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This is solution to one of problems in Numerical Analysis. This is matlab code. Its helpful to students of Computer Science, Electrical and Mechanical Engineering. This code also help to understand algorithm and logic behind the problem. This code includes: Wave, Equation, Finite, Difference, Algorithm, Approximate, Boundary, Conditions, Initial, Constant, Endpoint, Integers
Typology: Exercises
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% To approximate the solution to the wave equation: % subject to the boundary conditions % u(0,t) = u(l,t) = 0, 0 < t < T = max t % and the initial conditions % u(x,0) = F(x) and Du(x,0)/Dt = G(x), 0 <= x <= l: % % INPUT: endpoint l; maximum time T; constant ALPHA; integers m, N. % % OUTPUT: approximations W(I,J) to u(x(I),t(J)) for each I = 0, ..., m % and J=0,...,N. syms('OK', 'FX', 'FT', 'ALPHA', 'M', 'N', 'M1', 'M2', 'N1', 'N2'); syms('H', 'K', 'V', 'J', 'W', 'I', 'FLAG', 'NAME', 'OUP', 'X', 's', 'x'); TRUE = 1; FALSE = 0; fprintf(1,'This is the Finite-Difference Method for the Wave Equation.\n'); fprintf(1,'Input the functions F(X) and G(X) in terms of x, \n'); fprintf(1,'on separate lines. \n'); fprintf(1,'For example: sin(pi*x)\n'); fprintf(1,' 0 \n'); s = input(' ','s'); F = inline(s,'x'); s = input(' ','s'); G = inline(s,'x'); fprintf(1,'The lefthand endpoint on the X-axis is 0.\n'); OK = FALSE; while OK == FALSE fprintf(1,'Input the righthand endpoint on the X-axis.\n'); FX = input(' '); if FX <= 0 fprintf(1,'Must be a positive number.\n'); else OK = TRUE; end; end; OK = FALSE; while OK == FALSE fprintf(1,'Input the maximum value of the time variable T.\n'); FT = input(' '); if FT <= 0 fprintf(1,'Must be a positive number.\n'); else OK = TRUE; end; end; fprintf(1,'Input the constant alpha.\n'); ALPHA = input(' '); OK = FALSE; while OK == FALSE fprintf(1,'Input integer m = number of intervals on X-axis\n'); fprintf(1,'and N = number of time intervals - on separate lines.\n');
fprintf(1,'Note that m must be 3 or larger.\n'); M = input(' '); N = input(' '); if M <= 2 | N <= 0 fprintf(1,'Numbers are not within correct range.\n'); else OK = TRUE; end; end; if OK == TRUE W = zeros(M+1,N+1); M1 = M+1; M2 = M-1; N1 = N+1; N2 = N-1; % STEP 1 % V is used for lambda H = FX/M; K = FT/N; V = ALPHAK/H; % STEP 2 for J = 2 : N W(1,J) = 0; W(M1,J) = 0; end; % STEP 3 W(1,1) = F(0); W(M1,1) = F(FX); % STEP 4 for I = 2 : M W(I,1) = F(H(I-1)); W(I,2) = (1-V^2)F(H(I-1))+V^2(F(IH)+F(H(I-2)))/2+KG(H(I-1)); end; % STEP 5 for J = 2 : N for I = 2 : M W(I,J+1) = 2(1-V^2)W(I,J)+V^2(W(I+1,J)+W(I-1,J))-W(I,J-1); end; end; % STEP 6 fprintf(1,'Choice of output method:\n'); fprintf(1,'1. Output to screen\n'); fprintf(1,'2. Output to text file\n'); fprintf(1,'Please enter 1 or 2.\n'); FLAG = input(' '); if FLAG == 2 fprintf(1,'Input the file name in the form - drive:\name.ext\n'); fprintf(1,'for example: A:\OUTPUT.DTA\n'); NAME = input(' ','s'); OUP = fopen(NAME,'wt'); else OUP = 1; end; fprintf(OUP, 'FINITE DIFFERENCE METHOD FOR THE WAVE EQUATION\n\n');