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WGU E010 (D335) FOUNDATIONS OF PROGRAMMING (PYTHON) FINAL EXAM QUESTIONS WITH DETAILED- VERIFIED ANSWERS- ALREADY GRADED A+ || NEWEST EXAM 2025-2026 Computer Science / Information Technology This WGU E010 (D335) Foundations of Programming (Python) exam covers variables, data types, type conversion, operators (arithmetic, comparison, logical, assignment), strings (slicing, methods, formatting), lists, tuples, dictionaries, sets (mutability, operations), conditionals (if/elif/else, ternary), loops (for, while, break, continue, else), functions (definition, parameters, return, scope, lambda, recursion), file I/O (open, read, write, append, with context), exception handling (try/except/else/finally, raise), and modules (import, math, random, os, sys)
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Computer Science / Information Technology This WGU E010 (D335) Foundations of Programming (Python) exam covers variables, data types, type conversion, operators (arithmetic, comparison, logical, assignment), strings (slicing, methods, formatting), lists, tuples, dictionaries, sets (mutability, operations), conditionals (if/elif/else, ternary), loops (for, while, break, continue, else), functions (definition, parameters, return, scope, lambda, recursion), file I/O (open, read, write, append, with context), exception handling (try/except/else/finally, raise), and modules (import, math, random, os, sys). SECTION 1 – VARIABLES, DATA TYPES, AND OPERATORS (Q1–25)
A) 50.0 – the code works correctly because strings convert automatically. B) "12.5012.5012.5012.50" – the string is repeated four times instead of numeric multiplication. C) 12.50 * 4 – the expression is printed literally. D) Error – you cannot multiply a string by an integer. CORRECT ANSWER: B Rationale: Multiplying a string by an integer repeats the string. Since price is a string ("12.50"), not a float, the result is the string repeated four times. To fix, convert to float: float(price) * quantity.
Rationale: % gives remainder: 7 ÷ 3 = 2 remainder 1 → x = 1. // gives floor division: 7 // 3 = 2. Output is 1 2.
result = 8 + 2 * 3 ** 2 // 4 print(result) What is the value printed, following operator precedence? A) 11 B) 17 C) 14 D) 8 CORRECT ANSWER: B Rationale: Precedence: exponentiation (**) first: 3 ** 2 = 9. Then multiplication/division from left to right: 2 * 9 = 18, 18 // 4 = 4 (floor division). Then addition: 8 + 4 = 12. Wait, that gives 12, not 17. Let me re‑evaluate carefully: Expression: 8 + 2 * 3 ** 2 // 4 Step 1: 3 ** 2 = 9 Step 2: 2 * 9 = 18 Step 3: 18 // 4 = 4 Step 4: 8 + 4 = 12. But 12 is not among options. Did I misread? Perhaps the code has 8 + 2 * 3 ** 2 // 4 – that is 12. Option A is 11, B 17, C 14, D 8. None is 12. So there might be a typo. Let me adjust the question to avoid error.
C) D) CORRECT ANSWER: B Rationale: Division (/) always returns a float, even when both operands are integers. Here a is int, b is float, so the result is float.
A) True B) False C) Error D) None CORRECT ANSWER: A Rationale: 10 % 2 == 0 is True. 5 > 3 is True. So True and True = True. Then True or (7==8) = True or False = True.
python (not (3 > 2)) or (4 < 5) and (6 == 6) A) True B) False C) Error due to parentheses D) None CORRECT ANSWER: A Rationale: 3 > 2 is True, so not True = False. 4 < 5 is True, 6 == 6 is True, so True and True = True. Then False or True = True.
Then 15 - 8 + 3 + 1 = 11. That works. I'll use that. CORRECT ANSWER: B Rationale: Multiplication/division first: b*2=8, a//b=3. Then 15-8=7, 7+3=10, 10+1=11.
A) The program prints inf (infinity). B) The program raises a ZeroDivisionError. C) The program prints 0. D) The program returns None. CORRECT ANSWER: B Rationale: Division by zero raises a ZeroDivisionError at runtime. Python does not return infinity for integer or float division by zero; it throws an exception.
A) x=10, y=20, z is assigned None. B) x=10, y=20, z raises a ValueError because not enough values to unpack. C) x=10, y=20, z is assigned an empty tuple. D) The code runs without error, and z is undefined. CORRECT ANSWER: B Rationale: Unpacking requires the number of variables to match the number of values. Here, 3 variables but only 2 values → ValueError.
B) "1020" – string concatenation, not addition. C) 10+20 – the plus is printed literally. D) Error – cannot concatenate two strings. CORRECT ANSWER: B Rationale: The + operator on strings performs concatenation. "10" + "20" produces "1020".
Rationale: 6 > 0 and 6 % 2 == 0 → True → Yes. 5 > 0 is True but 5 % 2 == 0 is False → False → No.