Volkswagen Emission Scandal, Lecture notes of Designs and Groups

Volkswagen Emissions. Scandal. DESIGN OF EXPERIMENTS (DOE) ... Overview of Volkswagen Company. • Problems Identified and COPQ. • Root Cause Analysis.

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2021/2022

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Volkswagen Emissions
Scandal
DESIGN O F E X P E R I M E N T S (DOE)
FINAL PRESENTATION
VOLKSWAGEN EMISSIONS SCANDAL - GROUP 3
Group 3:
Aditya Krishnan
Anurag Kumar Ashok Kumar
Nithin Katragadda
Saahith Kuraparthi
Sindhu Kundur
Xiaqing Li
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Volkswagen Emissions

Scandal

DESIGN OF EXPERIMENTS (DOE)

FINAL PRESENTATION

VOLKSWAGEN EMISSIONS SCANDAL - GROUP 3

Group 3: Aditya Krishnan Anurag Kumar Ashok Kumar Nithin Katragadda Saahith Kuraparthi Sindhu Kundur Xiaqing Li

Agenda

  • Problem Statement
  • Overview of Volkswagen Company
  • Problems Identified and COPQ
  • Root Cause Analysis
  • Design of Experiment

o 8 Steps of DOE using T-table

o DOE using Minitab

  • Conclusion

Overview of Volkswagen Company

  • Headquartered in Wolfsburg, Germany
  • Until January 2016, the largest manufacturer of cars in the world
  • Makers of some of the most iconic cars such as VW Beetle and Minibus.
  • Owns brands such as o Audi o Bugatti o Porsche o Lamborghini o Ducati o Bentley

Scandal

  • VW diesel cars had “defeat device” software installed in them o Could detect when cars were being tested and accordingly improve emission results
  • EPA discovered emission discrepancies in Sept 2015 o 500K cars in the US o 11 Million cars worldwide
  • “Defeat Device” found in Porsche and Audi models as well
  • Stocks plummet

Cost of Poor Quality

  • Non Conformities o Emission standards not met by diesel engines o Nitrogen Oxide(NO) emissions 40 times higher than the permissible limit
  • Inefficient Processes o Lack of transparency and accountability o Lack of proper quality checks
  • Lost Opportunities o Heavy costs incurred due to car recalls o Stock prices crashed o Brand value jeopardized

Items of Concern from COPQ

  • Not met standards set by regulatory body
  • No quality assessments by 3rd party vendors
  • Lack of transparency in the organization
  • Company chose to build “Defeat Device”

rather than tackle the emission problem

  • Huge losses for company and stakeholders
  • Company needs a lot of time and budget to

manage the recalls and correcting the

emission problem

Root Cause of Technical Issues - Pareto Chart

Design of Experiment

  • Based on Pareto chart o 43% cause of emission from Engine o If Engine is corrected, emissions will reduce significantly
  • Further analyzing the Engine, the factors that affect emissions o Engine Type  4 cylinder engine vs 6 cylinder engine o Weight  Small car (1 Ton) vs Large car (3.5 Tonnes) o Average Speeds  City Traffic (30 MPH) vs Highway Traffic (60 MPH)
  • The cars will undergo on-road emission testing to avoid discrepancies from in-house testing

Steps for Analysis of Effects in a DOE

I. Calculate the effects

II. Calculate the Pareto chart

III. Calculate the Standard Deviation of the experiment, Se

IV. Calculate the standard deviation of the Effects, Seff

V. Determine the T-statistic

VI. Calculate the decision limits and determine the significant effects

VII. Graph significant effects

VIII. Model the significant effects

Step 1 - Calculate the effects

  • Effects of Individual factors o Engine Type: 0.

o Weight: 2.

o Avg Speed: 1.

  • Effects of two level interactions o Engine and Weight: -0. o Engine and Avg Speed: -0.

o Weight and Avg Speed: 0.

  • Effects of three level interaction o Engine, Weight and Avg Speed: 0.

Step 3 - Calculate the Standard Deviation - Se

  • Average variance of the Base 8 Runs

o 𝑆𝑏^2 = 0.^21 +^4.^23 +^3.^65 +^1.^31 + 8 0.^19 +^0.^15 +^0.^17 +^0.^14 = 1. 26

  • Degree of Freedom for design

o 𝑑𝑓𝑏 = # 𝑜𝑓 𝑟𝑢𝑛𝑠 ∗ #𝑜𝑓 𝑟𝑒𝑝𝑙𝑖𝑐𝑎𝑡𝑒𝑠 − 1

= 8 ∗ 2 − 1 = 8

  • Calculate 𝑆𝑒^2

o 𝑆𝑒^2 = 𝑆𝑏^2 = 1.

o 𝑆𝑒 = 1.25 = 1.

Step 4 - Calculate the Standard Deviation of the Effects

  • 𝑆𝑒𝑓𝑓 = 𝑆𝑒 ∗

4 𝑁

  • 1.12 ∗

4 8

  • 1.12 ∗ 0.707 = 0.

Step 6 - Calculate decision limits and significant effects

𝐷𝑒𝑐𝑖𝑠𝑖𝑜𝑛 𝐿𝑖𝑚𝑖𝑡 = ±𝑡 ∗ 𝑆𝑒𝑓𝑓 = ±1.859 ∗ 0.792 = ±1.

Step 7 - Graph significant effects