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WORKSHEET:SOLUTIONS AND COLLIGATIVE PROPERTIES. SET A: 1. Find the molarity of all ions in a solution that contains 0.165 moles of aluminum chloride in 820.
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Answer: [Al 3+]= 0.201 M , (Cl-] = 0.603M.
(Note: There is no reaction taking place.)
Answer: [H+]= 0.11 M, [NO3-]= 0.59M, [Ca2+]= 0.24 M.
Answer: [K +] = 0.71 M, [SO42-]= 0.24 M, [PO4 3-]= 0.074 M.
Answer: 20 g Al(OH)3 left over, [Al3+]=0.83 M, [NO3-]= 2.5M
benzene at 20. ° C is 75 mm Hg and that of toluene at 20.0 ° C is 22 mm Hg. Assume that Raoult’s law holds for each component of the solution, calculate the mole fraction of benzene in the vapor. ( molar mass of benzene= 78.0 g/mole and toluene = 92.0 g/mole.) Answer= 0.
density of the solution is 1.50 g/ml. What is the molarity of the glucose solution? ( Kf for water is
1.86 ° C.kg/mole) Answer: 4.16 mole/L
H2O is 0.512 ° C .kg/mole) Answer=: 101.9 ° C
b. Write the total-ionic and net-ionic equations for the above reaction. Total ionic: Net-ionic: c. Give the name and mass of any precipitate(s)that may have formed. Answer: 1.87 g of Co2(CO3)3 precipitate.
Calculate the molar concentration of each ion remaining in solution after the reaction is complete. Answer:concentration of potassium ions= 0.874 M, concentration of cobalt (III) ions= 0.0372 M concentration of carbonate ions= 0 M concentration of chloride ions= 0.986 M
benzene= 4.96 ° C .kg/mole) Answer: 82 g/mole
=0.512 ° C .kg/mole) Answer: 101.2 ° C
Answer: -25.5 ° C
d. Calculate the molar concentration of each ion remaining in solution after reaction is complete. Answer: Concentration of carbonate ions= 0 M Concentration of aluminum ions = 0.0252 M Concentration of nitrate ions= 0.312 M Concentration of sodium ions = 0.236 M
and density of 1.68 g/ml? KB for water is 0.512 ° C .kg/mole. ( C6H12O6 is a nonvolatile nondissociating
solute.) Answer: 3.07 mole/L
1.35 g/ml. ( C12H22O11 is a nonvolatile nondissociating solute.) The molal freezing point depression
constant of water is 1.86 ° C .kg/mole. Answer: Freezing point= -1.14 ° C
heptane is 0.522 atm , and the vapor pressure of pure octane is 0.238 atm. A solution is made of 5.32 g heptane and 8.80 g octane. Calculate the mole fraction of octane in the vapor at the above temperature. Answer: 0.
The molal freezing point depression constant for benzene is 5.12 ° C .kg/mole.) Answer: 128 g/mole; C8H4N
Answer: 4.88 x 10^4 g/mole