RAKESH ASERY (09EC73)
EXPERIMENT NO:- {1}
Object:-
Design a microstrip rectangular patch with dielectric substrate
Ɛr=2.2 & hight h=0.1588 cm. at resonance frequency fr=10GHz.
Solution:- Given:- Microstrip rectangular patch
Ɛr=2.2 , h=0.1588cm. & fr=10GHz
(a)Width:- =˳√
(Ɛ)
where V˳=Light velocity=3x10^10cm/sec.
w = ^√
^(.) =1.1858cm.
(b)Effective permittivity:- Ɛeff = Ɛ
+(Ɛ)
(/)
Ɛeff = 2.2 + 1
2+(2.2 −1)
2(1 + 12X0.1588/1.1858) = 1.97
(c) Increment length:- ∆L = .(Ɛ.)
.
(Ɛ.)
.
∆L = ..(..)( .
..)
(..)( .
..)
∆L = 0.083cm.
(d)Actual length:- L = λ/2˗˗ 2∆L
Where λ=wavelength λ=˳
Ɛ
λ=3x10^10
10^10√. = 2.1365cm.
Now L = 2.1365/2˗˗ 2X0.083 =0.9019cm.
(e)Effective length:- Leff =L+2∆L
Leff =0.9019+2X0.083 = 1.068cm.
