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Wave @plics ° ° = JAZ +A + 2A,Ag Cop (Ap) wasultamt armpitude, fr T= T,+T, +232, Cs (49) . Sesubbomt Intensity Ei rm (Ae Cuest te caest —» phate diff = Qu Phase = axgumnent e& Cob of Sin eG ae SN=A cate on. Ax) ) ) ) ) ) ) ) ) FEO ) ) Sasme FRLeGULEN CY . ) ) phase. GN Bt EG AA OR EEE CEP REE SRS SG TE pare ra Rauation of Wone 1 = A, Cos “(Re-wt+¢)) Equation of wave @ = Ag, Co (Kx -wt+2) The Sources which Aave w Constamt phase differance Fete ebsewing- unferterunce dry dive Lgnt Waves , Jt JS necess— au that the dwe sources Should be cehexent: A Susface connecting peirtts Araning- escitdation dn Same A wave fecemit Js | te the dinection of prepagaten ok Ware. . €-dinection ok atl ~ Wave. prepagation pet x Seusece, ea bs ‘ Wane, rent ph Wave Sena OE GSA 5 AN alia eta Se AE Daa ea he ee ee er en ee Ca Coa | Ast. Ao = 2M5G I ‘ Gy At = oS a dy = MA D Su = MAD (Gr PNS) y= 0, AD , 2aDd ko | eee od Cemithod = 45t Vast IM! > ede of maxima, a = (m+ Sa ~ (yr orn) ye AD bab ad eed Vist Vand “AD BAD ack ad Yyst =) and +e Side ie oe (+1) > @rdesu Ef minimum Perr -ve Side, [nm] — edesu ef rruniroun ) wD i} ae 1 ac oO | | 0 SDE SO ESI a On OS eel 3G deal GOS eek pore NT ge th Satay SR eee an ee ee RUSS , mie aes | = Quadra YDSE dhe Skit Sppasxation ds OA2mm & Scewary H distance, JS 1m . 3% boy inge UB ot a distomce o& 75mm | P Jaen the Cembial Quinge, Find wavelength of Light. 3p = 45mm aoa = t5mm I ore 3 | , 2 I | A= 15 y%2 = 5x10 1mm 30 lot A= 500nm I QuadDistamce blur dive amtemnas ka wadie- Statien JS 400m. The station epexotes at 1500 KHz. At distamces cmust I Qpactese thar, Yoom , dn whicy dixections wil you weceve best. signal (sttemgth) 7 V= 1500 KHz ADW= MA A= 3x108 dsine = MA 5 x 10° Sine = m ( B00 =o Nee Goo cs = 200m -t @ = Si Oe. Siru ( a) Sins == 1., “$b 0, ioe +4 0 Total & dixeations 2 hse WITH WHITE eT oe Hea b/us dhe Certiad maximum amd the 1St maximum Sed, & VIBGYOR wWikl be ebseurd with centual amaximum being. ushite. Howevess agtew gsing a Strle fuxtheu , thee will be a Comfus paktewn of colors & dk We go even Pusctheu » | | | aes a SE ee ee Wi 3 oly «a oe pa See rea eee ee eee ene ees a Que Whee wilh Tbe Ya S& Lat centre,’ ay eles I ; Con ( B= 4 ; Ap = 2% = Qn, a0 2 * 3 A | & Oo H re 4 = AD_ = Pry I on L (Skit Sntemsity o% Ste width) H [RELATION Bho- VELOCITY OF UGHT G REFRACTIVE INDEX) ' Wher a Wane theanels ene medium te amethesu, ots feequency dees met chamge.. AY CaN aide (4 = S)> Spee ane oy ede Saal Na Speak iru medium A Omer Ge ANS os Ses oN Oy (Amedium = Cate) The equivademt path, saquized rv aisy te praeduce, the Same, ates digzeumce, A wy givery ithicRness of mmatesdab . I 1 | i | I i i i | I 1 i | I | i 1 1 i I 1 i i I 1 | | | Katte = A Lay Ln—> 1 I I I | i i i I i i i I | i 1 I I i i I i | | i | | Atma Px are AY *Te compkete, Sarme mo. f cycles dn ai , dhe ware Arane travelled a distance, geacten, tham 2. (Baits = 4 Lmediwrn) The pot Lsngtr seqiisad dirs medium 2 ite pawduce, dhe Same phose difference 0% a gvere thickness ef amedtum 2, dS cadded the M.E.P. dru medi 2. Fousrm dhe previous discussion , Wwe Cam say dhat Oras) 7 NT A aig aie al) AMARANTE EAS Ai Os hee Sa aE TE LE eters Vit p sy sake |e red Que) What with Aapper te dhe Feunge widih Jf w YDSE Setup hE TE NE ELEC oe Car OE ae ee re re ee Was dmmexsed Jr a medium & oapactive index ‘ar ? = Ame Pm = Am 2 = AD. Ad =P. A ie pattesn wit shaink by w facterv of SA’. Qua) Calcubate dhe shift un Centaal maximum Jf a Rheem f dcRness “XL & seofpactive undex *a? JS placed dry feast of one ot; the Stits. by definition of centeral max. | (S)Proprical = (S2 PP optical 6 (S\Pquemekical +ygt -d = (SeP) gpemetziical | -d Sine + (A-I)L =O (a-)é& = dsine ¥ oe i Cae) Y = (1) t.D- Qui) Caleudcte Fpinge Shift & conditions fo yeu shift. (S)Popt = Ge opt Ait, (SP gg + AE = (SP ape + Aleka” te 0 (A, Yd, - (Aen ke =dhSime ody | qe . | y= Loyang Cag eD Fetes Zoe Shift, AM,t,- ©, = Agta -Lp (A, “DE = Ap - ke | | 0 Te a ee alge ee rn ge a ae a ec ec —_¢ fo yet Ya JX D Oe OS PPPS CF ET TSS CLS Yo Ee EEO TO Loree Ie Sa a RE EP Na a PRLS RC ARN TO NUE SN eK US CAAT, Sen ee ee i, y Que) decode Ceritxal maxinusm. dsine -dsing =0 Sind Sd D | ie 4 ae TOTAL NO. oF MAXIMAS & aid Te count the se. maximas amd amninimas , we calculate, dhe max. possible Pattu diffeumce & thar use the, act what cmaxima with eccusy ot ay pobru difference of inte multiple && 6A’ 8 minima with cesaspend te edd muvipl B “Ae Que) Calculate, Leta me. g mnaximax & cmininas . Alse find pesition gf gh exude cmaximum. Ma.xirnas = 44 Minimas = 100 Aw = 49A dceso = GA GAO= Yds 8, Sine = SA Ug” exdee naxira = path difference SoH 9in es SE eT Sa ee mnt (1m tha Gs oetoece Tiel abies ae eed cna Sa sete ee a L Qu) AS U move alsng, | What Js dhe can. vate (a) Maximum (6) Minimus ©) alse ted the order oa maxima, /erminimay , | a F tane= YA x, 4A : ap % ist, pan diff. Js } ak 18t ernaxima, , pain diff. = SA cone as 6 a= tA G (b) fax®rie® = 35a +20 Iea* = 4GA + FAK 4 Wes IS ke Set LA thos 28 (c) 3nd Maxima, HP minima, (a) Find amox & omin: value of. Fete maxima , ote 1G ae = e+ AM Bare mw = ISA a Feta ominimas , oP lee = axt4 AD + AC y x = 63 y CL Ee a EE eee eee eo ere cae eS 4 (a) X+HIGA GW= SA a BP + led = oF +9A~ +6 Are Ae Ce CS dhe x-direction beginning Fasm Sa, i f % feu ustuch. Ws get Zea EC a LL el OL eee ore: Yt eae FRom MULTIPLE SLUTS weg Heme we Cam finds the pat diffeamces Aue dhe Shextest patty & all dhe dncident Mght, phasews at amy pt. amd get dhe gesuitamt Jntensity. Ads = Qe AXLz S A s | Abs = 2RAX, : aor z" fess Saw i bee (5) Que-) s, ies N Me We Oo Pa a THES. ta once Biss | 23.5 Np S¢—p —>|_p ——> SP -SaP = Ag SP - SaP = aA/3 AG #28. BA = 20 A 6 3 Ada= 2m YA . Bn A 3 % Ig = <3 Ca ee Ca Ub ee ote ee aL el eee Qua) Srv a YDSE ,untemsity due de ene Spat = 1, & due do athe. Js Ip. Find scatio of emax. de min. Untensity on Scmeara- Ip=I,+Iq + @NI, JE, Cosh Imax = (om +ARY | aad oo aa ae AT - die : Ip W+l eels coca | eee > Tp 4, L, = Ip Cot (42) mee ee 4 O < («2 Neecst =e Ab= 2m = an dy = aD ¢ 30 ) Geer pene} 4 Consideo a pein P on the Scrum as Shouse Uns the fig. SF we wamt a minima at P, then the phate Sum ef the Vaxieus says Ceming. feem dhe stit Sheuld be zene. We alse Rneur dhar dhe phases ok untewumediate points will be umifewmly distuibuted bius tne phase of dep - cmest peint amd dhe bette -mmest point. + Thus JF these Gwe phasers aw Jnteqge ne. e& cycles apoxk her cw minimum will be ebtained. A Mathematically » Fee Minium 2Ldsin@ = enw A Py oS ae = ie 2__firsointion oF OBJECTS pre | Due te di tiene ts, the image eka distamt ebject JS mot w Single paint Ury the fecal peiré plome but ut ~ Aas am am Hodis of (i 22a/g) wtheae dy us the | apextune ef the fens. ie G= b22a db | “Te get ay shaxp image, jet’ aperture, the Lams | - Shewlds be hox.ge- |. XFety sesohition,amqulass separation blur tue ebjects sheuld | be (h22Agy) Ce CG 7 2G Ce Sseen = a Met “eseeveds C,Cp Sl 22a i d em basaly, oeseyed (just) CCp > 22a CH) Cheaply nesered ie. fotu thue ebjects ie be cl amgulase Sepaxatienm Trust be atleas' Heseived, thei. (22 Jb) A poelaxisedd dS w thins Seme motesial which, alleuss dhol Component of electric Held ite pass ~ Which Js along dts axis. a Thus Jf ithe asngle of electaic Field with pelareids axis , JS 97, then the transmitted field us *E Cs’. Artensity Ob (Béectaic field )* ES PPS POE Ieee Fe ee ee ee ee See ys | | a eg a eg ra oS a ne Oe Cer re keer ee — bo F ) ) ) Ee ee ne a CoE i a ee Thus, dhe dxamsmitted intensity a ) soflected. 2 > 2 Fe. maximum, nee | Aart = (amt) AL nS u (because fo Yene ec dhem JS so SshiPted) A= Hat Cam+1) *When «& ds axge , chesd axe many \ralues ok de buingw A Ds YOORM & FOONM. Thus maximas of emamy grits wi be thsesugh, amd Se me intesLexomce wi@ be ebseswed duo te whicty interfesumce Js only Seon dns thim Hem. . 303) AM, =133 , AeF kb, A> GOonm . cas a,b = mA 2 ck = MA/ 24, 4 | | a a Rc a gc re ance Ne 
