Vertical Photography - Lecture Notes | SURE 340, Study notes of Engineering

Material Type: Notes; Professor: Burtch; Class: Photogrammetry; Subject: Surveying Engineering; University: Ferris State University; Term: Unknown 1989;

Typology: Study notes

Pre 2010

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VERTICAL
PHOTOGRAPHY
Photographic Scale Calculations Over Flat Terrain
________________________________________________________________________________
Given: distance on the photograph and coordinates of corresponding points on the ground
ab 3.0833in:= abmab 25.4mm
in
:= abm0.078m=
XA3910451.51m:= YA244219.02m:=
XB3910138.12m:= YB243867.07m:=
AB XBXA
()
2YBYA
()
2
+:= AB 471.256m=
The denominator of the scale is (s):
sAB
ab
:= s 6017=
The scale of the photograph is 1:6017
Computing Flying Height on a Vertical Photograph
The basic equation for finding the flying height on a vertical photograph
where the elevations of the points are not equal is
(
)
(
)
2
AB
2
AB
2YYXXAB +=
where AB is the ground distance between two points and Xi, Yi are the
ground coordinates of the two points at the end of the line. Recall that the
ground coordinates can be determined from the photo measurements using
the relationships:
y
f
hH
Yx
f
hH
X
=
=
where H is the flying height above the datum, h is the elevation of the ground
point, f is the focal length of the camera, and x, y are the photographic
coordinates of point i.
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VERTICAL

PHOTOGRAPHY

Photographic Scale Calculations Over Flat Terrain


Given: distance on the photograph and coordinates of corresponding points on the ground

ab := 3.0833in ab (^) m ab 25.4⋅ mm in

:= ab (^) m =0.078m

XA := 3910451.51m YA :=244219.02m

XB := 3910138.12m YB :=243867.07m

AB := (^) ( XB −XA)^2 +(Y (^) B −YA)^2 AB =471.256m

The denominator of the scale is (s):

s AB ab

:= (^) s = 6017

The scale of the photograph is 1:

Computing Flying Height on a Vertical Photograph

The basic equation for finding the flying height on a vertical photograph

where the elevations of the points are not equal is

AB^2 = ( XB−XA)^2 +( YB−YA)^2

where AB is the ground distance between two points and X i , Y i are the

ground coordinates of the two points at the end of the line. Recall that the

ground coordinates can be determined from the photo measurements using

the relationships:

y

f

x Y H h

f

X =H−h = −

where H is the flying height above the datum, h is the elevation of the ground

point, f is the focal length of the camera, and x, y are the photographic

coordinates of point i.

Center for Photogrammetric Training Vertical Photography

Substitute the values for X and Y into the distance equation yields

2 a

A b

B

2 a

A b

2 B y

f

H h

y

f

H h

x

f

H h

x

f

H h

AB ⎟

+⎛^ − − −

=⎛^ − − −

Rearranging,

( ) ( )

2 [(^ b a)^ (^ A a B b)]^22 [(^ b a)^ (^ A a B b)]^2

2 2 b B b a A a

2 2 b B b a A a

2

y y H h y h y

f

x x H h x h x^1

f

Hy h y Hy h y

f

Hx h x Hx h x^1

f

AB^1

Let:

( ) ( ) ( (^) A a B b) ( (^) A a B b)

b a b a

n h x h x q h y h y

m x x p y y

Then the ground distance can be represented by

( ) ( )

2 [(^22 )^2 (^ )^ (^22 )]

2 2

2 2

2

m p H 2 mn 2 pgH n q

f

pH q

f

mH n^1

f

AB^1

Moving the distance squared (AB^2 ) to the right hand side gives us the

quadratic form of the equation. Let

( ) ( ) ( )

( )( ) ( )( )

( ) ( ) (^2) 2

2 A a B b

2 (^2) A a B b 2

2 2

2

b a A a B b b a A a B b 2

2

2 b a

2 b a 2

2 2

AB

f

h x h x h y h y

AB

f

n q

c

f

2 x x h x h x 2 y y h y h y

f

2 mn 2 pq

b

f

x x y y

f

m p

a

The solution is found by solving the quadratic equation in the form of

2 a

b b 4 ac

H

− ±^2 −

Center for Photogrammetric Training Vertical Photography

AB =553.

h (^) Avg

Z A +Z B

:= h (^) Avg =293. Compute initial estimate of the flying height

H 1 AB

ab

:= ⋅f +h (^) Avg H 1 =1219.

Check the initial estimate of H:

XA

H 1 −Z A

f

:= ⋅xa YA

H 1 −Z A

f

:= ⋅y (^) a

YB

H 1 −Z B

f X := ⋅y^ b B

H 1 −Z B

f

:= ⋅xb

AB 1 := ( XB −XA)^2 +(Y (^) B −YA)^2 AB 1 =555.

Diff := AB −AB 1 Diff =−2. Adjust the flying height

H 2 AB

AB 1

:= ⋅ ( H 1 −h (^) Avg)+h (^) Avg H 1 := H 2 H 1 =1215.

Check the current estimate of H:

Calculation of flying height over variable terrain

Iterative Method

Given quantities: (^) f :=152. x 1 := 69 y 1 := − 174 xa

x 1 60

:= ⋅25.4 y (^) a

y (^1) 60

x 2 := − 28 y 2 := 19 xb

x 2 60

:= ⋅25.4 y (^) b

y (^2) 60

XA := 3910451.51 YA := 244219.02 Z A :=287.

XB := 3909949.05 YB := 243987.10 Z B :=298.

Compute photo distance and ground distance

ab := ( xb −xa)^2 +( y (^) b −y (^) a)^2 ab =91.

AB := ( XB −XA)^2 +( YB −YA)^2

Center for Photogrammetric Training Vertical Photography

X A

H 1 −Z A

f

:= ⋅xa Y (^) A

H 1 −Z A

f

:= ⋅y (^) a

Y B

H 1 −Z B

f X := ⋅y^ b B

H 1 −Z B

f

:= ⋅xb

AB 1 := (^) ( X (^) B − X (^) A)^2 + ( Y (^) B − Y (^) A)^2 AB 1 =553.

Diff := AB −AB 1 Diff =− 0

RCB