let Y be a normed space, let C be a convex subset of the dual space Y ∗^ and let g ∈ Y ∗. If g is not in the weak*-closure of C then there exists y ∈ Y such that
g(y) > sup f ∈C
f (y).
Proof. As in other separation theorems, we may assume that 0 ∈ C. If g /∈ C w* then there exists a weak* open neighborhood U of g such that U ∩ C = ∅. Now U has the form
U = {f ∈ Y ∗^ : |f (yi) − g(yi)| < i for i = 1, 2 ,... , n} = g + V,
where V is the weak* open neighborhood of 0 given by
V = {h ∈ Y ∗^ : |h(yi)| < i for i = 1, 2 ,... , n}.
The set C˜ = C + V is open and g /∈ C˜, so (as in the HBST proved earlier) there exists η ∈ Y ∗∗^ such that
η(g) ≥ sup f ∈C+V
η(f ) > sup f ∈C
η(f ).
Since V ⊇
i≤n ker^ JY^ (yi) we have (“by algebra” as in Proposition 5.3)^ η^ ∈^ sp〈JY^ (yi) :^ i^ ≤^ n〉^ whence^ η^ =^ JY^ (y) for some y ∈ Y X.
Theorem 5.9 (Goldstine). If X is a normed space then JX [BX ] is weak*-dense in BX∗∗^.
Proof. Let X be a normed space and let g ∈ X∗∗^ \ JX [BX ]
w* ; we shall show that ‖g‖ > 1. Taking Y = X∗^ and C = JX [BX ], we deduce from Proposition 5.8 that there exists f ∈ X∗^ such that
g(f ) > sup{(JX x)(f ) : x ∈ BX } = sup{f (x) : x ∈ BX } = ‖f ‖.
This implies that ‖g‖ > 1
Theorem 5.10. A Banach space X is reflexive if and only if BX is compact in the weak topology.