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Worksheet #1: Read PDF articles 1-4 found on the course web page, and review the 12 Principles of Green Chemistry. (handout). These articles provide a good ...
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CHEM 489 Advanced Environmental Chemistry – Spring 20 20
Worksheet #1: Read PDF articles 1 - 4 found on the course web page, and review the 12 Principles of Green Chemistry (handout). These articles provide a good overview of green chemistry, are an easy read, and may be helpful in answering some of these questions. You should answer these questions on a separate sheet of paper. You can work together, but must submit your own worksheet and your own answers.
(b) Define % Yield and % Atom Economy. How do these two metrics differ? We use % yield and % atom economy as metrics to evaluate the efficiency of a chemical reaction or process. The ideal atom economy (100% atom economy) is where all reactant atoms are incorporated in the desired product. Atom economy is calculated by comparing the molecular mass (atoms) of the desired product to the sum of the molecular masses (atoms) of all reactants. A balanced chemical equation is required, as are stoichiometric multipliers for molecular mass. Atom economy takes into account how efficiently all the reactant atoms are used in a reaction. The higher the atom economy the lower the amount of waste produced. The % yield is calculated by comparing the moles (mass) of the limiting reactant to the moles (mass) of the desired product(s). % Yield does not take into account the amount of waste produced. (c) Do all reactant atoms end up in the desired product? If no, which atoms do not? Without doing a calculation, what is your preliminary assessment of the reactions Atom Economy? Yes, all reactant atoms end up in the product, so we have 100% atom economy. (d) Based on the balanced equation given above, what component(s) of this reaction is/are not considered in evaluating efficiency based on % Yield and Atom Economy? The energy used for running this reaction at 35oC, and the solvent, acetonitrile. (e) Based on your lab experience (especially CHEM 243/244 labs), what other components of this process might be relevant to a full assessment based on Molecular Design? Any additional solvents for workup, use of water for washing, etc., and drying agents are not considered. All these would contribute to the waste from this process. (f) This reaction used 5 .0 g of N-methylimidazole and 20 .0 g of 1 - chlorobutane. Loo up or calculate the molecular weight and number of moles of each. Based on the stoichiometry in the balanced equation, do you see a potential problem here? Explain. MW of N-methylimidazole = 82.10 g/mole MW of 1 - chlorobutane = 92.57 g/mole 5 .0 g of N-methylimidazole = 0. 061 mole 20 .0 g of 1 - chlorobutane = 0.2 16 mole The reaction stoichiometry is 1:1, but there is an excess of 1 - chlorobutane. The excess of 1 - chlorobutane will end up as waste unless it can be recycled and reused. ( 5 ) Compare and contrast how green chemists reduce Risk as compared to traditional “command and control”? Risk is a function of the Hazard, Exposure and Vulnerability; Risk = f(Hazard x Exposure x Vulnerability). Establishing environmental laws attempts to reduce Risk through “Command & Control,” or Treatment & Abatement; in other words trying to control the problem after the fact. Green Chemistry reduces Risk by reducing or eliminating the Hazard, so protection from Exposure is unnecessary, those most vulnerable are less affected, and Command & Control Regulations (and their inherent costs) are not necessary. ( 6 ) The 12 Principles of Green Chemistry can serve as a useful guide to the design, creation and use of chemicals and chemical technologies focused on the potential for human health and environmental benefits. For each idea or concept in the table below, identify a Primary and Secondary green chemistry principle that might apply. You do not need to justify your answers.