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Worksheet 11. MATH 10B. Tu 2/28/19. 1. Concept of Independence. • What is the probability that two people chosen at random were born during ...
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Tu 2/28/
Solution:
1
12
1 12 =^
1 12
Solution: If n > 12, by the pigeonhole principle, at least two people were born in the same month. Otherwise, P (at least two born in the same month) = 1 − P (all born in different month) = 1 − 1212 × 1112 × 1012... 12 − 12 n +1.
Solution: In other words, we want to find the minimum n such that 1 − P (all born in different month) = 1 − 1212 × 1112 × 1012... 12 − 12 n+1 > 12. When n = 4 , P (at least two born in the same month) ≈ 0 .482, and When n = 5 , P (at least two born in the same month) ≈ 0 .618. Thus, n ≥ 5.
Solution: Let A be the event that first die rolled is a 1, and B be the event that the sum of the two dice is a 7. Then,
Therefore, P (A ∩ B) = P (A)P (B).
Tu 2/28/
Solution: P (at least two of them were both born on April 1st) = 1 − P (none of them were both born on April 1st) −P (exactly one of them were both born on April 1st) = 1−(^365366 )n−
(n 1
( 3661 )(^365366 )(n−1)
- Solving the equation, we have n > 614.
Solution:
3
Solution: 1 − 0. 495
Solution: 1 − 0. 515
Solution: 0. 515 + 0. 495
Solution: P (E) =
Therefore, independent.